{"id":246699,"date":"2025-07-07T10:50:10","date_gmt":"2025-07-07T10:50:10","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=246699"},"modified":"2025-07-07T10:50:12","modified_gmt":"2025-07-07T10:50:12","slug":"write-and-balance-the-equation-for-the-decomposition-of-aluminum-chloride-into-its-elements","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/07\/write-and-balance-the-equation-for-the-decomposition-of-aluminum-chloride-into-its-elements\/","title":{"rendered":"Write and balance the equation for the decomposition of aluminum chloride into its elements"},"content":{"rendered":"\n<p>Write and balance the equation for the decomposition of aluminum chloride into its elements. phase symbols are optional.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The decomposition of aluminum chloride (AlCl\u2083) into its elements is a chemical reaction where aluminum chloride breaks down into its constituent elements: aluminum (Al) and chlorine (Cl\u2082).<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Unbalanced equation:<\/h3>\n\n\n\n<p>AlCl3\u2192Al+Cl2\\text{AlCl}_3 \\rightarrow \\text{Al} + \\text{Cl}_2AlCl3\u200b\u2192Al+Cl2\u200b<\/p>\n\n\n\n<p>Now, let&#8217;s balance this equation.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Balancing aluminum (Al):<\/strong><br>On the left side, we have one aluminum atom in AlCl\u2083, and on the right side, aluminum appears as a free element (Al). So, the number of aluminum atoms is already balanced.<\/li>\n\n\n\n<li><strong>Balancing chlorine (Cl):<\/strong><br>On the left side, we have three chlorine atoms in AlCl\u2083. However, chlorine (Cl) on the right side appears as Cl\u2082, meaning two chlorine atoms per molecule of chlorine gas. Therefore, we need to balance chlorine by placing a coefficient of 3\/2 in front of Cl\u2082 to match the three chlorine atoms on the left side. AlCl3\u2192Al+32Cl2\\text{AlCl}_3 \\rightarrow \\text{Al} + \\frac{3}{2} \\text{Cl}_2AlCl3\u200b\u2192Al+23\u200bCl2\u200b<\/li>\n\n\n\n<li><strong>Removing the fraction:<\/strong><br>To avoid fractions, we multiply the entire equation by 2. This gives us: 2AlCl3\u21922Al+3Cl22 \\text{AlCl}_3 \\rightarrow 2 \\text{Al} + 3 \\text{Cl}_22AlCl3\u200b\u21922Al+3Cl2\u200b<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Final balanced equation:<\/h3>\n\n\n\n<p>2AlCl3\u21922Al+3Cl22 \\text{AlCl}_3 \\rightarrow 2 \\text{Al} + 3 \\text{Cl}_22AlCl3\u200b\u21922Al+3Cl2\u200b<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The reaction is a decomposition reaction, where a compound breaks down into simpler substances.<\/li>\n\n\n\n<li>Aluminum chloride (AlCl\u2083) is composed of aluminum and chlorine. When it decomposes, it produces aluminum (Al) and chlorine gas (Cl\u2082).<\/li>\n\n\n\n<li>The aluminum atoms on the left (in AlCl\u2083) are balanced by the aluminum atoms on the right side of the equation.<\/li>\n\n\n\n<li>Chlorine is more complex because it naturally forms a diatomic molecule (Cl\u2082). Hence, the number of chlorine atoms on both sides must be balanced by adjusting the coefficient of chlorine gas.<\/li>\n\n\n\n<li>The final balanced equation shows that for every 2 molecules of AlCl\u2083, you get 2 atoms of aluminum and 3 molecules of chlorine gas.<\/li>\n<\/ul>\n\n\n\n<p>This decomposition reaction typically requires energy, such as heat or electrolysis, to break the ionic bonds in AlCl\u2083.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-920.jpeg\" alt=\"\" class=\"wp-image-246700\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write and balance the equation for the decomposition of aluminum chloride into its elements. phase symbols are optional. The Correct Answer and Explanation is: The decomposition of aluminum chloride (AlCl\u2083) into its elements is a chemical reaction where aluminum chloride breaks down into its constituent elements: aluminum (Al) and chlorine (Cl\u2082). Unbalanced equation: AlCl3\u2192Al+Cl2\\text{AlCl}_3 \\rightarrow [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-246699","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/246699","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=246699"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/246699\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=246699"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=246699"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=246699"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}