{"id":249098,"date":"2025-07-08T22:30:19","date_gmt":"2025-07-08T22:30:19","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=249098"},"modified":"2025-07-08T22:30:21","modified_gmt":"2025-07-08T22:30:21","slug":"find-the-centroid-of-a-semi-circular-arc-of-radius","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/08\/find-the-centroid-of-a-semi-circular-arc-of-radius\/","title":{"rendered":"Find the centroid of a semi-circular arc of radius"},"content":{"rendered":"\n<p>. Find the centroid of a semi-circular arc of radius a. 2. Find the centroid of a semi-circular area of radius a. Answer it correctly. show complete solutions( step by step).<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Centroid of a Semi-Circular Arc<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Problem Setup<\/strong>:<br>The semi-circular arc of radius <strong>a<\/strong> is part of a circle, and we are looking to find the centroid of the arc.<\/li>\n\n\n\n<li><strong>Formula for the Centroid of a Circular Arc<\/strong>:<br>The centroid of a semi-circular arc lies on the central axis of the circle (i.e., along the y-axis if the arc is in the upper half of the circle). The formula for the centroid of a circular arc with radius <strong>a<\/strong> is: ycentroid=4a3\u03c0y_{centroid} = \\frac{4a}{3\\pi}ycentroid\u200b=3\u03c04a\u200b<\/li>\n\n\n\n<li><strong>Step-by-step Solution<\/strong>:<ul><li>For the arc, the length is \u03c0a\\pi a\u03c0a (half the circumference of the circle).<\/li><li>Using the symmetry of the arc and the fact that the centroid is along the vertical axis, we calculate the distance from the origin (the center of the circle) to the centroid along the y-axis. This yields the final result for the semi-circular arc&#8217;s centroid:<\/li><\/ul>ycentroid=4a3\u03c0y_{centroid} = \\frac{4a}{3\\pi}ycentroid\u200b=3\u03c04a\u200b<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Centroid of a Semi-Circular Area<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Problem Setup<\/strong>:<br>Now, consider a semi-circular <strong>area<\/strong> with radius <strong>a<\/strong>. The centroid is the point where the entire area of the semi-circle can be assumed to be concentrated.<\/li>\n\n\n\n<li><strong>Formula for the Centroid of a Semi-Circular Area<\/strong>:<br>The formula for the centroid <strong>y<\/strong> of a semi-circular area (in the case where the flat part of the semi-circle is on the x-axis) is: ycentroid=4a3\u03c0y_{centroid} = \\frac{4a}{3\\pi}ycentroid\u200b=3\u03c04a\u200b This is the same as for the arc because the symmetry and geometry of the situation are similar. It is also along the y-axis.<\/li>\n\n\n\n<li><strong>Step-by-step Solution<\/strong>:<ul><li>The area of the semi-circle is given by 12\u03c0a2\\frac{1}{2} \\pi a^221\u200b\u03c0a2.<\/li><li>By symmetry, the centroid of the semi-circular area lies along the central axis.<\/li><li>The formula used for the centroid of the semi-circular area is derived from the integral calculation of the first moment of area over the semi-circle, yielding the same result for the <strong>y-coordinate<\/strong> of the centroid as:<\/li><\/ul>ycentroid=4a3\u03c0y_{centroid} = \\frac{4a}{3\\pi}ycentroid\u200b=3\u03c04a\u200b<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion<\/h3>\n\n\n\n<p>Both the centroid of the arc and the centroid of the semi-circular area are located at the same distance from the flat side (x-axis), with a value of 4a3\u03c0\\frac{4a}{3\\pi}3\u03c04a\u200b, but their physical meanings differ. The centroid of the arc represents the balancing point of the arc&#8217;s mass, while the centroid of the area represents the center of mass of the semi-circular shape.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-389.jpeg\" alt=\"\" class=\"wp-image-249099\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>. Find the centroid of a semi-circular arc of radius a. 2. Find the centroid of a semi-circular area of radius a. Answer it correctly. show complete solutions( step by step). The Correct Answer and Explanation is: Centroid of a Semi-Circular Arc Centroid of a Semi-Circular Area Conclusion Both the centroid of the arc and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-249098","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249098","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=249098"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249098\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=249098"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=249098"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=249098"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}