{"id":247329,"date":"2025-07-07T15:58:07","date_gmt":"2025-07-07T15:58:07","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=247329"},"modified":"2025-07-07T15:58:08","modified_gmt":"2025-07-07T15:58:08","slug":"what-is-the-oxidation-number-of-chromium-in-the-chromate-ion-cro42","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/07\/what-is-the-oxidation-number-of-chromium-in-the-chromate-ion-cro42\/","title":{"rendered":"What is the oxidation number of chromium in the chromate ion, CrO42-"},"content":{"rendered":"\n<p>What is the oxidation number of chromium in the chromate ion, CrO42-<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The oxidation number of chromium in the chromate ion (CrO\u2084\u00b2\u207b) is +6.<\/p>\n\n\n\n<p>To determine the oxidation number of chromium in CrO\u2084\u00b2\u207b, we need to apply the rules for oxidation numbers.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Oxidation number of oxygen<\/strong>: In most compounds, oxygen has an oxidation number of -2. Since there are four oxygen atoms in the chromate ion, the total oxidation number contributed by oxygen is 4 \u00d7 (-2) = -8.<\/li>\n\n\n\n<li><strong>Charge on the ion<\/strong>: The chromate ion (CrO\u2084\u00b2\u207b) has a total charge of -2. This means that the sum of the oxidation numbers of all elements in the ion must equal -2.<\/li>\n\n\n\n<li><strong>Oxidation number of chromium<\/strong>: Let the oxidation number of chromium be x. The sum of the oxidation numbers must equal the charge of the ion. Therefore, we can write the equation:<\/li>\n<\/ol>\n\n\n\n<p>x+(\u22128)=\u22122x + (-8) = -2<\/p>\n\n\n\n<p>Solving for x: x\u22128=\u22122x &#8211; 8 = -2 x=+6x = +6<\/p>\n\n\n\n<p>Thus, the oxidation number of chromium in CrO\u2084\u00b2\u207b is +6.<\/p>\n\n\n\n<p>This oxidation state indicates that chromium is in a highly oxidized form. Chromates are often used in various chemical processes, including as oxidizing agents. The +6 oxidation state of chromium is also a key feature in the chemistry of chromium compounds, particularly in its toxicological impact, as hexavalent chromium compounds are more dangerous compared to other chromium oxidation states.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the oxidation number of chromium in the chromate ion, CrO42- The correct answer and explanation is: The oxidation number of chromium in the chromate ion (CrO\u2084\u00b2\u207b) is +6. To determine the oxidation number of chromium in CrO\u2084\u00b2\u207b, we need to apply the rules for oxidation numbers. x+(\u22128)=\u22122x + (-8) = -2 Solving for [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-247329","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/247329","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=247329"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/247329\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=247329"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=247329"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=247329"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}