{"id":246658,"date":"2025-07-07T10:17:30","date_gmt":"2025-07-07T10:17:30","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=246658"},"modified":"2025-07-07T10:17:33","modified_gmt":"2025-07-07T10:17:33","slug":"please-draw-and-label-the-orbital-diagram-for-chlorine-cl","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/07\/please-draw-and-label-the-orbital-diagram-for-chlorine-cl\/","title":{"rendered":"Please draw and label the orbital diagram for chlorine (Cl)"},"content":{"rendered":"\n<p>Please draw and label the orbital diagram for chlorine (Cl). In the blank provided here, please write out the electron configuration. Then upload your orbital diagram to the assignments folder. Make sure your answer is clearly labeled and legible<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-263.png\" alt=\"\" class=\"wp-image-246659\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Of course. Here is the correct answer and explanation for the assignment.<\/p>\n\n\n\n<p><strong>Answer<\/strong><\/p>\n\n\n\n<p><strong>Electron Configuration for Chlorine (Cl):<\/strong><br>1s\u00b22s\u00b22p\u20763s\u00b23p\u2075<\/p>\n\n\n\n<p><strong>Orbital Diagram for Chlorine (Cl):<\/strong><br>(This is a text representation of the drawing you would create.)<\/p>\n\n\n\n<p><strong>1s:<\/strong>&nbsp;[\u2191\u2193]<br><strong>2s:<\/strong>&nbsp;[\u2191\u2193]<br><strong>2p:<\/strong>&nbsp;[\u2191\u2193]&nbsp;[\u2191\u2193]&nbsp;[\u2191\u2193]<br><strong>3s:<\/strong>&nbsp;[\u2191\u2193]<br><strong>3p:<\/strong>&nbsp;[\u2191\u2193]&nbsp;[\u2191\u2193]&nbsp;[\u2191]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p>To determine the electron configuration and orbital diagram for chlorine (Cl), we must first identify its atomic number from the periodic table, which is 17. This number indicates that a neutral chlorine atom contains 17 protons and, therefore, 17 electrons that need to be placed into atomic orbitals.<\/p>\n\n\n\n<p><strong>Electron Configuration:<\/strong><\/p>\n\n\n\n<p>The electron configuration describes the distribution of these 17 electrons among the various atomic orbitals. We follow the Aufbau principle, which states that electrons fill the lowest energy orbitals first. The order of filling is 1s, 2s, 2p, 3s, 3p, and so on.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>The\u00a01s\u00a0orbital can hold 2 electrons:\u00a01s\u00b2. (15 electrons remaining)<\/li>\n\n\n\n<li>The\u00a02s\u00a0orbital can hold 2 electrons:\u00a02s\u00b2. (13 electrons remaining)<\/li>\n\n\n\n<li>The\u00a02p\u00a0subshell, consisting of three orbitals, can hold a total of 6 electrons:\u00a02p\u2076. (7 electrons remaining)<\/li>\n\n\n\n<li>The\u00a03s\u00a0orbital can hold 2 electrons:\u00a03s\u00b2. (5 electrons remaining)<\/li>\n\n\n\n<li>Finally, the remaining 5 electrons go into the\u00a03p\u00a0subshell:\u00a03p\u2075.<\/li>\n<\/ol>\n\n\n\n<p>Combining these gives the full electron configuration for chlorine:&nbsp;<strong>1s\u00b22s\u00b22p\u20763s\u00b23p\u2075<\/strong>. Chlorine\u2019s outermost energy level is n=3, which contains 7 valence electrons (3s\u00b23p\u2075), defining it as a halogen.<\/p>\n\n\n\n<p><strong>Orbital Diagram:<\/strong><\/p>\n\n\n\n<p>The orbital diagram provides a more detailed visual representation, showing the individual orbitals and the spin of the electrons within them. Each box represents an orbital, and arrows represent electrons.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Pauli Exclusion Principle:<\/strong>\u00a0An orbital can hold a maximum of two electrons, and they must have opposite spins (represented by an up arrow\u00a0\u2191\u00a0and a down arrow\u00a0\u2193).<\/li>\n\n\n\n<li><strong>Hund&#8217;s Rule:<\/strong>\u00a0When filling orbitals of equal energy (like the three\u00a0p\u00a0orbitals), electrons are placed one at a time in each orbital with parallel spins before any orbital is doubly occupied.<\/li>\n<\/ul>\n\n\n\n<p>For chlorine&#8217;s 17 electrons:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The\u00a01s,\u00a02s,\u00a02p, and\u00a03s\u00a0orbitals are all completely filled with paired electrons (\u2191\u2193).<\/li>\n\n\n\n<li>The\u00a03p\u00a0subshell has 5 electrons. According to Hund&#8217;s rule, we first place one electron in each of the three\u00a03p\u00a0orbitals ([\u2191] [\u2191] [\u2191]). Then, we go back and pair up the first two orbitals with the remaining two electrons ([\u2191\u2193] [\u2191\u2193] [\u2191]). This results in two of the\u00a03p\u00a0orbitals being full and one being half-filled. This single unpaired electron is what makes the chlorine atom highly reactive, as it readily accepts one more electron to achieve a stable, filled\u00a03p\u00a0subshell.<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-910.jpeg\" alt=\"\" class=\"wp-image-246660\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Please draw and label the orbital diagram for chlorine (Cl). In the blank provided here, please write out the electron configuration. Then upload your orbital diagram to the assignments folder. Make sure your answer is clearly labeled and legible The Correct Answer and Explanation is: Of course. Here is the correct answer and explanation for [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-246658","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/246658","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=246658"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/246658\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=246658"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=246658"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=246658"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}