{"id":246083,"date":"2025-07-06T18:25:33","date_gmt":"2025-07-06T18:25:33","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=246083"},"modified":"2025-07-06T18:25:35","modified_gmt":"2025-07-06T18:25:35","slug":"oxygen-gas-o2g-has-a-density-of-0-00111-g-cm3-at-room-temperature-and-1-atmospheric-pressure","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/06\/oxygen-gas-o2g-has-a-density-of-0-00111-g-cm3-at-room-temperature-and-1-atmospheric-pressure\/","title":{"rendered":"\u00a0Oxygen gas (O2(g)) has a density of 0.00111 g\/cm3\u00a0at room temperature and 1 atmospheric pressure"},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">&nbsp;Oxygen gas (O2(g)) has a density of 0.00111 g\/cm3&nbsp;at room temperature and 1 atmospheric pressure<\/pre>\n\n\n\n<p>. Oxygen gas (<br>) has a density of 0.00111 g\/cm<br>at room temperature and 1 atmospheric pressure. If you had 1 gallon of pure oxygen gas, how much would that amount weigh in pounds? Hint: 1 gal = 3.78 L and 2.2 lbs = 1 kg. (13 points)<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To find the weight of 1 gallon of pure oxygen gas, we need to follow these steps:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Convert the volume of oxygen from gallons to liters<\/h3>\n\n\n\n<p>We know that 1 gallon = 3.78 liters. So, the volume of oxygen gas we are dealing with is:Volume&nbsp;in&nbsp;liters=1&nbsp;gallon\u00d73.78&nbsp;L\/gallon=3.78&nbsp;L\\text{Volume in liters} = 1 \\text{ gallon} \\times 3.78 \\text{ L\/gallon} = 3.78 \\text{ L}Volume&nbsp;in&nbsp;liters=1&nbsp;gallon\u00d73.78&nbsp;L\/gallon=3.78&nbsp;L<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Use the density of oxygen gas to calculate the mass<\/h3>\n\n\n\n<p>The density of oxygen gas is given as 0.00111 g\/cm\u00b3 at room temperature and 1 atm pressure. To proceed, we need to convert liters to cubic centimeters (cm\u00b3), since the density is given in g\/cm\u00b3.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>1 liter = 1000 cm\u00b3.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the volume of oxygen in cubic centimeters is:Volume&nbsp;in&nbsp;cm3=3.78&nbsp;L\u00d71000&nbsp;cm3\/L=3780&nbsp;cm3\\text{Volume in cm}^3 = 3.78 \\text{ L} \\times 1000 \\text{ cm}^3\/\\text{L} = 3780 \\text{ cm}^3Volume&nbsp;in&nbsp;cm3=3.78&nbsp;L\u00d71000&nbsp;cm3\/L=3780&nbsp;cm3<\/p>\n\n\n\n<p>Now, we can calculate the mass of oxygen using the formula:Mass=Density\u00d7Volume\\text{Mass} = \\text{Density} \\times \\text{Volume}Mass=Density\u00d7Volume<\/p>\n\n\n\n<p>Substituting the values:Mass=0.00111&nbsp;g\/cm3\u00d73780&nbsp;cm3=4.1978&nbsp;g\\text{Mass} = 0.00111 \\text{ g\/cm}^3 \\times 3780 \\text{ cm}^3 = 4.1978 \\text{ g}Mass=0.00111&nbsp;g\/cm3\u00d73780&nbsp;cm3=4.1978&nbsp;g<\/p>\n\n\n\n<p>So, the mass of 1 gallon of oxygen gas is approximately 4.20 grams.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Convert grams to kilograms<\/h3>\n\n\n\n<p>Since 1 kilogram = 1000 grams, we convert the mass to kilograms:Mass&nbsp;in&nbsp;kg=4.20&nbsp;g1000=0.0042&nbsp;kg\\text{Mass in kg} = \\frac{4.20 \\text{ g}}{1000} = 0.0042 \\text{ kg}Mass&nbsp;in&nbsp;kg=10004.20&nbsp;g\u200b=0.0042&nbsp;kg<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Convert kilograms to pounds<\/h3>\n\n\n\n<p>Finally, we use the conversion factor: 1 kg = 2.2 lbs.Mass&nbsp;in&nbsp;lbs=0.0042&nbsp;kg\u00d72.2&nbsp;lbs\/kg=0.00924&nbsp;lbs\\text{Mass in lbs} = 0.0042 \\text{ kg} \\times 2.2 \\text{ lbs\/kg} = 0.00924 \\text{ lbs}Mass&nbsp;in&nbsp;lbs=0.0042&nbsp;kg\u00d72.2&nbsp;lbs\/kg=0.00924&nbsp;lbs<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p>The weight of 1 gallon of pure oxygen gas is approximately <strong>0.00924 pounds<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>The process involves converting the given volume (1 gallon) to liters, converting liters to cubic centimeters, using the density to calculate the mass in grams, and then converting grams to pounds. The small mass of oxygen gas illustrates how light gases can be compared to liquids or solids.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-784.jpeg\" alt=\"\" class=\"wp-image-246084\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>&nbsp;Oxygen gas (O2(g)) has a density of 0.00111 g\/cm3&nbsp;at room temperature and 1 atmospheric pressure . Oxygen gas () has a density of 0.00111 g\/cmat room temperature and 1 atmospheric pressure. If you had 1 gallon of pure oxygen gas, how much would that amount weigh in pounds? Hint: 1 gal = 3.78 L and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-246083","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/246083","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=246083"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/246083\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=246083"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=246083"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=246083"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}