{"id":249813,"date":"2025-07-10T05:25:23","date_gmt":"2025-07-10T05:25:23","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=249813"},"modified":"2025-07-10T05:25:26","modified_gmt":"2025-07-10T05:25:26","slug":"xrightarrowh_2o-ho-ch_2-ch_2-br","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/10\/xrightarrowh_2o-ho-ch_2-ch_2-br\/","title":{"rendered":"\u00a0\\xrightarrow{H_2O} ? HO-CH_2-CH_2-Br"},"content":{"rendered":"\n
\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

It seems that the image you’ve provided shows two organic reactions involving a bromine (Br) atom attached to carbon atoms in a molecule. Let me break it down:<\/p>\n\n\n\n

    \n
  1. First Reaction (top):<\/strong>\n
      \n
    • The structure shown is an alkene (double bond between two carbon atoms) with a bromine atom attached to one of the carbons.<\/li>\n\n\n\n
    • The reagent is water (H2O).<\/li>\n\n\n\n
    • In this reaction, water will react with the alkene via hydrohalogenation<\/strong>. The double bond is broken, and water will add across the double bond, resulting in the formation of an alcohol.<\/li>\n\n\n\n
    • Product<\/strong>: The product would be an alcohol<\/strong> where one of the carbon atoms that was part of the original double bond now has a hydroxyl group (-OH) attached to it.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • Second Reaction (bottom):<\/strong>\n
        \n
      • The starting material is a bromo-alcohol (HOCH2-CH2Br), with the hydroxyl group (-OH) on one carbon and the bromine atom on another.<\/li>\n\n\n\n
      • The reagents are sodium hydroxide (NaOH) and water (H2O).<\/li>\n\n\n\n
      • In this reaction, the hydroxide ion (OH-) from NaOH will undergo nucleophilic substitution<\/strong> on the carbon attached to the bromine (C-Br bond). The bromine atom will leave, and the hydroxide will take its place, forming an alcohol.<\/li>\n\n\n\n
      • Product<\/strong>: The product is an alcohol<\/strong> where the bromine is replaced by a hydroxyl group (-OH), resulting in a dihydroxy compound.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n

        Both reactions involve substitution or addition mechanisms that lead to the formation of alcohols from the starting compounds.<\/p>\n\n\n\n

        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

        The Correct Answer and Explanation is: It seems that the image you’ve provided shows two organic reactions involving a bromine (Br) atom attached to carbon atoms in a molecule. Let me break it down: Both reactions involve substitution or addition mechanisms that lead to the formation of alcohols from the starting compounds.<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-249813","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249813","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=249813"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/249813\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=249813"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=249813"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=249813"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}