{"id":245375,"date":"2025-07-06T07:17:04","date_gmt":"2025-07-06T07:17:04","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=245375"},"modified":"2025-07-06T07:17:07","modified_gmt":"2025-07-06T07:17:07","slug":"calculate-the-molecular-mass-of-menthol-c10h20","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/06\/calculate-the-molecular-mass-of-menthol-c10h20\/","title":{"rendered":"Calculate the molecular mass of menthol, C10H20"},"content":{"rendered":"\n<p>Calculate the molecular mass of menthol, C10H20. 156.26 amu<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-220.png\" alt=\"\" class=\"wp-image-245376\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer:<\/strong>&nbsp;156.26 amu<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To calculate the molecular mass of a compound, you must sum the atomic masses of all the atoms present in its chemical formula. The molecular mass represents the total mass of one molecule of the substance and is expressed in atomic mass units (amu).<\/p>\n\n\n\n<p>The chemical formula for menthol is given as C\u2081\u2080H\u2082\u2080O. Let&#8217;s break down the calculation step-by-step:<\/p>\n\n\n\n<p><strong>1. Identify the Elements and Atom Count:<\/strong><br>First, we identify the elements and the number of atoms for each from the chemical formula C\u2081\u2080H\u2082\u2080O:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbon (C):<\/strong>\u00a0There are 10 atoms.<\/li>\n\n\n\n<li><strong>Hydrogen (H):<\/strong>\u00a0There are 20 atoms.<\/li>\n\n\n\n<li><strong>Oxygen (O):<\/strong>\u00a0There is 1 atom.<\/li>\n<\/ul>\n\n\n\n<p><strong>2. Find the Atomic Mass of Each Element:<\/strong><br>Next, we use the standard average atomic masses for each element as found on the periodic table:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The atomic mass of Carbon (C) is approximately\u00a0<strong>12.01 amu<\/strong>.<\/li>\n\n\n\n<li>The atomic mass of Hydrogen (H) is approximately\u00a0<strong>1.008 amu<\/strong>.<\/li>\n\n\n\n<li>The atomic mass of Oxygen (O) is approximately\u00a0<strong>16.00 amu<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p><strong>3. Calculate the Total Mass for Each Element:<\/strong><br>Now, we multiply the number of atoms of each element by its atomic mass to find its total contribution to the molecule&#8217;s overall mass.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Total mass from Carbon:<\/strong>\u00a010 atoms \u00d7 12.01 amu\/atom =\u00a0<strong>120.10 amu<\/strong><\/li>\n\n\n\n<li><strong>Total mass from Hydrogen:<\/strong>\u00a020 atoms \u00d7 1.008 amu\/atom =\u00a0<strong>20.16 amu<\/strong><\/li>\n\n\n\n<li><strong>Total mass from Oxygen:<\/strong>\u00a01 atom \u00d7 16.00 amu\/atom =\u00a0<strong>16.00 amu<\/strong><\/li>\n<\/ul>\n\n\n\n<p><strong>4. Sum the Masses to Find the Molecular Mass:<\/strong><br>Finally, we add the total masses of all the elements together to determine the molecular mass of menthol.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Molecular Mass = (Total mass of Carbon) + (Total mass of Hydrogen) + (Total mass of Oxygen)<\/li>\n\n\n\n<li>Molecular Mass = 120.10 amu + 20.16 amu + 16.00 amu<\/li>\n\n\n\n<li><strong>Molecular Mass = 156.26 amu<\/strong><\/li>\n<\/ul>\n\n\n\n<p>This calculated value matches one of the options provided. Therefore, the molecular mass of menthol is 156.26 amu<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-641.jpeg\" alt=\"\" class=\"wp-image-245377\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Calculate the molecular mass of menthol, C10H20. 156.26 amu The Correct Answer and Explanation is: Correct Answer:&nbsp;156.26 amu Explanation: To calculate the molecular mass of a compound, you must sum the atomic masses of all the atoms present in its chemical formula. The molecular mass represents the total mass of one molecule of the substance [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-245375","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/245375","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=245375"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/245375\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=245375"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=245375"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=245375"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}