{"id":242778,"date":"2025-07-04T09:20:28","date_gmt":"2025-07-04T09:20:28","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=242778"},"modified":"2025-07-04T09:20:30","modified_gmt":"2025-07-04T09:20:30","slug":"mycomycin-a-naturally-occurring-antibiotic-produced-by-the-fungus-nocardia-acidophilus-has-the-molecular-formula-c13h10o2-and-the-systematic-name-3578-tridecatetraene-1012","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/04\/mycomycin-a-naturally-occurring-antibiotic-produced-by-the-fungus-nocardia-acidophilus-has-the-molecular-formula-c13h10o2-and-the-systematic-name-3578-tridecatetraene-1012\/","title":{"rendered":"Mycomycin, a naturally occurring antibiotic produced by the fungus Nocardia acidophilus, has the molecular formula\u00a0C13H10O2\u00a0and the systematic name\u00a03,5,7,8\u00a0-tridecatetraene- 10,12 diynoic acid."},"content":{"rendered":"\n
Mycomycin, a naturally occurring antibiotic produced by the fungus Nocardia acidophilus, has the molecular formula C13H10O2 and the systematic name 3,5,7,8 -tridecatetraene- 10,12 diynoic acid. Draw the structure of mycomycin.<\/pre>\n\n\n\n


<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n
To draw the structure of mycomycin, you need to account for its molecular formula C13H10O2C_{13}H_{10}O_2C13\u200bH10\u200bO2\u200b and its systematic name “3,4,7,8-tridecatetraene-10,12-diynoic acid.”<\/p>\n\n\n\n
Step 1: Identify the basic components<\/h3>\n\n\n\n
    \n
  1. Aromatic rings<\/strong>: The name “tridecatetraene” suggests the presence of conjugated double bonds (tetraene), and this is often indicative of an aromatic ring structure, which is likely a benzene ring (C6H5).<\/li>\n\n\n\n
  2. Conjugated system<\/strong>: The name “tridecatetraene” also tells you there are alternating double bonds (i.e., a conjugated system of 4 double bonds). This is typically found in a polyene chain.<\/li>\n\n\n\n
  3. Diynoic acid<\/strong>: The presence of “diynoic acid” suggests two triple bonds (C\u2261C) are located at positions 10 and 12 of the molecule, along with a carboxylic acid group (-COOH) at the end.<\/li>\n<\/ol>\n\n\n\n
    Step 2: Drawing the structure<\/h3>\n\n\n\n
      \n
    • Benzene ring<\/strong>: Start with a six-membered carbon ring with alternating double bonds (C6H5).<\/li>\n\n\n\n
    • Polyene chain<\/strong>: Attach a polyene chain to the benzene ring. The chain should be 7 carbon atoms long, with alternating single and double bonds. The positions 10 and 12 should be triple bonds.<\/li>\n\n\n\n
    • Carboxylic acid group<\/strong>: Attach a carboxyl group (-COOH) to the last carbon of the polyene chain.<\/li>\n\n\n\n
    • Positioning of functional groups<\/strong>: The carboxyl group is at the 10th position, and the triple bonds occur at positions 10 and 12. This conjugated system is consistent with mycomycin\u2019s structure.<\/li>\n<\/ul>\n\n\n\n
      Step 3: The structure<\/h3>\n\n\n\n
      The final structure of mycomycin would look like this:<\/p>\n\n\n\n
        \n
      • A benzene ring (C6H5) attached to a long chain (C13).<\/li>\n\n\n\n
      • The chain consists of alternating single and double bonds, with two triple bonds and a carboxyl group (-COOH) at the terminal end.<\/li>\n<\/ul>\n\n\n\n
        Explanation of the structure:<\/h3>\n\n\n\n
        The alternating double bonds in the polyene chain create a conjugated system, which is important for the molecule’s chemical reactivity. The carboxyl group at the end of the molecule contributes to its acidic nature and may play a role in its biological activity as an antibiotic. The conjugated system and triple bonds contribute to the molecule’s overall stability and its ability to interact with bacterial targets.<\/p>\n\n\n\n
        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"
        Mycomycin, a naturally occurring antibiotic produced by the fungus Nocardia acidophilus, has the molecular formula C13H10O2 and the systematic name 3,5,7,8 -tridecatetraene- 10,12 diynoic acid. Draw the structure of mycomycin. The Correct Answer and Explanation is: To draw the structure of mycomycin, you need to account for its molecular formula C13H10O2C_{13}H_{10}O_2C13\u200bH10\u200bO2\u200b and its systematic name “3,4,7,8-tridecatetraene-10,12-diynoic acid.” Step 1: […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-242778","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/242778","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=242778"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/242778\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=242778"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=242778"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=242778"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}