{"id":248647,"date":"2025-07-08T14:39:20","date_gmt":"2025-07-08T14:39:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=248647"},"modified":"2025-07-08T14:39:22","modified_gmt":"2025-07-08T14:39:22","slug":"in-the-following-equation-identify-the-acids-bases-and-conjugate-pairs","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/08\/in-the-following-equation-identify-the-acids-bases-and-conjugate-pairs\/","title":{"rendered":"In the following equation, identify the acids, bases, and conjugate pairs."},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">In the following equation, identify the acids, bases, and conjugate pairs. NH4 + + BrO3 ? ? NH3 + HBrO3 (a) What is the acid? (b) What is its conjugate base? (c) What is the base? d) What is its conjugate acid?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Let&#8217;s break down the given equation:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>NH\u2084\u207a + BrO\u2083\u207b \u21cc NH\u2083 + HBrO\u2083<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This is a typical acid-base reaction in water, and it follows the Bronsted-Lowry acid-base theory. According to this theory:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>An acid<\/strong> is a proton (H\u207a) donor.<\/li>\n\n\n\n<li><strong>A base<\/strong> is a proton (H\u207a) acceptor.<\/li>\n\n\n\n<li><strong>Conjugate acid<\/strong> is what the base becomes after accepting a proton.<\/li>\n\n\n\n<li><strong>Conjugate base<\/strong> is what the acid becomes after donating a proton.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Now, let\u2019s analyze each part of the equation:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(a) What is the acid?<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The acid is <strong>NH\u2084\u207a (ammonium ion)<\/strong>.<br>Why? NH\u2084\u207a donates a proton (H\u207a) to become <strong>NH\u2083 (ammonia)<\/strong>. The proton is transferred from NH\u2084\u207a to BrO\u2083\u207b, which makes NH\u2084\u207a the acid.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(b) What is its conjugate base?<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The conjugate base of NH\u2084\u207a is <strong>NH\u2083 (ammonia)<\/strong>.<br>When NH\u2084\u207a donates a proton (H\u207a), it becomes NH\u2083, which is its conjugate base. In essence, NH\u2083 is the species that results after NH\u2084\u207a has given up its proton.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(c) What is the base?<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The base in this reaction is <strong>BrO\u2083\u207b (bromate ion)<\/strong>.<br>Why? BrO\u2083\u207b accepts a proton (H\u207a) to become <strong>HBrO\u2083 (bromous acid)<\/strong>. Therefore, BrO\u2083\u207b is the base since it takes in a proton.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(d) What is its conjugate acid?<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The conjugate acid of BrO\u2083\u207b is <strong>HBrO\u2083 (bromous acid)<\/strong>.<br>Once BrO\u2083\u207b accepts a proton, it becomes HBrO\u2083, which is its conjugate acid. The species formed after the base accepts a proton is always its conjugate acid.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>(a) The <strong>acid<\/strong> is <strong>NH\u2084\u207a<\/strong>.<\/li>\n\n\n\n<li>(b) Its <strong>conjugate base<\/strong> is <strong>NH\u2083<\/strong>.<\/li>\n\n\n\n<li>(c) The <strong>base<\/strong> is <strong>BrO\u2083\u207b<\/strong>.<\/li>\n\n\n\n<li>(d) Its <strong>conjugate acid<\/strong> is <strong>HBrO\u2083<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This reaction demonstrates how acids and bases interact through proton transfer, resulting in conjugate acid-base pairs.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-283.jpeg\" alt=\"\" class=\"wp-image-248648\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>In the following equation, identify the acids, bases, and conjugate pairs. NH4 + + BrO3 ? ? NH3 + HBrO3 (a) What is the acid? (b) What is its conjugate base? (c) What is the base? d) What is its conjugate acid? The Correct Answer and Explanation is: Let&#8217;s break down the given equation: NH\u2084\u207a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-248647","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/248647","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=248647"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/248647\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=248647"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=248647"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=248647"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}