{"id":248318,"date":"2025-07-08T09:55:34","date_gmt":"2025-07-08T09:55:34","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=248318"},"modified":"2025-07-08T09:55:36","modified_gmt":"2025-07-08T09:55:36","slug":"what-is-the-molecular-shape-of-h2o","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/08\/what-is-the-molecular-shape-of-h2o\/","title":{"rendered":"What is the molecular shape of H2O"},"content":{"rendered":"\n

What is the molecular shape of H2O? A) tetrahedral B) linear C) T-shaped D) bent E) trigonal pyramidal<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The correct molecular shape of H2O (water) is D) bent<\/strong>.<\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

Water (H2O) has a bent<\/strong> molecular geometry due to the way its atoms are arranged and the electron repulsion between the lone pairs on the oxygen atom. Here\u2019s a detailed breakdown:<\/p>\n\n\n\n

    \n
  1. Electron Domain and Lewis Structure<\/strong>:\n
      \n
    • Oxygen has 6 valence electrons, and each hydrogen atom contributes 1 electron. The molecule forms two single bonds between oxygen and hydrogen.<\/li>\n\n\n\n
    • Oxygen also has two lone pairs of electrons, which occupy more space around the oxygen atom.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • VSEPR Theory<\/strong> (Valence Shell Electron Pair Repulsion Theory):\n
        \n
      • According to VSEPR theory, electron pairs around an atom arrange themselves to minimize repulsion. In H2O, there are 4 electron domains<\/strong> around the oxygen atom: two bonding pairs (O-H bonds) and two lone pairs.<\/li>\n\n\n\n
      • These 4 electron pairs would ideally form a tetrahedral<\/strong> arrangement in space. However, because lone pairs take up more space than bonding pairs, they push the bonding pairs closer together.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
      • Molecular Shape<\/strong>:\n
          \n
        • The result of this repulsion is that the bonding pairs of electrons are pushed into a bent<\/strong> shape rather than forming a linear or tetrahedral structure.<\/li>\n\n\n\n
        • The bond angle between the two hydrogen atoms in H2O is approximately 104.5\u00b0<\/strong>, which is less than the 109.5\u00b0 bond angle seen in perfect tetrahedral geometry due to the presence of lone pairs.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n

          In summary, the bent<\/strong> shape arises from the combination of bonding and lone pairs, creating a molecular structure where the angle between the hydrogen-oxygen-hydrogen bond is less than 109.5\u00b0, and the molecule adopts a “V”-shaped or bent geometry.<\/p>\n\n\n\n

          \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

          What is the molecular shape of H2O? A) tetrahedral B) linear C) T-shaped D) bent E) trigonal pyramidal The Correct Answer and Explanation is: The correct molecular shape of H2O (water) is D) bent. Explanation: Water (H2O) has a bent molecular geometry due to the way its atoms are arranged and the electron repulsion between […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-248318","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/248318","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=248318"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/248318\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=248318"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=248318"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=248318"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}