{"id":250229,"date":"2025-07-10T08:24:39","date_gmt":"2025-07-10T08:24:39","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=250229"},"modified":"2025-07-10T08:24:41","modified_gmt":"2025-07-10T08:24:41","slug":"identify-the-species-oxidized-the-species-reduced-the-oxidizing-agent-and-the-reducing-agent-in-the-following-electron-transfer-reaction-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/10\/identify-the-species-oxidized-the-species-reduced-the-oxidizing-agent-and-the-reducing-agent-in-the-following-electron-transfer-reaction-2\/","title":{"rendered":"Identify the species oxidized, the species reduced, the oxidizing agent, and the reducing agent in the following electron-transfer reaction"},"content":{"rendered":"\n

Identify the species oxidized, the species reduced, the oxidizing agent, and the reducing agent in the following electron-transfer reaction. Ni(s) + Pb2+(aq) -> Ni2+(aq) + Pb(s) Species oxidized: Ni(s) Species reduced: Pb2+(aq) Oxidizing agent: Pb2+(aq) Reducing agent: Ni(s) As the reaction proceeds, electrons are transferred from Ni(s) to Pb2+(aq). b) Identify the species oxidized, the species reduced, the oxidizing agent, and the reducing agent in the following electron-transfer reaction. Br2(l) + Pb(s) -> 2Br-(aq) + Pb2+(aq) Species oxidized: Pb(s) Species reduced: Br2(l) Oxidizing agent: Br2(l) Reducing agent: Pb(s) As the reaction proceeds, electrons are transferred from Pb(s) to Br2(l). c) Identify the species oxidized, the species reduced, the oxidizing agent, and the reducing agent in the following electron-transfer reaction. 2Al(s) + 3Sn2+(aq) -> 2Al3+(aq) + 3Sn(s) Species oxidized: Sn2+(aq) Species reduced: Al(s) Oxidizing agent: Al(s) Reducing agent: Sn2+(aq) As the reaction proceeds, electrons are transferred from Sn2+(aq) to Al(s).<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

In each of the given reactions, we need to identify the species being oxidized and reduced, as well as the oxidizing and reducing agents. Let\u2019s break down each reaction:<\/p>\n\n\n\n

a) Ni(s) + Pb\u00b2\u207a(aq) \u2192 Ni\u00b2\u207a(aq) + Pb(s)<\/h3>\n\n\n\n
    \n
  1. Species oxidized<\/strong>: Ni(s)<\/strong>. Oxidation is the loss of electrons. In this reaction, nickel (Ni) starts as a solid (Ni(s)) and turns into Ni\u00b2\u207a (aq), meaning it loses two electrons.<\/li>\n\n\n\n
  2. Species reduced<\/strong>: Pb\u00b2\u207a(aq)<\/strong>. Reduction is the gain of electrons. Lead ions (Pb\u00b2\u207a) gain electrons and are reduced to form solid lead (Pb).<\/li>\n\n\n\n
  3. Oxidizing agent<\/strong>: Pb\u00b2\u207a(aq)<\/strong>. The species that gains electrons is called the oxidizing agent. Here, Pb\u00b2\u207a is reduced by gaining electrons from Ni(s), so Pb\u00b2\u207a is the oxidizing agent.<\/li>\n\n\n\n
  4. Reducing agent<\/strong>: Ni(s)<\/strong>. The species that loses electrons is called the reducing agent. Since Ni(s) loses electrons to reduce Pb\u00b2\u207a, Ni(s) is the reducing agent.<\/li>\n<\/ol>\n\n\n\n

    In this reaction, Ni(s)<\/strong> is oxidized and provides the electrons for the reduction of Pb\u00b2\u207a(aq)<\/strong>.<\/p>\n\n\n\n

    b) Br\u2082(l) + Pb(s) \u2192 2Br\u207b(aq) + Pb\u00b2\u207a(aq)<\/h3>\n\n\n\n
      \n
    1. Species oxidized<\/strong>: Pb(s)<\/strong>. Here, solid lead (Pb) goes from an oxidation state of 0 in Pb(s) to Pb\u00b2\u207a in solution, meaning it loses two electrons and is oxidized.<\/li>\n\n\n\n
    2. Species reduced<\/strong>: Br\u2082(l)<\/strong>. Bromine (Br\u2082) starts as a liquid molecule with an oxidation state of 0 and is reduced to Br\u207b by gaining electrons.<\/li>\n\n\n\n
    3. Oxidizing agent<\/strong>: Br\u2082(l)<\/strong>. The species that gains electrons is the oxidizing agent. In this case, bromine (Br\u2082) is reduced to Br\u207b, so Br\u2082 is the oxidizing agent.<\/li>\n\n\n\n
    4. Reducing agent<\/strong>: Pb(s)<\/strong>. The species that loses electrons is the reducing agent. Here, Pb(s) gives up electrons, so Pb(s) is the reducing agent.<\/li>\n<\/ol>\n\n\n\n

      In this reaction, Pb(s)<\/strong> is oxidized, and Br\u2082(l)<\/strong> is reduced.<\/p>\n\n\n\n

      c) 2Al(s) + 3Sn\u00b2\u207a(aq) \u2192 2Al\u00b3\u207a(aq) + 3Sn(s)<\/h3>\n\n\n\n
        \n
      1. Species oxidized<\/strong>: Al(s)<\/strong>. Aluminum (Al) starts as a solid and is oxidized to form Al\u00b3\u207a, meaning it loses three electrons.<\/li>\n\n\n\n
      2. Species reduced<\/strong>: Sn\u00b2\u207a(aq)<\/strong>. Tin (Sn\u00b2\u207a) ions gain electrons and are reduced to solid tin (Sn).<\/li>\n\n\n\n
      3. Oxidizing agent<\/strong>: Sn\u00b2\u207a(aq)<\/strong>. The species that gains electrons is the oxidizing agent. Here, Sn\u00b2\u207a is reduced to Sn(s), so Sn\u00b2\u207a is the oxidizing agent.<\/li>\n\n\n\n
      4. Reducing agent<\/strong>: Al(s)<\/strong>. The species that loses electrons is the reducing agent. Aluminum (Al) is oxidized to Al\u00b3\u207a, so Al(s) is the reducing agent.<\/li>\n<\/ol>\n\n\n\n

        In this reaction, Al(s)<\/strong> is oxidized, and Sn\u00b2\u207a(aq)<\/strong> is reduced.<\/p>\n\n\n\n

        Summary:<\/h3>\n\n\n\n
          \n
        • In each reaction, the species that is oxidized loses electrons, and the species that is reduced gains electrons.<\/li>\n\n\n\n
        • The oxidizing agent<\/strong> is always the species that gets reduced (it gains electrons), and the reducing agent<\/strong> is the species that gets oxidized (it loses electrons).<\/li>\n<\/ul>\n\n\n\n

          By analyzing the electron transfer process, we can correctly identify the species involved and how they interact to facilitate the reactions.<\/p>\n\n\n\n

          \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

          Identify the species oxidized, the species reduced, the oxidizing agent, and the reducing agent in the following electron-transfer reaction. Ni(s) + Pb2+(aq) -> Ni2+(aq) + Pb(s) Species oxidized: Ni(s) Species reduced: Pb2+(aq) Oxidizing agent: Pb2+(aq) Reducing agent: Ni(s) As the reaction proceeds, electrons are transferred from Ni(s) to Pb2+(aq). b) Identify the species oxidized, the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-250229","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/250229","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=250229"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/250229\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=250229"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=250229"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=250229"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}