{"id":241652,"date":"2025-07-03T19:26:30","date_gmt":"2025-07-03T19:26:30","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=241652"},"modified":"2025-07-03T19:26:34","modified_gmt":"2025-07-03T19:26:34","slug":"write-the-chemical-formula-of-these-coordination-compounds-formula-name-pentaaquabromomanganeseiv-bromide-x-5-2-sodium-triamminetrichlorotitanateii-pentacarbonylchlorocopperii-chloride","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/03\/write-the-chemical-formula-of-these-coordination-compounds-formula-name-pentaaquabromomanganeseiv-bromide-x-5-2-sodium-triamminetrichlorotitanateii-pentacarbonylchlorocopperii-chloride\/","title":{"rendered":"Write the chemical formula of these coordination compounds formula name pentaaquabromomanganese(IV) bromide X 5 2 sodium triamminetrichlorotitanate(II) pentacarbonylchlorocopper(II) chloride"},"content":{"rendered":"\n<p>Write the chemical formula of these coordination compounds formula name pentaaquabromomanganese(IV) bromide X 5 2 sodium triamminetrichlorotitanate(II) pentacarbonylchlorocopper(II) chloride<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let&#8217;s break down the chemical formulas for each of these coordination compounds:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>Pentaaquabromomanganese(IV) bromide<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Name analysis<\/strong>:\n<ul class=\"wp-block-list\">\n<li><strong>Pentaaquabromo<\/strong>: The central metal ion is <strong>manganese<\/strong> (Mn) with a <strong>+4<\/strong> oxidation state (Manganese(IV)). It is coordinated to five water molecules (aqua, H2O) and one bromide ion (Br\u207b).<\/li>\n\n\n\n<li><strong>Bromide<\/strong>: An additional bromide ion (Br\u207b) is present as the counterion to balance the charge.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Formula<\/strong>: The number of water molecules is 5, and there is 1 bromide ion as a ligand. Manganese(IV) will have a charge of +4. Each bromide ion has a charge of -1, and water molecules are neutral. To balance the charge, we need one more bromide ion outside the coordination sphere.\n<ul class=\"wp-block-list\">\n<li><strong>Formula<\/strong>: <strong>[Mn(H2O)5Br]Br2<\/strong><\/li>\n\n\n\n<li>The structure consists of a manganese(IV) center surrounded by five water molecules and one bromide ion in the coordination sphere, with two additional bromide ions as counterions.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>Sodium triamminetrichlorotitanate(II)<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Name analysis<\/strong>:\n<ul class=\"wp-block-list\">\n<li><strong>Sodium<\/strong>: The counterion is sodium (Na\u207a).<\/li>\n\n\n\n<li><strong>Triamminetrichlorotitanate(II)<\/strong>: The central metal ion is <strong>titanium<\/strong> (Ti) in the <strong>+2<\/strong> oxidation state (Titanium(II)), coordinated to three ammonia molecules (NH\u2083) and three chloride ions (Cl\u207b).<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Formula<\/strong>: The titanium ion has a +2 charge, while the ammonia molecules are neutral and the chloride ions each carry a -1 charge. The overall complex will need sodium counterions to balance the charge.\n<ul class=\"wp-block-list\">\n<li><strong>Formula<\/strong>: <strong>Na2[Ti(NH3)3Cl3]<\/strong><\/li>\n\n\n\n<li>The sodium ions balance the +2 charge from the titanium and the overall negative charge from the chloride ligands.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">3. <strong>Pentacarbonylchlorocopper(II) chloride<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Name analysis<\/strong>:\n<ul class=\"wp-block-list\">\n<li><strong>Pentacarbonyl<\/strong>: The central metal is <strong>copper<\/strong> (Cu) in the <strong>+2<\/strong> oxidation state, and it is coordinated to five carbonyl ligands (CO).<\/li>\n\n\n\n<li><strong>Chloride<\/strong>: There is one chloride ion (Cl\u207b) as a ligand.<\/li>\n\n\n\n<li><strong>Chloride<\/strong> (again): A chloride ion is present as a counterion to balance the charges.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Formula<\/strong>: The copper ion has a +2 charge, each carbonyl (CO) is neutral, and the chloride ligand (Cl\u207b) in the coordination sphere is also neutral. The extra chloride ion is required as a counterion to balance the charge.\n<ul class=\"wp-block-list\">\n<li><strong>Formula<\/strong>: <strong>[Cu(CO)5Cl]Cl<\/strong><\/li>\n\n\n\n<li>The structure contains five carbonyl ligands attached to copper(II), with one additional chloride ion as the counterion.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Summary of Formulas:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Pentaaquabromomanganese(IV) bromide<\/strong>: <strong>[Mn(H2O)5Br]Br2<\/strong><\/li>\n\n\n\n<li><strong>Sodium triamminetrichlorotitanate(II)<\/strong>: <strong>Na2[Ti(NH3)3Cl3]<\/strong><\/li>\n\n\n\n<li><strong>Pentacarbonylchlorocopper(II) chloride<\/strong>: <strong>[Cu(CO)5Cl]Cl<\/strong><\/li>\n<\/ol>\n\n\n\n<p>These names and formulas follow the conventions for naming coordination compounds, where the ligands are named in alphabetical order (ignoring prefixes like &#8220;tri-&#8221; and &#8220;penta-&#8220;) and the oxidation state of the metal is indicated in parentheses. The counterions balance the charges on the coordination sphere.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-167.jpeg\" alt=\"\" class=\"wp-image-241653\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write the chemical formula of these coordination compounds formula name pentaaquabromomanganese(IV) bromide X 5 2 sodium triamminetrichlorotitanate(II) pentacarbonylchlorocopper(II) chloride The Correct Answer and Explanation is: Let&#8217;s break down the chemical formulas for each of these coordination compounds: 1. Pentaaquabromomanganese(IV) bromide 2. Sodium triamminetrichlorotitanate(II) 3. Pentacarbonylchlorocopper(II) chloride Summary of Formulas: These names and formulas follow the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-241652","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/241652","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=241652"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/241652\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=241652"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=241652"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=241652"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}