{"id":245423,"date":"2025-07-06T07:49:25","date_gmt":"2025-07-06T07:49:25","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=245423"},"modified":"2025-07-06T07:49:27","modified_gmt":"2025-07-06T07:49:27","slug":"hydroxide-and-hydrochloric-acid","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/06\/hydroxide-and-hydrochloric-acid\/","title":{"rendered":"Hydroxide and hydrochloric acid"},"content":{"rendered":"\n

Hydroxide and hydrochloric acid? a. OH-(aq) + H+(aq) \u00e0 H2O(l) b. NaOH(aq) + HCl(aq) \u00e0 NaCl(aq) + H2O(l) c. Na+(aq) + Cl-(aq) \u00e0 NaCl(aq) d. OH- + H+ \u00e0 H2O
Which of the following represents the net ionic equation for the acid\/base reaction between sodium hydroxide and hydrochloric acid? a. OH-(aq) + H+(aq) \u00e0 H2O(l) b. NaOH(aq) + HCl(aq) \u00e0 NaCl(aq) + H2O(l) c. Na+(aq) + Cl-(aq) \u00e0 NaCl(aq) d. OH- + H+ \u00e0 H2O<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The correct net ionic equation for the acid\/base reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl) is:<\/p>\n\n\n\n

a. OH-(aq) + H+(aq) \u2192 H2O(l)<\/strong><\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n
    \n
  1. Understanding the Reaction:<\/strong>
    When sodium hydroxide (NaOH), a strong base, reacts with hydrochloric acid (HCl), a strong acid, they undergo a neutralization reaction. This reaction results in the formation of water (H2O) and sodium chloride (NaCl), a salt. The complete equation is: NaOH(aq)+HCl(aq)\u2192NaCl(aq)+H2O(l)NaOH(aq) + HCl(aq) \\rightarrow NaCl(aq) + H2O(l)NaOH(aq)+HCl(aq)\u2192NaCl(aq)+H2O(l)<\/li>\n\n\n\n
  2. Breaking Down the Ionic Components:<\/strong>
    Both NaOH and HCl dissociate fully in water because they are strong electrolytes. This means the equation can be written in terms of their ions:
    • NaOH \u2192 Na+(aq) + OH-(aq)<\/strong><\/li>
    • HCl \u2192 H+(aq) + Cl-(aq)<\/strong><\/li><\/ul>Substituting these into the reaction gives: Na+(aq)+OH\u2212(aq)+H+(aq)+Cl\u2212(aq)\u2192Na+(aq)+Cl\u2212(aq)+H2O(l)Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) \\rightarrow Na+(aq) + Cl-(aq) + H2O(l)Na+(aq)+OH\u2212(aq)+H+(aq)+Cl\u2212(aq)\u2192Na+(aq)+Cl\u2212(aq)+H2O(l)<\/li>\n\n\n\n
    • Identifying the Spectator Ions:<\/strong>
      In the above equation, the sodium ion (Na+) and chloride ion (Cl-) are spectator ions, meaning they do not participate in the actual chemical change. They appear on both sides of the equation without being altered.<\/li>\n\n\n\n
    • Net Ionic Equation:<\/strong>
      By removing the spectator ions, the net ionic equation focuses on the actual reaction that occurs, which is the combination of hydroxide ions (OH-) from NaOH and hydrogen ions (H+) from HCl to form water: OH\u2212(aq)+H+(aq)\u2192H2O(l)OH-(aq) + H+(aq) \\rightarrow H2O(l)OH\u2212(aq)+H+(aq)\u2192H2O(l) This equation shows the essence of the acid\/base neutralization process, where hydroxide ions (a base) combine with hydrogen ions (an acid) to produce water.<\/li>\n<\/ol>\n\n\n\n

      Other Answer Choices:<\/h3>\n\n\n\n
        \n
      • b. NaOH(aq) + HCl(aq) \u2192 NaCl(aq) + H2O(l):<\/strong> This is the complete molecular equation but does not represent the net ionic equation.<\/li>\n\n\n\n
      • c. Na+(aq) + Cl-(aq) \u2192 NaCl(aq):<\/strong> This shows the dissociation of sodium chloride in solution, but it doesn’t represent the acid\/base reaction.<\/li>\n\n\n\n
      • d. OH- + H+ \u2192 H2O:<\/strong> This is similar to option a<\/strong>, but it is missing the aqueous state notation for the ions. However, it’s essentially the same equation.<\/li>\n<\/ul>\n\n\n\n

        The net ionic equation is the most simplified form that focuses on the actual chemical change, leaving out the spectator ions.<\/p>\n\n\n\n

        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

        Hydroxide and hydrochloric acid? a. OH-(aq) + H+(aq) \u00e0 H2O(l) b. NaOH(aq) + HCl(aq) \u00e0 NaCl(aq) + H2O(l) c. Na+(aq) + Cl-(aq) \u00e0 NaCl(aq) d. OH- + H+ \u00e0 H2OWhich of the following represents the net ionic equation for the acid\/base reaction between sodium hydroxide and hydrochloric acid? a. OH-(aq) + H+(aq) \u00e0 H2O(l) b. […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-245423","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/245423","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=245423"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/245423\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=245423"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=245423"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=245423"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}