{"id":241754,"date":"2025-07-04T03:04:26","date_gmt":"2025-07-04T03:04:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=241754"},"modified":"2025-07-04T03:04:28","modified_gmt":"2025-07-04T03:04:28","slug":"which-of-the-following-is-the-lewis-dot-structure-for-one-formula-unit-of-calcium-oxide","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/04\/which-of-the-following-is-the-lewis-dot-structure-for-one-formula-unit-of-calcium-oxide\/","title":{"rendered":"Which of the following is the Lewis dot structure for one formula unit of calcium oxide"},"content":{"rendered":"\n

Which of the following is the Lewis dot structure for one formula unit of calcium oxide<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The Lewis dot structure for one formula unit of calcium oxide (CaO) represents the bonding between a calcium atom (Ca) and an oxygen atom (O). Here’s how to determine the correct structure:<\/p>\n\n\n\n

Step-by-Step Explanation:<\/h3>\n\n\n\n
    \n
  1. Electron Configuration<\/strong>:\n
      \n
    • Calcium (Ca)<\/strong> is an alkaline earth metal in Group 2 of the periodic table. It has an atomic number of 20, meaning its electron configuration is:
      Ca:\u20091s2\u20092s2\u20092p6\u20093s2\u20093p6\u20094s2\\text{Ca:} \\, 1s^2 \\, 2s^2 \\, 2p^6 \\, 3s^2 \\, 3p^6 \\, 4s^2Ca:1s22s22p63s23p64s2
      Calcium has two valence electrons in the 4s orbital (since it\u2019s in Group 2), and it tends to lose these two electrons to achieve a stable electron configuration similar to that of a noble gas (in this case, argon).<\/li>\n\n\n\n
    • Oxygen (O)<\/strong> is in Group 16 with an atomic number of 8, and its electron configuration is:
      O:\u20091s2\u20092s2\u20092p4\\text{O:} \\, 1s^2 \\, 2s^2 \\, 2p^4O:1s22s22p4
      Oxygen has six valence electrons, and it needs two more electrons to complete its octet, thus it tends to gain two electrons.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • Formation of Ions<\/strong>:\n
        \n
      • Calcium (Ca)<\/strong> loses two electrons to form a Ca\u00b2\u207a ion<\/strong>. This leaves it with a stable electron configuration similar to argon.<\/li>\n\n\n\n
      • Oxygen (O)<\/strong> gains two electrons to form an O\u00b2\u207b ion<\/strong>, achieving a stable electron configuration like neon.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
      • Bonding<\/strong>:\n
          \n
        • Calcium donates its two valence electrons to oxygen, forming an ionic bond between the Ca\u00b2\u207a and O\u00b2\u207b ions.<\/li>\n\n\n\n
        • Since this is an ionic bond, there are no shared electrons, but the bond is a result of the electrostatic attraction between the positively charged Ca\u00b2\u207a ion and the negatively charged O\u00b2\u207b ion.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n

          Lewis Structure:<\/h3>\n\n\n\n
            \n
          • Ca\u00b2\u207a<\/strong>: This ion does not have any dots, as it has lost its valence electrons.<\/li>\n\n\n\n
          • O\u00b2\u207b<\/strong>: This ion will have eight dots around it, representing its full octet.<\/li>\n<\/ul>\n\n\n\n

            Thus, the correct Lewis dot structure is represented as:<\/p>\n\n\n\n

            Ca\u00b2\u207a [O\u00b2\u207b]<\/strong><\/p>\n\n\n\n

            The two ions are attracted to each other in a 1:1 ratio to form calcium oxide, with the calcium ion and oxide ion held together by the ionic bond.<\/p>\n\n\n\n

            Conclusion:<\/h3>\n\n\n\n

            In summary, the Lewis dot structure for one formula unit of calcium oxide (CaO) involves the calcium ion (Ca\u00b2\u207a) with no dots (since it lost its electrons) and the oxide ion (O\u00b2\u207b) with eight dots around it. This illustrates the ionic bonding between the two ions, making it a stable compound.<\/p>\n\n\n\n

            \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

            Which of the following is the Lewis dot structure for one formula unit of calcium oxide The Correct Answer and Explanation is: The Lewis dot structure for one formula unit of calcium oxide (CaO) represents the bonding between a calcium atom (Ca) and an oxygen atom (O). Here’s how to determine the correct structure: Step-by-Step […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-241754","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/241754","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=241754"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/241754\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=241754"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=241754"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=241754"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}