{"id":248478,"date":"2025-07-08T12:04:36","date_gmt":"2025-07-08T12:04:36","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=248478"},"modified":"2025-07-08T12:04:38","modified_gmt":"2025-07-08T12:04:38","slug":"what-is-the-oxidation-state-of-cl-in-each-ion","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/08\/what-is-the-oxidation-state-of-cl-in-each-ion\/","title":{"rendered":"What is the oxidation state of Cl in each ion"},"content":{"rendered":"\n<p>What is the oxidation state of Cl in each ion? a. ClO- b. ClO2- c. ClO3- d. ClO4-<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let&#8217;s go through the oxidation states of chlorine in each ion one by one:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">a. <strong>ClO\u207b (Hypochlorite ion)<\/strong><\/h3>\n\n\n\n<p>In the hypochlorite ion (ClO\u207b), oxygen has an oxidation state of -2. Since the ion has an overall charge of -1, the sum of the oxidation states of chlorine and oxygen must equal -1.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Let the oxidation state of chlorine be x.<\/li>\n\n\n\n<li>The total charge equation will be:<br>x + (-2) = -1<br>x &#8211; 2 = -1<br>x = +1<\/li>\n<\/ul>\n\n\n\n<p>So, the oxidation state of chlorine in ClO\u207b is <strong>+1<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">b. <strong>ClO\u2082\u207b (Chlorite ion)<\/strong><\/h3>\n\n\n\n<p>In the chlorite ion (ClO\u2082\u207b), oxygen has an oxidation state of -2. With a charge of -1, the sum of the oxidation states of chlorine and the two oxygens must equal -1.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Let the oxidation state of chlorine be x.<\/li>\n\n\n\n<li>The total charge equation will be:<br>x + 2(-2) = -1<br>x &#8211; 4 = -1<br>x = +3<\/li>\n<\/ul>\n\n\n\n<p>So, the oxidation state of chlorine in ClO\u2082\u207b is <strong>+3<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">c. <strong>ClO\u2083\u207b (Chlorate ion)<\/strong><\/h3>\n\n\n\n<p>In the chlorate ion (ClO\u2083\u207b), oxygen has an oxidation state of -2. With a charge of -1, the sum of the oxidation states of chlorine and the three oxygens must equal -1.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Let the oxidation state of chlorine be x.<\/li>\n\n\n\n<li>The total charge equation will be:<br>x + 3(-2) = -1<br>x &#8211; 6 = -1<br>x = +5<\/li>\n<\/ul>\n\n\n\n<p>So, the oxidation state of chlorine in ClO\u2083\u207b is <strong>+5<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">d. <strong>ClO\u2084\u207b (Perchlorate ion)<\/strong><\/h3>\n\n\n\n<p>In the perchlorate ion (ClO\u2084\u207b), oxygen again has an oxidation state of -2. With a charge of -1, the sum of the oxidation states of chlorine and the four oxygens must equal -1.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Let the oxidation state of chlorine be x.<\/li>\n\n\n\n<li>The total charge equation will be:<br>x + 4(-2) = -1<br>x &#8211; 8 = -1<br>x = +7<\/li>\n<\/ul>\n\n\n\n<p>So, the oxidation state of chlorine in ClO\u2084\u207b is <strong>+7<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>a. <strong>ClO\u207b<\/strong>: Oxidation state of Cl is <strong>+1<\/strong>.<\/li>\n\n\n\n<li>b. <strong>ClO\u2082\u207b<\/strong>: Oxidation state of Cl is <strong>+3<\/strong>.<\/li>\n\n\n\n<li>c. <strong>ClO\u2083\u207b<\/strong>: Oxidation state of Cl is <strong>+5<\/strong>.<\/li>\n\n\n\n<li>d. <strong>ClO\u2084\u207b<\/strong>: Oxidation state of Cl is <strong>+7<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>Each of these species has chlorine in different oxidation states based on the number of oxygen atoms it is bonded to, which influences the overall charge distribution.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-242.jpeg\" alt=\"\" class=\"wp-image-248479\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the oxidation state of Cl in each ion? a. ClO- b. ClO2- c. ClO3- d. ClO4- The Correct Answer and Explanation is: Let&#8217;s go through the oxidation states of chlorine in each ion one by one: a. ClO\u207b (Hypochlorite ion) In the hypochlorite ion (ClO\u207b), oxygen has an oxidation state of -2. Since [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-248478","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/248478","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=248478"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/248478\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=248478"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=248478"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=248478"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}