{"id":247147,"date":"2025-07-07T15:01:09","date_gmt":"2025-07-07T15:01:09","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=247147"},"modified":"2025-07-07T15:01:16","modified_gmt":"2025-07-07T15:01:16","slug":"write-the-complete-electron-configuration-for-the-beryllium-atom","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/07\/write-the-complete-electron-configuration-for-the-beryllium-atom\/","title":{"rendered":"Write the complete electron configuration for the beryllium atom."},"content":{"rendered":"\n

Write the complete electron configuration for the beryllium atom. Using the noble gas abbreviation, rewrite the electron configuration for the beryllium atom. [He] 2s2<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Of course. Based on the provided image and the principles of chemistry, here are the correct answers and a detailed explanation.<\/p>\n\n\n\n

Correct Answer for “Write the complete electron configuration for the beryllium atom”:<\/strong>
1s\u00b22s\u00b2<\/p>\n\n\n\n

Correct Answer for “Using the noble gas abbreviation rewrite the electron configuration for the beryllium atom”:<\/strong>
[He]2s\u00b2<\/p>\n\n\n\n

\n\n\n\n

Explanation<\/h3>\n\n\n\n

To determine the electron configuration of an atom, we must first identify how many electrons it has and then fill the atomic orbitals according to a set of rules.<\/p>\n\n\n\n

1. Finding the Number of Electrons<\/strong>
Beryllium (Be) is element number 4 on the periodic table. Its atomic number is 4, which means a neutral beryllium atom has 4 protons and 4 electrons<\/strong>. Our goal is to assign these 4 electrons to specific orbitals.<\/p>\n\n\n\n

2. The Complete Electron Configuration<\/strong>
The complete, or full, electron configuration lists all the filled orbitals starting from the lowest energy level. We follow the Aufbau principle<\/strong>, which states that electrons fill orbitals in order of increasing energy (1s, then 2s, then 2p, etc.).<\/p>\n\n\n\n

    \n
  • The first two electrons fill the lowest energy orbital, the\u00a01s\u00a0orbital. This is written as\u00a01s\u00b2<\/strong>. The superscript ‘2’ indicates two electrons are in that orbital.<\/li>\n\n\n\n
  • We have two electrons remaining (4 total – 2 used). These next two electrons go into the next lowest energy orbital, which is the\u00a02s\u00a0orbital. This is written as\u00a02s\u00b2<\/strong>.<\/li>\n<\/ul>\n\n\n\n

    Combining these gives the complete electron configuration for beryllium: 1s\u00b22s\u00b2<\/strong>.<\/p>\n\n\n\n

    In the image provided, the answer [He]2s\u00b2 was marked incorrect for this question because it is the abbreviated<\/em> form, not the complete<\/em> one the question asked for.<\/p>\n\n\n\n

    3. The Noble Gas Abbreviation<\/strong>
    The noble gas configuration is a convenient shorthand. It uses the symbol of the noble gas from the previous period to represent the “core” electrons.<\/p>\n\n\n\n

      \n
    • Beryllium is in Period 2 of the periodic table. The noble gas at the end of the previous period (Period 1) is\u00a0Helium (He)<\/strong>.<\/li>\n\n\n\n
    • The electron configuration of Helium is\u00a01s\u00b2.<\/li>\n\n\n\n
    • We can replace the\u00a01s\u00b2\u00a0part of beryllium’s full configuration (1s\u00b22s\u00b2) with the symbol\u00a0[He]\u00a0in brackets.<\/li>\n\n\n\n
    • We then write the remaining electrons, which are the valence electrons. For beryllium, this is\u00a02s\u00b2.<\/li>\n<\/ul>\n\n\n\n

      This gives the noble gas abbreviation for beryllium: [He]2s\u00b2<\/strong>.<\/p>\n\n\n\n

      The answer [Ar]3d\u00b9\u20704s\u00b24p\u2075 shown in the image is the configuration for Bromine (Br), a much larger atom with 35 electrons, and is therefore incorrect for beryllium.<\/p>\n\n\n\n

      \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

      Write the complete electron configuration for the beryllium atom. Using the noble gas abbreviation, rewrite the electron configuration for the beryllium atom. [He] 2s2 The Correct Answer and Explanation is: Of course. Based on the provided image and the principles of chemistry, here are the correct answers and a detailed explanation. Correct Answer for “Write […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-247147","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/247147","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=247147"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/247147\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=247147"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=247147"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=247147"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}