{"id":248928,"date":"2025-07-08T20:07:44","date_gmt":"2025-07-08T20:07:44","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=248928"},"modified":"2025-07-08T20:07:46","modified_gmt":"2025-07-08T20:07:46","slug":"for-the-reaction-nh3-no-%e2%86%92-n2-h2o-identify-the-reactants-products-and-their-coefficients-once-the-equation-is-balanced","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/08\/for-the-reaction-nh3-no-%e2%86%92-n2-h2o-identify-the-reactants-products-and-their-coefficients-once-the-equation-is-balanced\/","title":{"rendered":"For the reaction NH3 + NO \u2192 N2 + H2O, identify the reactants, products, and their coefficients once the equation is balanced."},"content":{"rendered":"\n<p>For the reaction NH3 + NO \u2192 N2 + H2O, identify the reactants, products, and their coefficients once the equation is balanced. (3 points) Group of answer choices Reactants: 2NH3 and 2NO; products: 2N2 and 3H2O Products: 2NH3 and 3NO; reactants: 2N2 and 3H2O Reactants: 4NH3 and 6NO; products: 5N2 and 6H2O Products: 4NH3 and 2NO; reactants: 3N2 and 6H2O<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The given chemical reaction is:<\/p>\n\n\n\n<p>NH3+NO\u2192N2+H2O\\text{NH}_3 + \\text{NO} \\rightarrow \\text{N}_2 + \\text{H}_2\\text{O}NH3\u200b+NO\u2192N2\u200b+H2\u200bO<\/p>\n\n\n\n<p>We need to balance the equation and identify the reactants, products, and their coefficients.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Write the unbalanced equation<\/h3>\n\n\n\n<p>The unbalanced equation is:<br>NH3+NO\u2192N2+H2O\\text{NH}_3 + \\text{NO} \\rightarrow \\text{N}_2 + \\text{H}_2\\text{O}NH3\u200b+NO\u2192N2\u200b+H2\u200bO<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Balance nitrogen atoms<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>On the left side, there is 1 nitrogen atom in NH\u2083 and 1 nitrogen atom in NO, so there are a total of 2 nitrogen atoms on the left.<\/li>\n\n\n\n<li>On the right side, N\u2082 has 2 nitrogen atoms. So, we balance the nitrogen atoms by placing a coefficient of 1 in front of N\u2082: NH3+NO\u21921N2+H2O\\text{NH}_3 + \\text{NO} \\rightarrow 1\\text{N}_2 + \\text{H}_2\\text{O}NH3\u200b+NO\u21921N2\u200b+H2\u200bO<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Balance hydrogen atoms<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>On the left, NH\u2083 has 3 hydrogen atoms, so we have a total of 3 hydrogen atoms from NH\u2083.<\/li>\n\n\n\n<li>On the right, H\u2082O has 2 hydrogen atoms. To balance the hydrogen atoms, place a coefficient of 3\/2 in front of H\u2082O: NH3+NO\u21921N2+32H2O\\text{NH}_3 + \\text{NO} \\rightarrow 1\\text{N}_2 + \\frac{3}{2}\\text{H}_2\\text{O}NH3\u200b+NO\u21921N2\u200b+23\u200bH2\u200bO<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Balance oxygen atoms<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>On the left, NO has 1 oxygen atom, so we need 1 oxygen atom on the right side.<\/li>\n\n\n\n<li>On the right side, H\u2082O has 1 oxygen atom, so we already have 1 oxygen atom in H\u2082O.<\/li>\n<\/ul>\n\n\n\n<p>Thus, oxygen is balanced, but we need to eliminate the fraction in front of H\u2082O.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 5: Eliminate fractions by multiplying through by 2<\/h3>\n\n\n\n<p>Multiply all the coefficients by 2 to eliminate the fraction:<\/p>\n\n\n\n<p>2NH3+2NO\u21922N2+3H2O2\\text{NH}_3 + 2\\text{NO} \\rightarrow 2\\text{N}_2 + 3\\text{H}_2\\text{O}2NH3\u200b+2NO\u21922N2\u200b+3H2\u200bO<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Balanced Equation:<\/h3>\n\n\n\n<p>The balanced equation is:<br>2NH3+2NO\u21922N2+3H2O2\\text{NH}_3 + 2\\text{NO} \\rightarrow 2\\text{N}_2 + 3\\text{H}_2\\text{O}2NH3\u200b+2NO\u21922N2\u200b+3H2\u200bO<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 6: Identify Reactants and Products<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Reactants<\/strong>: 2NH\u2083 and 2NO<\/li>\n\n\n\n<li><strong>Products<\/strong>: 2N\u2082 and 3H\u2082O<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Correct Answer:<\/h3>\n\n\n\n<p><strong>Reactants: 2NH\u2083 and 2NO; products: 2N\u2082 and 3H\u2082O<\/strong><\/p>\n\n\n\n<p>This is the correct balanced equation, and the stoichiometric coefficients are properly adjusted to ensure conservation of mass for each element.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-351.jpeg\" alt=\"\" class=\"wp-image-248929\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>For the reaction NH3 + NO \u2192 N2 + H2O, identify the reactants, products, and their coefficients once the equation is balanced. (3 points) Group of answer choices Reactants: 2NH3 and 2NO; products: 2N2 and 3H2O Products: 2NH3 and 3NO; reactants: 2N2 and 3H2O Reactants: 4NH3 and 6NO; products: 5N2 and 6H2O Products: 4NH3 and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-248928","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/248928","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=248928"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/248928\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=248928"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=248928"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=248928"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}