{"id":243867,"date":"2025-07-04T17:54:34","date_gmt":"2025-07-04T17:54:34","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=243867"},"modified":"2025-07-04T17:54:36","modified_gmt":"2025-07-04T17:54:36","slug":"what-will-happen-to-the-band-of-light-if-the-width-of-the-slit-is-narrowed","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/04\/what-will-happen-to-the-band-of-light-if-the-width-of-the-slit-is-narrowed\/","title":{"rendered":"What will happen to the band of light if the width of the slit is narrowed"},"content":{"rendered":"\n<p>What will happen to the band of light if the width of the slit is narrowed?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>When the width of the slit is narrowed, the band of light passing through the slit will become wider. This effect is due to the principles of diffraction, which occur when light encounters an obstacle or opening that is comparable in size to its wavelength.<\/p>\n\n\n\n<p>As light passes through a narrow slit, it bends or spreads out. The amount of spreading, known as diffraction, increases as the slit becomes smaller. This is because the waves of light interfere with each other after passing through the slit, creating a pattern of alternating bright and dark bands known as a diffraction pattern. The central band is the brightest, and the subsequent bands, known as fringes, become less intense as you move away from the center.<\/p>\n\n\n\n<p>The diffraction angle, which determines how much the light spreads out, is inversely related to the width of the slit. As the slit narrows, the angle of diffraction increases, and the bands become wider. Mathematically, the angle of diffraction \u03b8 for the first minimum in the diffraction pattern is given by: sin\u2061(\u03b8)=\u03bbd\\sin(\\theta) = \\frac{\\lambda}{d}<\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u03bb\\lambda is the wavelength of the light,<\/li>\n\n\n\n<li>dd is the width of the slit.<\/li>\n<\/ul>\n\n\n\n<p>As the slit width dd decreases, the value of sin\u2061(\u03b8)\\sin(\\theta) increases, leading to a larger diffraction angle. This results in a wider spread of light and a broader diffraction pattern. Therefore, narrowing the slit makes the band of light wider, while increasing the slit width would reduce the diffraction and make the band narrower.<\/p>\n\n\n\n<p>This effect is commonly observed in experiments like Young&#8217;s double-slit experiment and is a clear demonstration of the wave nature of light.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What will happen to the band of light if the width of the slit is narrowed? The correct answer and explanation is: When the width of the slit is narrowed, the band of light passing through the slit will become wider. This effect is due to the principles of diffraction, which occur when light encounters [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-243867","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/243867","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=243867"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/243867\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=243867"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=243867"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=243867"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}