{"id":247092,"date":"2025-07-07T14:42:12","date_gmt":"2025-07-07T14:42:12","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=247092"},"modified":"2025-07-07T14:42:14","modified_gmt":"2025-07-07T14:42:14","slug":"what-is-the-shape-of-co3-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/07\/what-is-the-shape-of-co3-2\/","title":{"rendered":"What is the shape of CO3-2"},"content":{"rendered":"\n<p>What is the shape of CO3-2 <\/p>\n\n\n\n<p>a) linear b) tetrahedral c) bent d) trigonal pyramidal e) trigonal planar<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>e) trigonal planar<\/strong>.<\/p>\n\n\n\n<p>The carbonate ion (CO\u2083\u00b2\u207b) consists of a central carbon atom bonded to three oxygen atoms. To determine its shape, we need to consider the molecular geometry based on the number of bonding and non-bonding electron pairs around the central carbon atom.<\/p>\n\n\n\n<p>First, the carbon atom forms three single bonds with three oxygen atoms. Since the overall charge on the ion is -2, there are two additional electrons that contribute to the negative charge. These extra electrons do not belong to a single oxygen atom but are shared between all three oxygens, creating a resonance structure. This means the electron distribution is not localized but is delocalized across all three oxygen atoms, resulting in equal bond lengths between the carbon and each oxygen.<\/p>\n\n\n\n<p>Next, according to the VSEPR (Valence Shell Electron Pair Repulsion) theory, the geometry of the molecule is determined by the repulsion between electron pairs. In CO\u2083\u00b2\u207b, there are three bonding pairs of electrons around the central carbon atom and no lone pairs of electrons. The ideal arrangement of these three bonding pairs is in a plane, forming angles of 120\u00b0 between them. This geometry is characteristic of a <strong>trigonal planar<\/strong> shape.<\/p>\n\n\n\n<p>The delocalization of electrons in the resonance structure contributes to the stability and the planar symmetry of the molecule. Therefore, the correct molecular shape of the carbonate ion is trigonal planar, not any of the other options such as linear, bent, or trigonal pyramidal.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the shape of CO3-2 a) linear b) tetrahedral c) bent d) trigonal pyramidal e) trigonal planar The correct answer and explanation is: The correct answer is e) trigonal planar. The carbonate ion (CO\u2083\u00b2\u207b) consists of a central carbon atom bonded to three oxygen atoms. To determine its shape, we need to consider the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-247092","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/247092","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=247092"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/247092\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=247092"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=247092"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=247092"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}