{"id":241446,"date":"2025-07-03T18:00:24","date_gmt":"2025-07-03T18:00:24","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=241446"},"modified":"2025-07-03T18:00:28","modified_gmt":"2025-07-03T18:00:28","slug":"melissa-and-madeline-love-pepperoni-pizza-but-sometimes-they-are-disappointed-with-the-small-number-of-pepperonis-on-their-pizza","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/03\/melissa-and-madeline-love-pepperoni-pizza-but-sometimes-they-are-disappointed-with-the-small-number-of-pepperonis-on-their-pizza\/","title":{"rendered":"Melissa and Madeline love pepperoni pizza, but sometimes they are disappointed with the small number of pepperonis on their pizza"},"content":{"rendered":"\n<p>Melissa and Madeline love pepperoni pizza, but sometimes they are disappointed with the small number of pepperonis on their pizza. To investigate, they went to their favorite pizza restaurant at 10 random times during the week and ordered a large pepperoni pizza. Here are the numbers of pepperoni on each pizza: 47, 36, 25, 37, 46, 36, 49, 32, 32, 34. Using the step method, we will construct and interpret a 95% confidence interval for the true mean number of pepperonis on a large pizza at this restaurant.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To construct a 95% confidence interval for the true mean number of pepperonis on a large pizza at the restaurant, we need to follow the steps of statistical inference. Here\u2019s how you can do it using the <strong>step method<\/strong>:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Identify the sample data<\/h3>\n\n\n\n<p>The data from the 10 random pizzas are as follows:<br><strong>47, 36, 25, 37, 46, 36, 49, 32, 32, 34<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Calculate the sample mean (x\u0304)<\/h3>\n\n\n\n<p>First, we need to find the mean (average) of the sample:Sample&nbsp;Mean&nbsp;(x\u02c9)=\u2211(all&nbsp;data&nbsp;values)Number&nbsp;of&nbsp;observations=47+36+25+37+46+36+49+32+32+3410\\text{Sample Mean (x\u0304)} = \\frac{\\sum \\text{(all data values)}}{\\text{Number of observations}} = \\frac{47 + 36 + 25 + 37 + 46 + 36 + 49 + 32 + 32 + 34}{10}Sample&nbsp;Mean&nbsp;(x\u02c9)=Number&nbsp;of&nbsp;observations\u2211(all&nbsp;data&nbsp;values)\u200b=1047+36+25+37+46+36+49+32+32+34\u200bSample&nbsp;Mean&nbsp;(x\u02c9)=40410=40.4\\text{Sample Mean (x\u0304)} = \\frac{404}{10} = 40.4Sample&nbsp;Mean&nbsp;(x\u02c9)=10404\u200b=40.4<\/p>\n\n\n\n<p>So, the sample mean is <strong>40.4<\/strong> pepperonis.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Calculate the sample standard deviation (s)<\/h3>\n\n\n\n<p>Next, we calculate the sample standard deviation. The formula for the sample standard deviation is:s=\u2211(xi\u2212x\u02c9)2n\u22121s = \\sqrt{\\frac{\\sum (x_i &#8211; \\bar{x})^2}{n &#8211; 1}}s=n\u22121\u2211(xi\u200b\u2212x\u02c9)2\u200b\u200b<\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>xix_ixi\u200b is each individual data point,<\/li>\n\n\n\n<li>x\u02c9\\bar{x}x\u02c9 is the sample mean,<\/li>\n\n\n\n<li>nnn is the number of observations (which is 10).<\/li>\n<\/ul>\n\n\n\n<p>Now, let\u2019s calculate the squared differences from the mean for each data point:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>(47 &#8211; 40.4)\u00b2 = 43.56<\/li>\n\n\n\n<li>(36 &#8211; 40.4)\u00b2 = 19.36<\/li>\n\n\n\n<li>(25 &#8211; 40.4)\u00b2 = 240.16<\/li>\n\n\n\n<li>(37 &#8211; 40.4)\u00b2 = 11.56<\/li>\n\n\n\n<li>(46 &#8211; 40.4)\u00b2 = 30.56<\/li>\n\n\n\n<li>(36 &#8211; 40.4)\u00b2 = 19.36<\/li>\n\n\n\n<li>(49 &#8211; 40.4)\u00b2 = 73.96<\/li>\n\n\n\n<li>(32 &#8211; 40.4)\u00b2 = 70.56<\/li>\n\n\n\n<li>(32 &#8211; 40.4)\u00b2 = 70.56<\/li>\n\n\n\n<li>(34 &#8211; 40.4)\u00b2 = 41.16<\/li>\n<\/ul>\n\n\n\n<p>Now, sum up the squared differences:\u2211(xi\u2212x\u02c9)2=43.56+19.36+240.16+11.56+30.56+19.36+73.96+70.56+70.56+41.16=620.4\\sum (x_i &#8211; \\bar{x})^2 = 43.56 + 19.36 + 240.16 + 11.56 + 30.56 + 19.36 + 73.96 + 70.56 + 70.56 + 41.16 = 620.4\u2211(xi\u200b\u2212x\u02c9)2=43.56+19.36+240.16+11.56+30.56+19.36+73.96+70.56+70.56+41.16=620.4<\/p>\n\n\n\n<p>Now, divide by n\u22121=9n &#8211; 1 = 9n\u22121=9 (since we have 10 data points):s=620.49=68.93\u22488.3s = \\sqrt{\\frac{620.4}{9}} = \\sqrt{68.93} \\approx 8.3s=9620.4\u200b\u200b=68.93\u200b\u22488.3<\/p>\n\n\n\n<p>So, the sample standard deviation is <strong>8.3<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Find the critical value (t*)<\/h3>\n\n\n\n<p>Since we are constructing a 95% confidence interval with a sample size of 10, we use the <strong>t-distribution<\/strong> with 9 degrees of freedom (df = n &#8211; 1 = 10 &#8211; 1 = 9). For a 95% confidence interval, the critical value <strong>t<\/strong>* for 9 degrees of freedom can be found in a t-table or using a calculator. The value is approximately <strong>2.262<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 5: Calculate the margin of error (ME)<\/h3>\n\n\n\n<p>The margin of error is calculated as:ME=t\u2217\u00d7snME = t^* \\times \\frac{s}{\\sqrt{n}}ME=t\u2217\u00d7n\u200bs\u200b<\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>t\u2217=2.262t^* = 2.262t\u2217=2.262,<\/li>\n\n\n\n<li>s=8.3s = 8.3s=8.3,<\/li>\n\n\n\n<li>n=10n = 10n=10.<\/li>\n<\/ul>\n\n\n\n<p>Now, plug the values in:ME=2.262\u00d78.310=2.262\u00d72.627\u22485.94ME = 2.262 \\times \\frac{8.3}{\\sqrt{10}} = 2.262 \\times 2.627 \\approx 5.94ME=2.262\u00d710\u200b8.3\u200b=2.262\u00d72.627\u22485.94<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 6: Construct the confidence interval<\/h3>\n\n\n\n<p>Finally, the 95% confidence interval is:CI=x\u02c9\u00b1ME=40.4\u00b15.94\\text{CI} = \\bar{x} \\pm ME = 40.4 \\pm 5.94CI=x\u02c9\u00b1ME=40.4\u00b15.94<\/p>\n\n\n\n<p>So, the confidence interval is:[40.4\u22125.94,40.4+5.94]=[34.46,46.34][40.4 &#8211; 5.94, 40.4 + 5.94] = [34.46, 46.34][40.4\u22125.94,40.4+5.94]=[34.46,46.34]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 7: Interpret the result<\/h3>\n\n\n\n<p>We are 95% confident that the true mean number of pepperonis on a large pizza at this restaurant lies between <strong>34.46 and 46.34<\/strong> pepperonis.<\/p>\n\n\n\n<p>This means that if we were to repeat this process many times, approximately 95% of the calculated confidence intervals would contain the true average number of pepperonis on a large pizza at this restaurant.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-161.jpeg\" alt=\"\" class=\"wp-image-241447\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Melissa and Madeline love pepperoni pizza, but sometimes they are disappointed with the small number of pepperonis on their pizza. To investigate, they went to their favorite pizza restaurant at 10 random times during the week and ordered a large pepperoni pizza. Here are the numbers of pepperoni on each pizza: 47, 36, 25, 37, [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-241446","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/241446","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=241446"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/241446\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=241446"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=241446"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=241446"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}