{"id":249066,"date":"2025-07-08T22:05:06","date_gmt":"2025-07-08T22:05:06","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=249066"},"modified":"2025-07-08T22:05:08","modified_gmt":"2025-07-08T22:05:08","slug":"a-standard-can-of-soda-has-a-volume-of-355-ml","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/08\/a-standard-can-of-soda-has-a-volume-of-355-ml\/","title":{"rendered":"A standard can of soda has a volume of 355 mL."},"content":{"rendered":"\n
A standard can of soda has a volume of 355 mL. The mass of the can is 0.369 kg when it is full, while the can weighs 0.153 N when empty. Determine the density, specific weight, and specific gravity of the soda, and compare your results to the corresponding values for water.<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n
Let’s break this down step by step.<\/p>\n\n\n\n
1. Density (\u03c1) of the Soda<\/strong><\/h3>\n\n\n\n
Density is defined as mass per unit volume: \u03c1=mV\\rho = \\frac{m}{V}\u03c1=Vm\u200b<\/p>\n\n\n\n
Where:<\/p>\n\n\n\n
\n
mmm is the mass of the soda<\/li>\n\n\n\n
VVV is the volume of the soda<\/li>\n<\/ul>\n\n\n\n
The total mass of the can when full is 0.369 kg. The mass of the empty can is determined from its weight: W=mgW = mgW=mg<\/p>\n\n\n\n
Where:<\/p>\n\n\n\n
\n
W=0.153\u2009NW = 0.153 \\, \\text{N}W=0.153N (weight of the empty can)<\/li>\n\n\n\n
g=9.81\u2009m\/s2g = 9.81 \\, \\text{m\/s}^2g=9.81m\/s2 (acceleration due to gravity)<\/li>\n<\/ul>\n\n\n\n
The mass of the empty can: mempty=Wg=0.1539.81=0.0156\u2009kgm_{\\text{empty}} = \\frac{W}{g} = \\frac{0.153}{9.81} = 0.0156 \\, \\text{kg}mempty\u200b=gW\u200b=9.810.153\u200b=0.0156kg<\/p>\n\n\n\n
Now, the mass of the soda itself: msoda=mfull\u2212mempty=0.369\u22120.0156=0.3534\u2009kgm_{\\text{soda}} = m_{\\text{full}} – m_{\\text{empty}} = 0.369 – 0.0156 = 0.3534 \\, \\text{kg}msoda\u200b=mfull\u200b\u2212mempty\u200b=0.369\u22120.0156=0.3534kg<\/p>\n\n\n\n
We are given the volume of the soda as 355 mL, which is equivalent to 0.355 L or 0.355 \u00d7 10\u207b\u00b3 m\u00b3.<\/p>\n\n\n\n
Now we can calculate the density: \u03c1soda=msodaV=0.35340.355\u00d710\u22123=997.5\u2009kg\/m3\\rho_{\\text{soda}} = \\frac{m_{\\text{soda}}}{V} = \\frac{0.3534}{0.355 \\times 10^{-3}} = 997.5 \\, \\text{kg\/m}^3\u03c1soda\u200b=Vmsoda\u200b\u200b=0.355\u00d710\u221230.3534\u200b=997.5kg\/m3<\/p>\n\n\n\n
2. Specific Weight (\u03b3) of the Soda<\/strong><\/h3>\n\n\n\n
Specific weight is the weight per unit volume: \u03b3=WV\\gamma = \\frac{W}{V}\u03b3=VW\u200b<\/p>\n\n\n\n
Thus, the specific weight: \u03b3soda=3.4640.355\u00d710\u22123=9755.8\u2009N\/m3\\gamma_{\\text{soda}} = \\frac{3.464}{0.355 \\times 10^{-3}} = 9755.8 \\, \\text{N\/m}^3\u03b3soda\u200b=0.355\u00d710\u221233.464\u200b=9755.8N\/m3<\/p>\n\n\n\n
3. Specific Gravity (SG) of the Soda<\/strong><\/h3>\n\n\n\n
Specific gravity is the ratio of the density of the substance to the density of water at the same temperature. The density of water is approximately 1000 kg\/m\u00b3 at 4\u00b0C. SG=\u03c1soda\u03c1water=997.51000=0.9975SG = \\frac{\\rho_{\\text{soda}}}{\\rho_{\\text{water}}} = \\frac{997.5}{1000} = 0.9975SG=\u03c1water\u200b\u03c1soda\u200b\u200b=1000997.5\u200b=0.9975<\/p>\n\n\n\n
Comparison to Water:<\/h3>\n\n\n\n
\n
Density of Water<\/strong>: 1000\u2009kg\/m31000 \\, \\text{kg\/m}^31000kg\/m3<\/li>\n\n\n\n
Specific Weight of Water<\/strong>: 9800\u2009N\/m39800 \\, \\text{N\/m}^39800N\/m3<\/li>\n\n\n\n
Specific Gravity of Water<\/strong>: 111<\/li>\n<\/ul>\n\n\n\n
Conclusion:<\/h3>\n\n\n\n
\n
The density<\/strong> of the soda is very close to that of water (997.5 kg\/m\u00b3 vs. 1000 kg\/m\u00b3), indicating that the soda has a similar density to water.<\/li>\n\n\n\n
The specific weight<\/strong> of the soda (9755.8 N\/m\u00b3) is slightly less than that of water (9800 N\/m\u00b3), which again shows that the soda is nearly the same as water in weight per unit volume.<\/li>\n\n\n\n
The specific gravity<\/strong> is about 0.9975, almost identical to that of water (SG = 1).<\/li>\n<\/ul>\n\n\n\n
This comparison shows that soda is nearly as dense and heavy as water, but with a slightly lower density and specific weight.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"
A standard can of soda has a volume of 355 mL. The mass of the can is 0.369 kg when it is full, while the can weighs 0.153 N when empty. Determine the density, specific weight, and specific gravity of the soda, and compare your results to the corresponding values for water. The Correct Answer […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-249066","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249066","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=249066"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249066\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=249066"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=249066"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=249066"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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<\/figure>\n","protected":false},"excerpt":{"rendered":"