{"id":242489,"date":"2025-07-04T07:55:40","date_gmt":"2025-07-04T07:55:40","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=242489"},"modified":"2025-07-04T07:55:42","modified_gmt":"2025-07-04T07:55:42","slug":"a-1-99-m-tall-basketball-player-wants-to-sink-the-ball-into-a-basket-located-14-5-m-from-the-player-as-in-figure-p3-58","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/04\/a-1-99-m-tall-basketball-player-wants-to-sink-the-ball-into-a-basket-located-14-5-m-from-the-player-as-in-figure-p3-58\/","title":{"rendered":"A 1.99 m tall basketball player wants to sink the ball into a basket located 14.5 m from the player, as in Figure P3.58."},"content":{"rendered":"\n

A 1.99 m tall basketball player wants to sink the ball into a basket located 14.5 m from the player, as in Figure P3.58. If he shoots the ball at a
angle, at what initial speed must he throw the basketball so that it goes through the hoop without striking the backboard<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

12.64<\/strong><\/p>\n\n\n\n

To find the initial speed of the basketball, we can analyze its motion using the principles of projectile motion. We will break the motion down into its horizontal and vertical components.<\/p>\n\n\n\n

First, let’s establish a coordinate system and list the known variables. Let the point where the ball is released be the origin (0,0) for simplicity in the initial calculation, and then adjust for the height difference. An alternative and more direct approach is to set the origin at the player’s feet. Let’s use the latter.<\/p>\n\n\n\n

Known Information:<\/strong><\/p>\n\n\n\n