{"id":246263,"date":"2025-07-07T04:18:22","date_gmt":"2025-07-07T04:18:22","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=246263"},"modified":"2025-07-07T04:18:24","modified_gmt":"2025-07-07T04:18:24","slug":"classify-the-following-molecules-into-chiral-o-achiral-ho-h","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/07\/classify-the-following-molecules-into-chiral-o-achiral-ho-h\/","title":{"rendered":"Classify the following molecules into chiral o achiral HO H"},"content":{"rendered":"\n

Classify the following molecules into chiral o achiral HO H? H? H? H? Br ????? ???? ??? OH NH2 9. Draw an enantiomer of each of the following molecule: H2N HO H SH 10. Draw a diastereomer of each of the following molecule: Br F Br NH2 CI Br NH2 OH HO HO<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Let’s break this down into two main tasks: classification of chirality and the drawing of enantiomers and diastereomers.<\/p>\n\n\n\n

8. Classification of Chiral vs Achiral Molecules<\/h3>\n\n\n\n

A molecule is chiral<\/strong> if it has a non-superimposable mirror image, meaning it lacks a plane of symmetry. An achiral<\/strong> molecule has a plane of symmetry and is superimposable on its mirror image.<\/p>\n\n\n\n

    \n
  1. HO<\/strong> \u2013 Without more context, this is ambiguous as a single hydroxyl group attached to a molecule does not define chirality on its own.<\/li>\n\n\n\n
  2. H2<\/strong> \u2013 A molecule with only hydrogen atoms can\u2019t be classified as chiral unless part of a more complex structure.<\/li>\n\n\n\n
  3. Br<\/strong> \u2013 Similarly, the presence of a single bromine atom doesn\u2019t indicate chirality unless part of a chiral center.<\/li>\n\n\n\n
  4. OH, NH2<\/strong> \u2013 Hydroxyl and amino groups may contribute to chirality if they are part of a molecule with a chiral center. For example, if an asymmetric carbon is bonded to these groups, it may be chiral.<\/li>\n<\/ol>\n\n\n\n

    To provide specific classifications for each molecule, I would need their full structures and the number of substituents around each carbon. However, it\u2019s safe to assume that molecules with multiple substituents that are non-identical (like Br<\/strong>, OH<\/strong>, NH2<\/strong>) on a single carbon could be chiral<\/strong>.<\/p>\n\n\n\n

    9. Enantiomer Drawing<\/h3>\n\n\n\n

    Enantiomers are pairs of molecules that are non-superimposable mirror images of each other. They occur when a molecule has a chiral center.<\/p>\n\n\n\n

    Let\u2019s break down the provided molecule:<\/p>\n\n\n\n

      \n
    • H2N HO H SH<\/strong><\/li>\n<\/ul>\n\n\n\n

      This seems to be a molecule with multiple groups attached to a central carbon, such as an amino group (H2N), hydroxyl group (OH), hydrogen (H), and thiol group (SH).<\/p>\n\n\n\n

      To draw an enantiomer:<\/p>\n\n\n\n

        \n
      1. Switch the position of any two groups attached to the chiral center.\n
          \n
        • If we swap the hydrogen (H) and the thiol group (SH), the molecule becomes the enantiomer.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n

          10. Diastereomer Drawing<\/h3>\n\n\n\n

          Diastereomers are stereoisomers that are not mirror images of each other. They have different physical properties, unlike enantiomers, which have identical physical properties except for their interaction with plane-polarized light.<\/p>\n\n\n\n

          Here\u2019s the provided molecule:<\/p>\n\n\n\n

            \n
          • Br F Br NH2 CI Br NH2 OH HO HO<\/strong><\/li>\n<\/ul>\n\n\n\n

            This molecule has multiple chiral centers (indicated by the presence of different substituents on different carbons). To create a diastereomer, you would modify the configuration at one or more but not all of the chiral centers. This would lead to a molecule with a different 3D arrangement of atoms, but not a mirror image.<\/p>\n\n\n\n

            For example, if you flip the configuration at one of the chiral centers, while leaving the others unchanged, you get a diastereomer.<\/p>\n\n\n\n

            \n\n\n\n

            In summary:<\/p>\n\n\n\n

              \n
            • Chiral vs. achiral depends on whether the molecule has a chiral center (usually a carbon bonded to four different groups).<\/li>\n\n\n\n
            • Enantiomers are mirror-image molecules, while diastereomers are non-mirror-image stereoisomers.<\/li>\n<\/ul>\n\n\n\n
              \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

              Classify the following molecules into chiral o achiral HO H? H? H? H? Br ????? ???? ??? OH NH2 9. Draw an enantiomer of each of the following molecule: H2N HO H SH 10. Draw a diastereomer of each of the following molecule: Br F Br NH2 CI Br NH2 OH HO HO The Correct […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-246263","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/246263","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=246263"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/246263\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=246263"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=246263"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=246263"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}