{"id":244767,"date":"2025-07-05T10:58:57","date_gmt":"2025-07-05T10:58:57","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=244767"},"modified":"2025-07-05T10:58:58","modified_gmt":"2025-07-05T10:58:58","slug":"what-is-the-empirical-formula-of-fructose-c6h12o6-found-in-honey","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/05\/what-is-the-empirical-formula-of-fructose-c6h12o6-found-in-honey\/","title":{"rendered":"What is the empirical formula of fructose (C6H12O6) found in honey"},"content":{"rendered":"\n

What is the empirical formula of fructose (C6H12O6) found in honey?<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The empirical formula of fructose (C6H12O6) is CH2O<\/strong>.<\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

The empirical formula represents the simplest whole-number ratio of the elements in a compound. To find the empirical formula for fructose, we first need to express the molecular formula of fructose (C6H12O6) in the simplest whole-number ratio.<\/p>\n\n\n\n

    \n
  1. Identify the elements and their quantities:<\/strong>\n
      \n
    • Fructose consists of Carbon (C), Hydrogen (H), and Oxygen (O).<\/li>\n\n\n\n
    • The molecular formula for fructose is C6H12O6<\/strong>, meaning it contains 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • Simplify the ratio:<\/strong>\n
        \n
      • Divide each subscript by the greatest common divisor (GCD) of the subscripts in the molecular formula.<\/li>\n\n\n\n
      • The GCD of 6 (C), 12 (H), and 6 (O) is 6<\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
      • Divide each element’s subscript by 6:<\/strong>\n
          \n
        • Carbon: 66=1\\frac{6}{6} = 166\u200b=1<\/li>\n\n\n\n
        • Hydrogen: 126=2\\frac{12}{6} = 2612\u200b=2<\/li>\n\n\n\n
        • Oxygen: 66=1\\frac{6}{6} = 166\u200b=1<\/li>\n<\/ul>\n<\/li>\n\n\n\n
        • The empirical formula:<\/strong>\n
            \n
          • The simplified ratio of the elements is 1:2:1, which corresponds to the empirical formula CH2O<\/strong>.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n

            This empirical formula CH2O<\/strong> is the simplest whole-number ratio of carbon, hydrogen, and oxygen atoms in fructose, whereas the molecular formula C6H12O6<\/strong> shows the actual number of atoms in a molecule of fructose.<\/p>\n\n\n\n

            \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

            What is the empirical formula of fructose (C6H12O6) found in honey? The Correct Answer and Explanation is: The empirical formula of fructose (C6H12O6) is CH2O. Explanation: The empirical formula represents the simplest whole-number ratio of the elements in a compound. To find the empirical formula for fructose, we first need to express the molecular formula […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-244767","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/244767","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=244767"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/244767\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=244767"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=244767"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=244767"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}