{"id":248437,"date":"2025-07-08T11:12:39","date_gmt":"2025-07-08T11:12:39","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=248437"},"modified":"2025-07-08T11:12:41","modified_gmt":"2025-07-08T11:12:41","slug":"what-is-the-formula-for-copperii-phosphate-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/08\/what-is-the-formula-for-copperii-phosphate-2\/","title":{"rendered":"What is the formula for copper(II) phosphate"},"content":{"rendered":"\n

What is the formula for copper(II) phosphate? Capitalization and punctuation count. Formula: Cu3(PO4)2. How many atoms of phosphorus are in 3.70 mol of copper(II) phosphate? Number of P atoms: 229.4.<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The formula for copper(II) phosphate is Cu\u2083(PO\u2084)\u2082<\/strong>.<\/p>\n\n\n\n

To find the number of phosphorus (P) atoms in 3.70 mol of copper(II) phosphate, follow these steps:<\/p>\n\n\n\n

    \n
  1. Identify the number of phosphorus atoms in one formula unit of Cu\u2083(PO\u2084)\u2082:<\/strong>\n
      \n
    • In Cu\u2083(PO\u2084)\u2082, there are two phosphate ions (PO\u2084)\u00b2\u207b.<\/li>\n\n\n\n
    • Each phosphate ion contains one phosphorus (P) atom.<\/li>\n\n\n\n
    • Therefore, for each formula unit of Cu\u2083(PO\u2084)\u2082, there are 2 phosphorus (P) atoms.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • Calculate the number of phosphorus atoms in 3.70 mol of copper(II) phosphate:<\/strong>\n
        \n
      • 1 mol of Cu\u2083(PO\u2084)\u2082 contains 2 mol of phosphorus atoms because there are two P atoms per formula unit.<\/li>\n\n\n\n
      • Therefore, 3.70 mol of Cu\u2083(PO\u2084)\u2082 contains 3.70 \u00d7 2 = 7.40 mol of phosphorus atoms.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
      • Convert moles of phosphorus atoms to the number of atoms:<\/strong>\n
          \n
        • Avogadro’s number (6.022 \u00d7 10\u00b2\u00b3) tells us how many atoms are in one mole of a substance.<\/li>\n\n\n\n
        • So, the number of phosphorus atoms in 7.40 mol of phosphorus is: Number\u00a0of\u00a0P\u00a0atoms=7.40\u00a0mol\u00d76.022\u00d71023\u00a0atoms\/mol\\text{Number of P atoms} = 7.40 \\text{ mol} \\times 6.022 \\times 10^{23} \\text{ atoms\/mol}Number\u00a0of\u00a0P\u00a0atoms=7.40\u00a0mol\u00d76.022\u00d71023\u00a0atoms\/mol =4.46\u00d71024\u00a0phosphorus\u00a0atoms.= 4.46 \\times 10^{24} \\text{ phosphorus atoms}.=4.46\u00d71024\u00a0phosphorus\u00a0atoms.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
        • Conclusion:<\/strong>\n
            \n
          • The number of phosphorus atoms in 3.70 mol of copper(II) phosphate is 4.46 \u00d7 10\u00b2\u2074<\/strong>.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n
            \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

            What is the formula for copper(II) phosphate? Capitalization and punctuation count. Formula: Cu3(PO4)2. How many atoms of phosphorus are in 3.70 mol of copper(II) phosphate? Number of P atoms: 229.4. The Correct Answer and Explanation is: The formula for copper(II) phosphate is Cu\u2083(PO\u2084)\u2082. To find the number of phosphorus (P) atoms in 3.70 mol of […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-248437","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/248437","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=248437"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/248437\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=248437"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=248437"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=248437"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}