{"id":240478,"date":"2025-07-03T09:40:41","date_gmt":"2025-07-03T09:40:41","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=240478"},"modified":"2025-07-03T09:40:43","modified_gmt":"2025-07-03T09:40:43","slug":"draw-a-lewis-structure-for-and-indicate-the-number-of-sigma-and-pi-bonds-in-h2o","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/03\/draw-a-lewis-structure-for-and-indicate-the-number-of-sigma-and-pi-bonds-in-h2o\/","title":{"rendered":"Draw a Lewis structure for, and indicate the number of sigma and pi bonds in H2O."},"content":{"rendered":"\n<p>Draw a Lewis structure for, and indicate the number of sigma and pi bonds in H2O.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To draw the Lewis structure of water (H\u2082O) and determine the number of sigma and pi bonds, follow these steps:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Count Valence Electrons<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Hydrogen (H) has 1 valence electron, and there are 2 hydrogen atoms, so the total valence electrons for hydrogen are 2.<\/li>\n\n\n\n<li>Oxygen (O) has 6 valence electrons, so the total valence electrons for oxygen are 6.<\/li>\n\n\n\n<li>Total valence electrons = 2 (from H) + 6 (from O) = 8 valence electrons.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Arrange the Atoms<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Oxygen (O) is the central atom because it is more electronegative than hydrogen.<\/li>\n\n\n\n<li>Attach each hydrogen atom to the oxygen atom using a single bond.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Distribute Electrons<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Each single bond (O-H) consists of 2 electrons, one from oxygen and one from hydrogen.<\/li>\n\n\n\n<li>Place the remaining electrons around oxygen to satisfy the octet rule for oxygen. After bonding with hydrogen, oxygen has 4 valence electrons left, which form 2 lone pairs.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Lewis Structure of H\u2082O:<\/h3>\n\n\n\n<pre class=\"wp-block-preformatted\">cppCopyEdit<code>      H \u2014 O \u2014 H\n       | \n      (lone pair)\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Oxygen has 2 lone pairs, and each hydrogen is bonded to oxygen with a single bond.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Count the Bonds<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Sigma (\u03c3) Bonds:<\/strong> A sigma bond is formed by the head-on overlap of atomic orbitals. In H\u2082O, there are two O-H single bonds, each consisting of one sigma bond.<\/li>\n\n\n\n<li><strong>Pi (\u03c0) Bonds:<\/strong> Pi bonds are formed by the sideways overlap of p orbitals, and they are present only in double or triple bonds. Since water has no double or triple bonds, it has <strong>zero pi bonds<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Number of sigma bonds<\/strong> = 2 (one between each H and O).<\/li>\n\n\n\n<li><strong>Number of pi bonds<\/strong> = 0 (since there are no double or triple bonds in H\u2082O).<\/li>\n<\/ul>\n\n\n\n<p>This structure follows the octet rule for oxygen (8 electrons around oxygen) and satisfies the hydrogen rule (2 electrons around each hydrogen).<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-7.jpeg\" alt=\"\" class=\"wp-image-240479\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Draw a Lewis structure for, and indicate the number of sigma and pi bonds in H2O. The Correct Answer and Explanation is: To draw the Lewis structure of water (H\u2082O) and determine the number of sigma and pi bonds, follow these steps: Step 1: Count Valence Electrons Step 2: Arrange the Atoms Step 3: Distribute [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-240478","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/240478","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=240478"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/240478\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=240478"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=240478"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=240478"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}