{"id":241912,"date":"2025-07-04T04:13:46","date_gmt":"2025-07-04T04:13:46","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=241912"},"modified":"2025-07-04T04:13:48","modified_gmt":"2025-07-04T04:13:48","slug":"what-is-the-formula-for-copper-ii-chlorate-preview","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/04\/what-is-the-formula-for-copper-ii-chlorate-preview\/","title":{"rendered":"What is the formula for copper (II) chlorate Preview"},"content":{"rendered":"\n<p>What is the formula for copper (II) chlorate Preview What is the molar mass of copper (II) chlorate g\/mole How many moles are there in 174.7 g of copper (II) chlorate moles How many grams are there in 2.5 moles of copper (II) chlorate g<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Formula for Copper (II) Chlorate:<\/h3>\n\n\n\n<p>The formula for copper (II) chlorate is <strong>Cu(ClO3)2<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Molar Mass of Copper (II) Chlorate:<\/h3>\n\n\n\n<p>To calculate the molar mass of <strong>Cu(ClO3)2<\/strong>, we need to sum up the atomic masses of all the atoms in the formula:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Copper (Cu) has an atomic mass of 63.55 g\/mol.<\/li>\n\n\n\n<li>Chlorine (Cl) has an atomic mass of 35.45 g\/mol.<\/li>\n\n\n\n<li>Oxygen (O) has an atomic mass of 16.00 g\/mol.<\/li>\n<\/ul>\n\n\n\n<p>Now, let&#8217;s calculate the molar mass:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>1 Cu atom = 63.55 g\/mol<\/li>\n\n\n\n<li>2 Cl atoms = 2 \u00d7 35.45 g\/mol = 70.90 g\/mol<\/li>\n\n\n\n<li>6 O atoms (since there are 3 O atoms in each ClO3 group and there are 2 such groups) = 6 \u00d7 16.00 g\/mol = 96.00 g\/mol<\/li>\n<\/ul>\n\n\n\n<p>Thus, the molar mass of Cu(ClO3)2 is:<br>63.55+70.90+96.00=230.45\u2009g\/mol63.55 + 70.90 + 96.00 = 230.45 \\, \\text{g\/mol}63.55+70.90+96.00=230.45g\/mol<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Moles in 174.7 g of Copper (II) Chlorate:<\/h3>\n\n\n\n<p>To find the number of moles, we use the formula:moles=massmolar&nbsp;mass\\text{moles} = \\frac{\\text{mass}}{\\text{molar mass}}moles=molar&nbsp;massmass\u200b<\/p>\n\n\n\n<p>Substitute the given values:moles=174.7\u2009g230.45\u2009g\/mol=0.758\u2009moles\\text{moles} = \\frac{174.7 \\, \\text{g}}{230.45 \\, \\text{g\/mol}} = 0.758 \\, \\text{moles}moles=230.45g\/mol174.7g\u200b=0.758moles<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Grams in 2.5 Moles of Copper (II) Chlorate:<\/h3>\n\n\n\n<p>To find the mass in grams for 2.5 moles, we use the formula:mass=moles\u00d7molar&nbsp;mass\\text{mass} = \\text{moles} \\times \\text{molar mass}mass=moles\u00d7molar&nbsp;mass<\/p>\n\n\n\n<p>Substitute the given values:mass=2.5\u2009moles\u00d7230.45\u2009g\/mol=576.125\u2009g\\text{mass} = 2.5 \\, \\text{moles} \\times 230.45 \\, \\text{g\/mol} = 576.125 \\, \\text{g}mass=2.5moles\u00d7230.45g\/mol=576.125g<\/p>\n\n\n\n<p>Thus, the answers are:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>The molar mass of copper (II) chlorate is <strong>230.45 g\/mol<\/strong>.<\/li>\n\n\n\n<li>There are <strong>0.758 moles<\/strong> in 174.7 g of copper (II) chlorate.<\/li>\n\n\n\n<li>There are <strong>576.13 grams<\/strong> in 2.5 moles of copper (II) chlorate.<\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-113.jpeg\" alt=\"\" class=\"wp-image-241913\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the formula for copper (II) chlorate Preview What is the molar mass of copper (II) chlorate g\/mole How many moles are there in 174.7 g of copper (II) chlorate moles How many grams are there in 2.5 moles of copper (II) chlorate g The Correct Answer and Explanation is: Formula for Copper (II) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center 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