{"id":245796,"date":"2025-07-06T12:42:49","date_gmt":"2025-07-06T12:42:49","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=245796"},"modified":"2025-07-06T12:42:51","modified_gmt":"2025-07-06T12:42:51","slug":"write-the-balanced-net-ionic-equation-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/06\/write-the-balanced-net-ionic-equation-2\/","title":{"rendered":"Write the balanced net ionic equation"},"content":{"rendered":"\n<p>Q(13) CuSO4(aq) + NaOH(aq) Write the balanced net ionic equation Q(14) CuSO4(aq) + Na2CO3(aq) Write the balanced net ionic equation Q(15) MnSO4(aq) + Na3PO4(aq) Write the balanced net ionic equation<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0);color:#0693e3\" class=\"has-inline-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>Net Ionic Equation for CuSO4(aq) + NaOH(aq):<\/strong><\/h3>\n\n\n\n<p><strong>Step 1: Write the balanced molecular equation.<\/strong>CuSO4(aq)+2NaOH(aq)\u2192Cu(OH)2(s)+Na2SO4(aq)\\text{CuSO}_4(aq) + 2\\text{NaOH}(aq) \\rightarrow \\text{Cu(OH)}_2(s) + \\text{Na}_2\\text{SO}_4(aq)CuSO4\u200b(aq)+2NaOH(aq)\u2192Cu(OH)2\u200b(s)+Na2\u200bSO4\u200b(aq)<\/p>\n\n\n\n<p><strong>Step 2: Dissociate all aqueous compounds into their ions.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>CuSO4 (aq) \u2192 Cu\u00b2\u207a (aq) + SO\u2084\u00b2\u207b (aq)<\/li>\n\n\n\n<li>NaOH (aq) \u2192 Na\u207a (aq) + OH\u207b (aq)<\/li>\n\n\n\n<li>Na\u2082SO\u2084 (aq) \u2192 2Na\u207a (aq) + SO\u2084\u00b2\u207b (aq)<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 3: Cancel spectator ions.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The sulfate ions (SO\u2084\u00b2\u207b) are present on both sides of the equation, so they are spectator ions and can be canceled out.<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 4: Write the net ionic equation.<\/strong>Cu2+(aq)+2OH\u2212(aq)\u2192Cu(OH)2(s)\\text{Cu}^{2+}(aq) + 2\\text{OH}^-(aq) \\rightarrow \\text{Cu(OH)}_2(s)Cu2+(aq)+2OH\u2212(aq)\u2192Cu(OH)2\u200b(s)<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>Net Ionic Equation for CuSO4(aq) + Na2CO3(aq):<\/strong><\/h3>\n\n\n\n<p><strong>Step 1: Write the balanced molecular equation.<\/strong>CuSO4(aq)+Na2CO3(aq)\u2192CuCO3(s)+Na2SO4(aq)\\text{CuSO}_4(aq) + \\text{Na}_2\\text{CO}_3(aq) \\rightarrow \\text{CuCO}_3(s) + \\text{Na}_2\\text{SO}_4(aq)CuSO4\u200b(aq)+Na2\u200bCO3\u200b(aq)\u2192CuCO3\u200b(s)+Na2\u200bSO4\u200b(aq)<\/p>\n\n\n\n<p><strong>Step 2: Dissociate all aqueous compounds into their ions.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>CuSO\u2084 (aq) \u2192 Cu\u00b2\u207a (aq) + SO\u2084\u00b2\u207b (aq)<\/li>\n\n\n\n<li>Na\u2082CO\u2083 (aq) \u2192 2Na\u207a (aq) + CO\u2083\u00b2\u207b (aq)<\/li>\n\n\n\n<li>Na\u2082SO\u2084 (aq) \u2192 2Na\u207a (aq) + SO\u2084\u00b2\u207b (aq)<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 3: Cancel spectator ions.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The sodium ions (Na\u207a) and sulfate ions (SO\u2084\u00b2\u207b) are spectator ions and can be canceled out.<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 4: Write the net ionic equation.<\/strong>Cu2+(aq)+CO32\u2212(aq)\u2192CuCO3(s)\\text{Cu}^{2+}(aq) + \\text{CO}_3^{2-}(aq) \\rightarrow \\text{CuCO}_3(s)Cu2+(aq)+CO32\u2212\u200b(aq)\u2192CuCO3\u200b(s)<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">3. <strong>Net Ionic Equation for MnSO4(aq) + Na3PO4(aq):<\/strong><\/h3>\n\n\n\n<p><strong>Step 1: Write the balanced molecular equation.<\/strong>MnSO4(aq)+Na3PO4(aq)\u2192Mn3(PO4)2(s)+Na2SO4(aq)\\text{MnSO}_4(aq) + \\text{Na}_3\\text{PO}_4(aq) \\rightarrow \\text{Mn}_3\\text{(PO}_4)_2(s) + \\text{Na}_2\\text{SO}_4(aq)MnSO4\u200b(aq)+Na3\u200bPO4\u200b(aq)\u2192Mn3\u200b(PO4\u200b)2\u200b(s)+Na2\u200bSO4\u200b(aq)<\/p>\n\n\n\n<p><strong>Step 2: Dissociate all aqueous compounds into their ions.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>MnSO\u2084 (aq) \u2192 Mn\u00b2\u207a (aq) + SO\u2084\u00b2\u207b (aq)<\/li>\n\n\n\n<li>Na\u2083PO\u2084 (aq) \u2192 3Na\u207a (aq) + PO\u2084\u00b3\u207b (aq)<\/li>\n\n\n\n<li>Na\u2082SO\u2084 (aq) \u2192 2Na\u207a (aq) + SO\u2084\u00b2\u207b (aq)<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 3: Cancel spectator ions.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The sodium ions (Na\u207a) and sulfate ions (SO\u2084\u00b2\u207b) are spectator ions and can be canceled out.<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 4: Write the net ionic equation.<\/strong>3Mn2+(aq)+2PO43\u2212(aq)\u2192Mn3(PO4)2(s)3\\text{Mn}^{2+}(aq) + 2\\text{PO}_4^{3-}(aq) \\rightarrow \\text{Mn}_3\\text{(PO}_4)_2(s)3Mn2+(aq)+2PO43\u2212\u200b(aq)\u2192Mn3\u200b(PO4\u200b)2\u200b(s)<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>In these reactions, the spectator ions (such as Na\u207a and SO\u2084\u00b2\u207b) do not participate in the chemical change, so they are removed from the equation. The remaining ions in the reaction form precipitates, which are represented as solid compounds in the net ionic equations. This highlights the key species involved in the reaction that undergo chemical changes, leaving out the ions that remain in solution unchanged.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-719.jpeg\" alt=\"\" class=\"wp-image-245797\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Q(13) CuSO4(aq) + NaOH(aq) Write the balanced net ionic equation Q(14) CuSO4(aq) + Na2CO3(aq) Write the balanced net ionic equation Q(15) MnSO4(aq) + Na3PO4(aq) Write the balanced net ionic equation The Correct Answer and Explanation is: 1. Net Ionic Equation for CuSO4(aq) + NaOH(aq): Step 1: Write the balanced molecular equation.CuSO4(aq)+2NaOH(aq)\u2192Cu(OH)2(s)+Na2SO4(aq)\\text{CuSO}_4(aq) + 2\\text{NaOH}(aq) \\rightarrow \\text{Cu(OH)}_2(s) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-245796","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/245796","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=245796"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/245796\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=245796"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=245796"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=245796"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}