{"id":245337,"date":"2025-07-06T04:01:53","date_gmt":"2025-07-06T04:01:53","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=245337"},"modified":"2025-07-06T04:01:56","modified_gmt":"2025-07-06T04:01:56","slug":"assign-the-characteristic-functional-groups-with-their-ir-peaks","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/06\/assign-the-characteristic-functional-groups-with-their-ir-peaks\/","title":{"rendered":"Assign the characteristic functional groups with their IR peaks"},"content":{"rendered":"\n<p>Assign the characteristic functional groups with their IR peaks. 9-Fluorenol<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-216.png\" alt=\"\" class=\"wp-image-245338\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here is the assignment of the characteristic functional groups in 9-Fluorenol with their corresponding peaks in the provided IR spectrum.<\/p>\n\n\n\n<p><strong>Correct Answer:<\/strong><\/p>\n\n\n\n<p>The IR spectrum of 9-Fluorenol can be analyzed by assigning the following absorption peaks to their respective functional groups:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>O-H Stretch (Alcohol):<\/strong>\u00a0The broad, strong absorption band centered at approximately\u00a0<strong>3200 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n<li><strong>Aromatic C-H Stretch:<\/strong>\u00a0The sharp peaks located just above 3000 cm\u207b\u00b9, in the range of\u00a0<strong>3020-3070 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n<li><strong>Aromatic C=C Stretch:<\/strong>\u00a0The multiple sharp peaks in the region of\u00a0<strong>1450-1600 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n<li><strong>C-O Stretch (Secondary Alcohol):<\/strong>\u00a0The strong, sharp peak at approximately\u00a0<strong>1015 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n<li><strong>Aromatic C-H Bend:<\/strong>\u00a0The very strong, sharp peak at approximately\u00a0<strong>740 cm\u207b\u00b9<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p>The IR spectrum of 9-Fluorenol displays characteristic absorptions that confirm its molecular structure, which includes a secondary alcohol and two aromatic rings. The analysis proceeds by identifying key vibrations from highest to lowest wavenumber.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>O-H Stretch (~3200 cm\u207b\u00b9):<\/strong>\u00a0The most easily identifiable feature is the very broad and strong absorption band centered around 3200 cm\u207b\u00b9. This is the definitive signature for the O-H stretching vibration of an alcohol. The broadness of the peak is a direct result of intermolecular hydrogen bonding between the hydroxyl groups of different 9-Fluorenol molecules.<\/li>\n\n\n\n<li><strong>C-H Stretches (~3050 cm\u207b\u00b9):<\/strong>\u00a0The region around 3000 cm\u207b\u00b9 is crucial for distinguishing between different types of C-H bonds. The sharp absorptions seen slightly above 3000 cm\u207b\u00b9 (approx. 3020-3070 cm\u207b\u00b9) are characteristic of C-H stretches where the carbon is sp\u00b2 hybridized, confirming the presence of aromatic rings. A weaker C-H stretch from the sp\u00b3-hybridized carbon at position 9 is expected just below 3000 cm\u207b\u00b9, although it may be less distinct.<\/li>\n\n\n\n<li><strong>Aromatic C=C Stretches (1450-1600 cm\u207b\u00b9):<\/strong>\u00a0The presence of several sharp peaks in the 1450-1600 cm\u207b\u00b9 region is indicative of carbon-carbon double bond (C=C) stretching within the aromatic rings. These &#8220;ring breathing&#8221; vibrations are a hallmark of aromatic compounds.<\/li>\n\n\n\n<li><strong>C-O Stretch (~1015 cm\u207b\u00b9):<\/strong>\u00a0In the fingerprint region, a strong and sharp absorption appears at about 1015 cm\u207b\u00b9. This peak is assigned to the C-O single bond stretching vibration. Its position is characteristic for a secondary alcohol, such as the one in 9-Fluorenol.<\/li>\n\n\n\n<li><strong>Aromatic C-H Bending (~740 cm\u207b\u00b9):<\/strong>\u00a0Finally, the very strong peak around 740 cm\u207b\u00b9 is due to the out-of-plane bending of the C-H bonds on the aromatic rings. The position of this powerful absorption is diagnostic for the substitution pattern; in this case, it is consistent with ortho-disubstituted rings.<\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-632.jpeg\" alt=\"\" class=\"wp-image-245339\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Assign the characteristic functional groups with their IR peaks. 9-Fluorenol The Correct Answer and Explanation is: Here is the assignment of the characteristic functional groups in 9-Fluorenol with their corresponding peaks in the provided IR spectrum. Correct Answer: The IR spectrum of 9-Fluorenol can be analyzed by assigning the following absorption peaks to their respective [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-245337","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/245337","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=245337"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/245337\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=245337"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=245337"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=245337"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}