Let’s break down each reaction one by one and write the molecular, ionic, and net ionic equations.<\/p>\n\n\n\n
1. Reaction: FeCl3(aq) + CoCl2(aq) \u2192 CoCl3(aq) + FeCl2(aq)<\/strong><\/h3>\n\n\n\nMolecular Equation:<\/strong><\/h4>\n\n\n\nThe molecular equation shows all compounds as intact molecules:FeCl3(aq)+CoCl2(aq)\u2192CoCl3(aq)+FeCl2(aq)FeCl_3(aq) + CoCl_2(aq) \\rightarrow CoCl_3(aq) + FeCl_2(aq)FeCl3\u200b(aq)+CoCl2\u200b(aq)\u2192CoCl3\u200b(aq)+FeCl2\u200b(aq)<\/p>\n\n\n\n
Ionic Equation:<\/strong><\/h4>\n\n\n\nIonic equations show all strong electrolytes as dissociated ions in aqueous solutions:Fe3+(aq)+3Cl\u2212(aq)+Co2+(aq)+2Cl\u2212(aq)\u2192Co3+(aq)+3Cl\u2212(aq)+Fe2+(aq)+2Cl\u2212(aq)Fe^{3+}(aq) + 3Cl^-(aq) + Co^{2+}(aq) + 2Cl^-(aq) \\rightarrow Co^{3+}(aq) + 3Cl^-(aq) + Fe^{2+}(aq) + 2Cl^-(aq)Fe3+(aq)+3Cl\u2212(aq)+Co2+(aq)+2Cl\u2212(aq)\u2192Co3+(aq)+3Cl\u2212(aq)+Fe2+(aq)+2Cl\u2212(aq)<\/p>\n\n\n\n
Net Ionic Equation:<\/strong><\/h4>\n\n\n\nThe net ionic equation removes the spectator ions (those that appear on both sides of the equation):Fe3+(aq)+Co2+(aq)\u2192Co3+(aq)+Fe2+(aq)Fe^{3+}(aq) + Co^{2+}(aq) \\rightarrow Co^{3+}(aq) + Fe^{2+}(aq)Fe3+(aq)+Co2+(aq)\u2192Co3+(aq)+Fe2+(aq)<\/p>\n\n\n\n
Explanation:
In this reaction, iron (III) chloride reacts with cobalt (II) chloride. Both are soluble salts and dissociate in aqueous solutions into their respective ions. The cobalt ion (Co\u00b2\u207a) and the iron ion (Fe\u00b3\u207a) undergo a redox reaction. Cobalt changes from a +2 to a +3 oxidation state, while iron reduces from a +3 to a +2 state.<\/p>\n\n\n\n
2. Reaction: CoCl2(aq) + AgNO3(aq) \u2192 Co(NO3)2(aq) + AgCl(s)<\/strong><\/h3>\n\n\n\nMolecular Equation:<\/strong><\/h4>\n\n\n\nThe molecular equation shows all compounds as intact molecules:CoCl2(aq)+2AgNO3(aq)\u2192Co(NO3)2(aq)+2AgCl(s)CoCl_2(aq) + 2AgNO_3(aq) \\rightarrow Co(NO_3)_2(aq) + 2AgCl(s)CoCl2\u200b(aq)+2AgNO3\u200b(aq)\u2192Co(NO3\u200b)2\u200b(aq)+2AgCl(s)<\/p>\n\n\n\n
Ionic Equation:<\/strong><\/h4>\n\n\n\nIonic equations show all strong electrolytes as dissociated ions in aqueous solutions:Co2+(aq)+2Cl\u2212(aq)+2Ag+(aq)+2NO3\u2212(aq)\u2192Co2+(aq)+2NO3\u2212(aq)+2AgCl(s)Co^{2+}(aq) + 2Cl^-(aq) + 2Ag^+(aq) + 2NO_3^-(aq) \\rightarrow Co^{2+}(aq) + 2NO_3^-(aq) + 2AgCl(s)Co2+(aq)+2Cl\u2212(aq)+2Ag+(aq)+2NO3\u2212\u200b(aq)\u2192Co2+(aq)+2NO3\u2212\u200b(aq)+2AgCl(s)<\/p>\n\n\n\n
Net Ionic Equation:<\/strong><\/h4>\n\n\n\nThe net ionic equation removes the spectator ions:2Ag+(aq)+2Cl\u2212(aq)\u21922AgCl(s)2Ag^+(aq) + 2Cl^-(aq) \\rightarrow 2AgCl(s)2Ag+(aq)+2Cl\u2212(aq)\u21922AgCl(s)<\/p>\n\n\n\n
Explanation:
In this case, cobalt chloride reacts with silver nitrate. Both salts dissociate in water to form their respective ions. Silver ions (Ag\u207a) and chloride ions (Cl\u207b) combine to form the insoluble precipitate silver chloride (AgCl). The cobalt (Co\u00b2\u207a) and nitrate (NO\u2083\u207b) ions are spectator ions that do not participate in the reaction, which is why they are excluded from the net ionic equation.<\/p>\n\n\n\n
Summary:<\/h3>\n\n\n\n\n- Molecular equations<\/strong> show all compounds as undissociated molecules.<\/li>\n\n\n\n
- Ionic equations<\/strong> break down strong electrolytes into their respective ions.<\/li>\n\n\n\n
- Net ionic equations<\/strong> exclude spectator ions, showing only the species that undergo a change during the reaction.<\/li>\n<\/ul>\n\n\n\n
These steps ensure a clearer understanding of the chemical changes that occur in each reaction.<\/p>\n\n\n\n![\"\"](\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-369.jpeg\")
<\/figure>\n","protected":false},"excerpt":{"rendered":". FeCl3(aq) + CoCl2(aq) 2. CoCl2(aq) + AgNO3(aq) What are the Molecular, Ionic, and Net Ionic Equations? The Correct Answer and Explanation is: Let’s break down each reaction one by one and write the molecular, ionic, and net ionic equations. 1. Reaction: FeCl3(aq) + CoCl2(aq) \u2192 CoCl3(aq) + FeCl2(aq) Molecular Equation: The molecular equation shows […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-249012","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=249012"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=249012"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=249012"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=249012"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
The molecular equation shows all compounds as intact molecules:FeCl3(aq)+CoCl2(aq)\u2192CoCl3(aq)+FeCl2(aq)FeCl_3(aq) + CoCl_2(aq) \\rightarrow CoCl_3(aq) + FeCl_2(aq)FeCl3\u200b(aq)+CoCl2\u200b(aq)\u2192CoCl3\u200b(aq)+FeCl2\u200b(aq)<\/p>\n\n\n\n
Ionic Equation:<\/strong><\/h4>\n\n\n\nIonic equations show all strong electrolytes as dissociated ions in aqueous solutions:Fe3+(aq)+3Cl\u2212(aq)+Co2+(aq)+2Cl\u2212(aq)\u2192Co3+(aq)+3Cl\u2212(aq)+Fe2+(aq)+2Cl\u2212(aq)Fe^{3+}(aq) + 3Cl^-(aq) + Co^{2+}(aq) + 2Cl^-(aq) \\rightarrow Co^{3+}(aq) + 3Cl^-(aq) + Fe^{2+}(aq) + 2Cl^-(aq)Fe3+(aq)+3Cl\u2212(aq)+Co2+(aq)+2Cl\u2212(aq)\u2192Co3+(aq)+3Cl\u2212(aq)+Fe2+(aq)+2Cl\u2212(aq)<\/p>\n\n\n\n
Net Ionic Equation:<\/strong><\/h4>\n\n\n\nThe net ionic equation removes the spectator ions (those that appear on both sides of the equation):Fe3+(aq)+Co2+(aq)\u2192Co3+(aq)+Fe2+(aq)Fe^{3+}(aq) + Co^{2+}(aq) \\rightarrow Co^{3+}(aq) + Fe^{2+}(aq)Fe3+(aq)+Co2+(aq)\u2192Co3+(aq)+Fe2+(aq)<\/p>\n\n\n\n
Explanation:
In this reaction, iron (III) chloride reacts with cobalt (II) chloride. Both are soluble salts and dissociate in aqueous solutions into their respective ions. The cobalt ion (Co\u00b2\u207a) and the iron ion (Fe\u00b3\u207a) undergo a redox reaction. Cobalt changes from a +2 to a +3 oxidation state, while iron reduces from a +3 to a +2 state.<\/p>\n\n\n\n
2. Reaction: CoCl2(aq) + AgNO3(aq) \u2192 Co(NO3)2(aq) + AgCl(s)<\/strong><\/h3>\n\n\n\nMolecular Equation:<\/strong><\/h4>\n\n\n\nThe molecular equation shows all compounds as intact molecules:CoCl2(aq)+2AgNO3(aq)\u2192Co(NO3)2(aq)+2AgCl(s)CoCl_2(aq) + 2AgNO_3(aq) \\rightarrow Co(NO_3)_2(aq) + 2AgCl(s)CoCl2\u200b(aq)+2AgNO3\u200b(aq)\u2192Co(NO3\u200b)2\u200b(aq)+2AgCl(s)<\/p>\n\n\n\n
Ionic Equation:<\/strong><\/h4>\n\n\n\nIonic equations show all strong electrolytes as dissociated ions in aqueous solutions:Co2+(aq)+2Cl\u2212(aq)+2Ag+(aq)+2NO3\u2212(aq)\u2192Co2+(aq)+2NO3\u2212(aq)+2AgCl(s)Co^{2+}(aq) + 2Cl^-(aq) + 2Ag^+(aq) + 2NO_3^-(aq) \\rightarrow Co^{2+}(aq) + 2NO_3^-(aq) + 2AgCl(s)Co2+(aq)+2Cl\u2212(aq)+2Ag+(aq)+2NO3\u2212\u200b(aq)\u2192Co2+(aq)+2NO3\u2212\u200b(aq)+2AgCl(s)<\/p>\n\n\n\n
Net Ionic Equation:<\/strong><\/h4>\n\n\n\nThe net ionic equation removes the spectator ions:2Ag+(aq)+2Cl\u2212(aq)\u21922AgCl(s)2Ag^+(aq) + 2Cl^-(aq) \\rightarrow 2AgCl(s)2Ag+(aq)+2Cl\u2212(aq)\u21922AgCl(s)<\/p>\n\n\n\n
Explanation:
In this case, cobalt chloride reacts with silver nitrate. Both salts dissociate in water to form their respective ions. Silver ions (Ag\u207a) and chloride ions (Cl\u207b) combine to form the insoluble precipitate silver chloride (AgCl). The cobalt (Co\u00b2\u207a) and nitrate (NO\u2083\u207b) ions are spectator ions that do not participate in the reaction, which is why they are excluded from the net ionic equation.<\/p>\n\n\n\n
Summary:<\/h3>\n\n\n\n\n- Molecular equations<\/strong> show all compounds as undissociated molecules.<\/li>\n\n\n\n
- Ionic equations<\/strong> break down strong electrolytes into their respective ions.<\/li>\n\n\n\n
- Net ionic equations<\/strong> exclude spectator ions, showing only the species that undergo a change during the reaction.<\/li>\n<\/ul>\n\n\n\n
These steps ensure a clearer understanding of the chemical changes that occur in each reaction.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":". FeCl3(aq) + CoCl2(aq) 2. CoCl2(aq) + AgNO3(aq) What are the Molecular, Ionic, and Net Ionic Equations? The Correct Answer and Explanation is: Let’s break down each reaction one by one and write the molecular, ionic, and net ionic equations. 1. Reaction: FeCl3(aq) + CoCl2(aq) \u2192 CoCl3(aq) + FeCl2(aq) Molecular Equation: The molecular equation shows […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-249012","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=249012"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=249012"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=249012"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=249012"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
The net ionic equation removes the spectator ions (those that appear on both sides of the equation):Fe3+(aq)+Co2+(aq)\u2192Co3+(aq)+Fe2+(aq)Fe^{3+}(aq) + Co^{2+}(aq) \\rightarrow Co^{3+}(aq) + Fe^{2+}(aq)Fe3+(aq)+Co2+(aq)\u2192Co3+(aq)+Fe2+(aq)<\/p>\n\n\n\n
Explanation:
In this reaction, iron (III) chloride reacts with cobalt (II) chloride. Both are soluble salts and dissociate in aqueous solutions into their respective ions. The cobalt ion (Co\u00b2\u207a) and the iron ion (Fe\u00b3\u207a) undergo a redox reaction. Cobalt changes from a +2 to a +3 oxidation state, while iron reduces from a +3 to a +2 state.<\/p>\n\n\n\n
2. Reaction: CoCl2(aq) + AgNO3(aq) \u2192 Co(NO3)2(aq) + AgCl(s)<\/strong><\/h3>\n\n\n\nMolecular Equation:<\/strong><\/h4>\n\n\n\nThe molecular equation shows all compounds as intact molecules:CoCl2(aq)+2AgNO3(aq)\u2192Co(NO3)2(aq)+2AgCl(s)CoCl_2(aq) + 2AgNO_3(aq) \\rightarrow Co(NO_3)_2(aq) + 2AgCl(s)CoCl2\u200b(aq)+2AgNO3\u200b(aq)\u2192Co(NO3\u200b)2\u200b(aq)+2AgCl(s)<\/p>\n\n\n\n
Ionic Equation:<\/strong><\/h4>\n\n\n\nIonic equations show all strong electrolytes as dissociated ions in aqueous solutions:Co2+(aq)+2Cl\u2212(aq)+2Ag+(aq)+2NO3\u2212(aq)\u2192Co2+(aq)+2NO3\u2212(aq)+2AgCl(s)Co^{2+}(aq) + 2Cl^-(aq) + 2Ag^+(aq) + 2NO_3^-(aq) \\rightarrow Co^{2+}(aq) + 2NO_3^-(aq) + 2AgCl(s)Co2+(aq)+2Cl\u2212(aq)+2Ag+(aq)+2NO3\u2212\u200b(aq)\u2192Co2+(aq)+2NO3\u2212\u200b(aq)+2AgCl(s)<\/p>\n\n\n\n
Net Ionic Equation:<\/strong><\/h4>\n\n\n\nThe net ionic equation removes the spectator ions:2Ag+(aq)+2Cl\u2212(aq)\u21922AgCl(s)2Ag^+(aq) + 2Cl^-(aq) \\rightarrow 2AgCl(s)2Ag+(aq)+2Cl\u2212(aq)\u21922AgCl(s)<\/p>\n\n\n\n
Explanation:
In this case, cobalt chloride reacts with silver nitrate. Both salts dissociate in water to form their respective ions. Silver ions (Ag\u207a) and chloride ions (Cl\u207b) combine to form the insoluble precipitate silver chloride (AgCl). The cobalt (Co\u00b2\u207a) and nitrate (NO\u2083\u207b) ions are spectator ions that do not participate in the reaction, which is why they are excluded from the net ionic equation.<\/p>\n\n\n\n
Summary:<\/h3>\n\n\n\n\n- Molecular equations<\/strong> show all compounds as undissociated molecules.<\/li>\n\n\n\n
- Ionic equations<\/strong> break down strong electrolytes into their respective ions.<\/li>\n\n\n\n
- Net ionic equations<\/strong> exclude spectator ions, showing only the species that undergo a change during the reaction.<\/li>\n<\/ul>\n\n\n\n
These steps ensure a clearer understanding of the chemical changes that occur in each reaction.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":". FeCl3(aq) + CoCl2(aq) 2. CoCl2(aq) + AgNO3(aq) What are the Molecular, Ionic, and Net Ionic Equations? The Correct Answer and Explanation is: Let’s break down each reaction one by one and write the molecular, ionic, and net ionic equations. 1. Reaction: FeCl3(aq) + CoCl2(aq) \u2192 CoCl3(aq) + FeCl2(aq) Molecular Equation: The molecular equation shows […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-249012","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=249012"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=249012"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=249012"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=249012"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
The molecular equation shows all compounds as intact molecules:CoCl2(aq)+2AgNO3(aq)\u2192Co(NO3)2(aq)+2AgCl(s)CoCl_2(aq) + 2AgNO_3(aq) \\rightarrow Co(NO_3)_2(aq) + 2AgCl(s)CoCl2\u200b(aq)+2AgNO3\u200b(aq)\u2192Co(NO3\u200b)2\u200b(aq)+2AgCl(s)<\/p>\n\n\n\n
Ionic Equation:<\/strong><\/h4>\n\n\n\nIonic equations show all strong electrolytes as dissociated ions in aqueous solutions:Co2+(aq)+2Cl\u2212(aq)+2Ag+(aq)+2NO3\u2212(aq)\u2192Co2+(aq)+2NO3\u2212(aq)+2AgCl(s)Co^{2+}(aq) + 2Cl^-(aq) + 2Ag^+(aq) + 2NO_3^-(aq) \\rightarrow Co^{2+}(aq) + 2NO_3^-(aq) + 2AgCl(s)Co2+(aq)+2Cl\u2212(aq)+2Ag+(aq)+2NO3\u2212\u200b(aq)\u2192Co2+(aq)+2NO3\u2212\u200b(aq)+2AgCl(s)<\/p>\n\n\n\n
Net Ionic Equation:<\/strong><\/h4>\n\n\n\nThe net ionic equation removes the spectator ions:2Ag+(aq)+2Cl\u2212(aq)\u21922AgCl(s)2Ag^+(aq) + 2Cl^-(aq) \\rightarrow 2AgCl(s)2Ag+(aq)+2Cl\u2212(aq)\u21922AgCl(s)<\/p>\n\n\n\n
Explanation:
In this case, cobalt chloride reacts with silver nitrate. Both salts dissociate in water to form their respective ions. Silver ions (Ag\u207a) and chloride ions (Cl\u207b) combine to form the insoluble precipitate silver chloride (AgCl). The cobalt (Co\u00b2\u207a) and nitrate (NO\u2083\u207b) ions are spectator ions that do not participate in the reaction, which is why they are excluded from the net ionic equation.<\/p>\n\n\n\n
Summary:<\/h3>\n\n\n\n\n- Molecular equations<\/strong> show all compounds as undissociated molecules.<\/li>\n\n\n\n
- Ionic equations<\/strong> break down strong electrolytes into their respective ions.<\/li>\n\n\n\n
- Net ionic equations<\/strong> exclude spectator ions, showing only the species that undergo a change during the reaction.<\/li>\n<\/ul>\n\n\n\n
These steps ensure a clearer understanding of the chemical changes that occur in each reaction.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":". FeCl3(aq) + CoCl2(aq) 2. CoCl2(aq) + AgNO3(aq) What are the Molecular, Ionic, and Net Ionic Equations? The Correct Answer and Explanation is: Let’s break down each reaction one by one and write the molecular, ionic, and net ionic equations. 1. Reaction: FeCl3(aq) + CoCl2(aq) \u2192 CoCl3(aq) + FeCl2(aq) Molecular Equation: The molecular equation shows […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-249012","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=249012"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=249012"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=249012"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=249012"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
The net ionic equation removes the spectator ions:2Ag+(aq)+2Cl\u2212(aq)\u21922AgCl(s)2Ag^+(aq) + 2Cl^-(aq) \\rightarrow 2AgCl(s)2Ag+(aq)+2Cl\u2212(aq)\u21922AgCl(s)<\/p>\n\n\n\n
Explanation:
In this case, cobalt chloride reacts with silver nitrate. Both salts dissociate in water to form their respective ions. Silver ions (Ag\u207a) and chloride ions (Cl\u207b) combine to form the insoluble precipitate silver chloride (AgCl). The cobalt (Co\u00b2\u207a) and nitrate (NO\u2083\u207b) ions are spectator ions that do not participate in the reaction, which is why they are excluded from the net ionic equation.<\/p>\n\n\n\n
Summary:<\/h3>\n\n\n\n\n- Molecular equations<\/strong> show all compounds as undissociated molecules.<\/li>\n\n\n\n
- Ionic equations<\/strong> break down strong electrolytes into their respective ions.<\/li>\n\n\n\n
- Net ionic equations<\/strong> exclude spectator ions, showing only the species that undergo a change during the reaction.<\/li>\n<\/ul>\n\n\n\n
These steps ensure a clearer understanding of the chemical changes that occur in each reaction.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":". FeCl3(aq) + CoCl2(aq) 2. CoCl2(aq) + AgNO3(aq) What are the Molecular, Ionic, and Net Ionic Equations? The Correct Answer and Explanation is: Let’s break down each reaction one by one and write the molecular, ionic, and net ionic equations. 1. Reaction: FeCl3(aq) + CoCl2(aq) \u2192 CoCl3(aq) + FeCl2(aq) Molecular Equation: The molecular equation shows […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-249012","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=249012"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=249012"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=249012"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=249012"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
These steps ensure a clearer understanding of the chemical changes that occur in each reaction.<\/p>\n\n\n\n . FeCl3(aq) + CoCl2(aq) 2. CoCl2(aq) + AgNO3(aq) What are the Molecular, Ionic, and Net Ionic Equations? The Correct Answer and Explanation is: Let’s break down each reaction one by one and write the molecular, ionic, and net ionic equations. 1. Reaction: FeCl3(aq) + CoCl2(aq) \u2192 CoCl3(aq) + FeCl2(aq) Molecular Equation: The molecular equation shows […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-249012","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=249012"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249012\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=249012"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=249012"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=249012"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}<\/figure>\n","protected":false},"excerpt":{"rendered":"