{"id":243449,"date":"2025-07-04T14:02:46","date_gmt":"2025-07-04T14:02:46","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=243449"},"modified":"2025-07-04T14:02:48","modified_gmt":"2025-07-04T14:02:48","slug":"which-molecule-is-a-stereoisomer-of-cis-2-pentene-3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/04\/which-molecule-is-a-stereoisomer-of-cis-2-pentene-3\/","title":{"rendered":"Which molecule is a stereoisomer of cis-2-pentene"},"content":{"rendered":"\n<p>Which molecule is a stereoisomer of cis-2-pentene? 0 B C. D<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-127.png\" alt=\"\" class=\"wp-image-243451\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is&nbsp;<strong>B<\/strong>.<\/p>\n\n\n\n<p>Stereoisomers are molecules that have the same molecular formula and the same connectivity of atoms, but they differ in the spatial arrangement of those atoms. To find the stereoisomer of&nbsp;<em>cis<\/em>-2-pentene, we need to find a molecule that meets these specific criteria.<\/p>\n\n\n\n<p>First, let&#8217;s analyze the starting molecule,&nbsp;<em>cis<\/em>-2-pentene.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>&#8220;Pent&#8221;<\/strong>\u00a0indicates a five-carbon chain.<\/li>\n\n\n\n<li><strong>&#8220;ene&#8221;<\/strong>\u00a0signifies a carbon-carbon double bond.<\/li>\n\n\n\n<li><strong>&#8220;2-&#8220;<\/strong>\u00a0places this double bond between the second and third carbon atoms.<\/li>\n\n\n\n<li><strong>&#8220;cis&#8221;<\/strong>\u00a0describes the geometry around the double bond, meaning the main carbon chain substituents (a methyl group and an ethyl group) are on the\u00a0<em>same side<\/em>\u00a0of the double bond.<\/li>\n\n\n\n<li>The molecular formula for any pentene is C5H10.<\/li>\n<\/ul>\n\n\n\n<p>Now, let&#8217;s evaluate the given options:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Molecule A<\/strong>\u00a0is 1-pentyne. It has a five-carbon chain but features a triple bond. Its molecular formula is C5H8. Because both its molecular formula and its connectivity (an alkyne instead of an alkene) are different, it is not a stereoisomer of\u00a0<em>cis<\/em>-2-pentene.<\/li>\n\n\n\n<li><strong>Molecule B<\/strong>\u00a0is\u00a0<em>trans<\/em>-2-pentene. It has a five-carbon chain with a double bond between the second and third carbons, just like\u00a0<em>cis<\/em>-2-pentene. Therefore, it shares the same molecular formula (C5H10) and the same connectivity. The key difference is its spatial arrangement. The term &#8220;trans&#8221; indicates that the carbon chain substituents are on\u00a0<em>opposite sides<\/em>\u00a0of the double bond. Since it only differs in its three-dimensional geometry,\u00a0<em>trans<\/em>-2-pentene is the stereoisomer (specifically, a geometric isomer or diastereomer) of\u00a0<em>cis<\/em>-2-pentene.<\/li>\n\n\n\n<li><strong>Molecule C<\/strong>\u00a0is 2-pentyne. It has a triple bond and a molecular formula of C5H8. For the same reasons as molecule A, it cannot be a stereoisomer of\u00a0<em>cis<\/em>-2-pentene.<\/li>\n\n\n\n<li><strong>Molecule D<\/strong>\u00a0is pentane. This is a saturated alkane, containing only single bonds. Its molecular formula is C5H12. It has a different molecular formula and connectivity, so it is not an isomer of\u00a0<em>cis<\/em>-2-pentene.<\/li>\n<\/ul>\n\n\n\n<p>Therefore, molecule B is the only option that is a stereoisomer of&nbsp;<em>cis<\/em>-2-pentene.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-332.jpeg\" alt=\"\" class=\"wp-image-243462\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which molecule is a stereoisomer of cis-2-pentene? 0 B C. D The Correct Answer and Explanation is: The correct answer is&nbsp;B. Stereoisomers are molecules that have the same molecular formula and the same connectivity of atoms, but they differ in the spatial arrangement of those atoms. To find the stereoisomer of&nbsp;cis-2-pentene, we need to find [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-243449","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/243449","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=243449"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/243449\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=243449"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=243449"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=243449"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}