{"id":244783,"date":"2025-07-05T11:12:41","date_gmt":"2025-07-05T11:12:41","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=244783"},"modified":"2025-07-05T11:12:43","modified_gmt":"2025-07-05T11:12:43","slug":"the-gravitational-force-of-attraction-between-earth-and-the-sun-is-35-471021-n","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/05\/the-gravitational-force-of-attraction-between-earth-and-the-sun-is-35-471021-n\/","title":{"rendered":"The gravitational force of attraction between earth and the sun is 35.4710^21 N"},"content":{"rendered":"\n<p>The gravitational force of attraction between earth and the sun is 35.47<em>10^21 N, Calculate the mass of the sun, given the mass of the earth is 5.98<\/em>10^24 kg and the mean distance between the earth and the sun is 1.496<em>10^11m given G=6.67<\/em>10^-11<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0);color:#0693e3\" class=\"has-inline-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The gravitational force of attraction between two objects can be calculated using Newton\u2019s law of universal gravitation:F=G\u22c5m1\u22c5m2r2F = \\frac{G \\cdot m_1 \\cdot m_2}{r^2}F=r2G\u22c5m1\u200b\u22c5m2\u200b\u200b<\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>FFF is the gravitational force between the two objects (in this case, between the Earth and the Sun), which is 35.47\u00d71021\u2009N35.47 \\times 10^{21} \\, \\text{N}35.47\u00d71021N,<\/li>\n\n\n\n<li>GGG is the gravitational constant, 6.67\u00d710\u221211\u2009N\u22c5m2\/kg26.67 \\times 10^{-11} \\, \\text{N} \\cdot \\text{m}^2\/\\text{kg}^26.67\u00d710\u221211N\u22c5m2\/kg2,<\/li>\n\n\n\n<li>m1m_1m1\u200b is the mass of the Earth, 5.98\u00d71024\u2009kg5.98 \\times 10^{24} \\, \\text{kg}5.98\u00d71024kg,<\/li>\n\n\n\n<li>m2m_2m2\u200b is the mass of the Sun (which we need to find),<\/li>\n\n\n\n<li>rrr is the distance between the centers of the two bodies, 1.496\u00d71011\u2009m1.496 \\times 10^{11} \\, \\text{m}1.496\u00d71011m.<\/li>\n<\/ul>\n\n\n\n<p>Rearrange the formula to solve for m2m_2m2\u200b, the mass of the Sun:m2=F\u22c5r2G\u22c5m1m_2 = \\frac{F \\cdot r^2}{G \\cdot m_1}m2\u200b=G\u22c5m1\u200bF\u22c5r2\u200b<\/p>\n\n\n\n<p>Now, plug in the known values:m2=(35.47\u00d71021)\u22c5(1.496\u00d71011)2(6.67\u00d710\u221211)\u22c5(5.98\u00d71024)m_2 = \\frac{(35.47 \\times 10^{21}) \\cdot (1.496 \\times 10^{11})^2}{(6.67 \\times 10^{-11}) \\cdot (5.98 \\times 10^{24})}m2\u200b=(6.67\u00d710\u221211)\u22c5(5.98\u00d71024)(35.47\u00d71021)\u22c5(1.496\u00d71011)2\u200b<\/p>\n\n\n\n<p>First, calculate the square of the distance:r2=(1.496\u00d71011)2=2.238\u00d71022\u2009m2r^2 = (1.496 \\times 10^{11})^2 = 2.238 \\times 10^{22} \\, \\text{m}^2r2=(1.496\u00d71011)2=2.238\u00d71022m2<\/p>\n\n\n\n<p>Now, calculate the numerator:F\u22c5r2=(35.47\u00d71021)\u22c5(2.238\u00d71022)=7.950\u00d71044\u2009N\u22c5m2F \\cdot r^2 = (35.47 \\times 10^{21}) \\cdot (2.238 \\times 10^{22}) = 7.950 \\times 10^{44} \\, \\text{N} \\cdot \\text{m}^2F\u22c5r2=(35.47\u00d71021)\u22c5(2.238\u00d71022)=7.950\u00d71044N\u22c5m2<\/p>\n\n\n\n<p>Now, calculate the denominator:G\u22c5m1=(6.67\u00d710\u221211)\u22c5(5.98\u00d71024)=3.986\u00d71014\u2009N\u22c5m2\/kgG \\cdot m_1 = (6.67 \\times 10^{-11}) \\cdot (5.98 \\times 10^{24}) = 3.986 \\times 10^{14} \\, \\text{N} \\cdot \\text{m}^2\/\\text{kg}G\u22c5m1\u200b=(6.67\u00d710\u221211)\u22c5(5.98\u00d71024)=3.986\u00d71014N\u22c5m2\/kg<\/p>\n\n\n\n<p>Finally, divide the numerator by the denominator to find the mass of the Sun:m2=7.950\u00d710443.986\u00d71014=1.994\u00d71030\u2009kgm_2 = \\frac{7.950 \\times 10^{44}}{3.986 \\times 10^{14}} = 1.994 \\times 10^{30} \\, \\text{kg}m2\u200b=3.986\u00d710147.950\u00d71044\u200b=1.994\u00d71030kg<\/p>\n\n\n\n<p>Thus, the mass of the Sun is approximately:m2=1.994\u00d71030\u2009kgm_2 = 1.994 \\times 10^{30} \\, \\text{kg}m2\u200b=1.994\u00d71030kg<\/p>\n\n\n\n<p>This calculation shows that the Sun\u2019s mass is around 1.994\u00d71030\u2009kg1.994 \\times 10^{30} \\, \\text{kg}1.994\u00d71030kg, which is in close agreement with the commonly accepted value of approximately 2\u00d71030\u2009kg2 \\times 10^{30} \\, \\text{kg}2\u00d71030kg.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-516.jpeg\" alt=\"\" class=\"wp-image-244784\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The gravitational force of attraction between earth and the sun is 35.4710^21 N, Calculate the mass of the sun, given the mass of the earth is 5.9810^24 kg and the mean distance between the earth and the sun is 1.49610^11m given G=6.6710^-11 The Correct Answer and Explanation is: The gravitational force of attraction between two [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center 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