{"id":245439,"date":"2025-07-06T07:51:58","date_gmt":"2025-07-06T07:51:58","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=245439"},"modified":"2025-07-06T07:52:00","modified_gmt":"2025-07-06T07:52:00","slug":"calculate-the-molecular-formula-mass-of-the-following-compound","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/06\/calculate-the-molecular-formula-mass-of-the-following-compound\/","title":{"rendered":"Calculate the molecular (formula) mass of the following compound"},"content":{"rendered":"\n<p>Calculate the molecular (formula) mass of the following compound: chromium(II) acetate<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The molecular formula for chromium(II) acetate is Cr(C2H3O2)2\\text{Cr(C}_2\\text{H}_3\\text{O}_2\\text{)}_2, which consists of one chromium (Cr) ion and two acetate (C\u2082H\u2083O\u2082) ions.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step-by-Step Calculation:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Chromium (Cr)<\/strong>: Chromium(II) indicates the chromium ion has a +2 charge. The atomic mass of chromium (Cr) is approximately <strong>52.00 g\/mol<\/strong>.<\/li>\n\n\n\n<li><strong>Acetate (C\u2082H\u2083O\u2082)<\/strong>: The acetate ion consists of two carbon (C) atoms, three hydrogen (H) atoms, and two oxygen (O) atoms. The atomic masses of carbon, hydrogen, and oxygen are as follows:<ul><li>Carbon (C): 12.01 g\/mol<\/li><li>Hydrogen (H): 1.008 g\/mol<\/li><li>Oxygen (O): 16.00 g\/mol<\/li><\/ul>Now, calculate the molecular mass of one acetate ion:<ul><li>Carbon: 2\u00d712.01=24.022 \\times 12.01 = 24.02 g\/mol<\/li><li>Hydrogen: 3\u00d71.008=3.0243 \\times 1.008 = 3.024 g\/mol<\/li><li>Oxygen: 2\u00d716.00=32.002 \\times 16.00 = 32.00 g\/mol<\/li><\/ul>Total mass of one acetate ion: 24.02+3.024+32.00=59.044\u2009g\/mol24.02 + 3.024 + 32.00 = 59.044 \\, \\text{g\/mol}<\/li>\n\n\n\n<li><strong>Two Acetate Ions<\/strong>: Since there are two acetate ions in chromium(II) acetate, multiply the molecular mass of one acetate ion by two: 59.044\u00d72=118.088\u2009g\/mol59.044 \\times 2 = 118.088 \\, \\text{g\/mol}<\/li>\n\n\n\n<li><strong>Total Molecular Mass<\/strong>: Now, sum the masses of the chromium ion and the two acetate ions: 52.00\u2009(Cr)+118.088\u2009(2\u00a0Acetates)=170.088\u2009g\/mol52.00 \\, (\\text{Cr}) + 118.088 \\, (\\text{2 Acetates}) = 170.088 \\, \\text{g\/mol}<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p>The molecular mass of chromium(II) acetate is <strong>170.088 g\/mol<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Calculate the molecular (formula) mass of the following compound: chromium(II) acetate The correct answer and explanation is: The molecular formula for chromium(II) acetate is Cr(C2H3O2)2\\text{Cr(C}_2\\text{H}_3\\text{O}_2\\text{)}_2, which consists of one chromium (Cr) ion and two acetate (C\u2082H\u2083O\u2082) ions. Step-by-Step Calculation: Final Answer: The molecular mass of chromium(II) acetate is 170.088 g\/mol.<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-245439","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/245439","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=245439"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/245439\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=245439"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=245439"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=245439"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}