{"id":246454,"date":"2025-07-07T07:54:21","date_gmt":"2025-07-07T07:54:21","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=246454"},"modified":"2025-07-07T07:54:23","modified_gmt":"2025-07-07T07:54:23","slug":"convert-the-following-from-m-molarity-to-i%c2%bcg-i%c2%bcl","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/07\/convert-the-following-from-m-molarity-to-i%c2%bcg-i%c2%bcl\/","title":{"rendered":"Convert the following from M (molarity) to \u00ce\u00bcg\/\u00ce\u00bcL"},"content":{"rendered":"\n

Convert the following from M (molarity) to \u00ce\u00bcg\/\u00ce\u00bcL (microgram\/microliter). Show all work for credit. MW = 37,000 g\/mole a.) 3.338 x 10^-5 M b.) 8.567 x 10^-6 M<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To convert molarity (M) to micrograms per microliter (\u03bcg\/\u03bcL), we need to follow these steps:<\/p>\n\n\n\n

Formula to use:<\/h3>\n\n\n\n

Mass (\u03bcg)=Molarity (M)\u00d7Molecular Weight (g\/mol)\u00d7106\\text{Mass (\u03bcg)} = \\text{Molarity (M)} \\times \\text{Molecular Weight (g\/mol)} \\times 10^6Mass (\u03bcg)=Molarity (M)\u00d7Molecular Weight (g\/mol)\u00d7106<\/p>\n\n\n\n

Here, we need to multiply by 10610^6106 because we’re converting from grams to micrograms (1 g = 10610^6106 \u03bcg) and from liters to microliters (1 L = 10610^6106 \u03bcL).<\/p>\n\n\n\n

Step-by-Step Solution for each part:<\/h3>\n\n\n\n

a) For 3.338\u00d710\u22125\u2009M3.338 \\times 10^{-5} \\, M3.338\u00d710\u22125M:<\/h4>\n\n\n\n
    \n
  1. Molarity (M)<\/strong> = 3.338\u00d710\u22125\u2009M3.338 \\times 10^{-5} \\, \\text{M}3.338\u00d710\u22125M<\/li>\n\n\n\n
  2. Molecular Weight (MW)<\/strong> = 37,000 g\/mol<\/li>\n\n\n\n
  3. Convert to \u03bcg\/\u03bcL: Mass\u00a0(\u03bcg\/\u03bcL)=3.338\u00d710\u22125\u2009M\u00d737,000\u2009g\/mol\u00d7106\\text{Mass (\u03bcg\/\u03bcL)} = 3.338 \\times 10^{-5} \\, \\text{M} \\times 37,000 \\, \\text{g\/mol} \\times 10^6Mass\u00a0(\u03bcg\/\u03bcL)=3.338\u00d710\u22125M\u00d737,000g\/mol\u00d7106 =3.338\u00d710\u22125\u00d737,000\u00d7106= 3.338 \\times 10^{-5} \\times 37,000 \\times 10^6=3.338\u00d710\u22125\u00d737,000\u00d7106 =123,526\u2009\u03bcg\/\u03bcL= 123,526 \\, \\mu g\/\\mu L=123,526\u03bcg\/\u03bcL<\/li>\n<\/ol>\n\n\n\n

    So, the answer for part (a) is: 123,526 \u03bcg\/\u03bcL<\/strong><\/p>\n\n\n\n

    b) For 8.567\u00d710\u22126\u2009M8.567 \\times 10^{-6} \\, M8.567\u00d710\u22126M:<\/h4>\n\n\n\n
      \n
    1. Molarity (M)<\/strong> = 8.567\u00d710\u22126\u2009M8.567 \\times 10^{-6} \\, \\text{M}8.567\u00d710\u22126M<\/li>\n\n\n\n
    2. Molecular Weight (MW)<\/strong> = 37,000 g\/mol<\/li>\n\n\n\n
    3. Convert to \u03bcg\/\u03bcL: Mass\u00a0(\u03bcg\/\u03bcL)=8.567\u00d710\u22126\u2009M\u00d737,000\u2009g\/mol\u00d7106\\text{Mass (\u03bcg\/\u03bcL)} = 8.567 \\times 10^{-6} \\, \\text{M} \\times 37,000 \\, \\text{g\/mol} \\times 10^6Mass\u00a0(\u03bcg\/\u03bcL)=8.567\u00d710\u22126M\u00d737,000g\/mol\u00d7106 =8.567\u00d710\u22126\u00d737,000\u00d7106= 8.567 \\times 10^{-6} \\times 37,000 \\times 10^6=8.567\u00d710\u22126\u00d737,000\u00d7106 =317,979\u2009\u03bcg\/\u03bcL= 317,979 \\, \\mu g\/\\mu L=317,979\u03bcg\/\u03bcL<\/li>\n<\/ol>\n\n\n\n

      So, the answer for part (b) is: 317,979 \u03bcg\/\u03bcL<\/strong><\/p>\n\n\n\n

      Explanation:<\/h3>\n\n\n\n

      To convert molarity (M, in mol\/L) to micrograms per microliter (\u03bcg\/\u03bcL), we use the formula that incorporates the molecular weight (MW) of the substance. By multiplying the molarity by the molecular weight in grams per mole and scaling up by a factor of 10610^6106 to account for the conversion from grams to micrograms and liters to microliters, we get the desired concentration in \u03bcg\/\u03bcL.<\/p>\n\n\n\n

      Thus, we end up with the two final concentrations:<\/p>\n\n\n\n

        \n
      • Part (a): 123,526 \u03bcg\/\u03bcL<\/strong><\/li>\n\n\n\n
      • Part (b): 317,979 \u03bcg\/\u03bcL<\/strong><\/li>\n<\/ul>\n\n\n\n
        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

        Convert the following from M (molarity) to \u00ce\u00bcg\/\u00ce\u00bcL (microgram\/microliter). Show all work for credit. MW = 37,000 g\/mole a.) 3.338 x 10^-5 M b.) 8.567 x 10^-6 M The Correct Answer and Explanation is: To convert molarity (M) to micrograms per microliter (\u03bcg\/\u03bcL), we need to follow these steps: Formula to use: Mass (\u03bcg)=Molarity (M)\u00d7Molecular Weight (g\/mol)\u00d7106\\text{Mass (\u03bcg)} = […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-246454","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/246454","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=246454"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/246454\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=246454"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=246454"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=246454"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}