{"id":250459,"date":"2025-07-10T09:43:52","date_gmt":"2025-07-10T09:43:52","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=250459"},"modified":"2025-07-10T09:43:54","modified_gmt":"2025-07-10T09:43:54","slug":"find-the-oxidation-number-of-al-in-al2o3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/10\/find-the-oxidation-number-of-al-in-al2o3\/","title":{"rendered":"Find the oxidation number of Al in Al2O3."},"content":{"rendered":"\n
Find the oxidation number of Al in Al2O3.<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n
To determine the oxidation number of aluminum (Al) in aluminum oxide (Al\u2082O\u2083), we need to follow a few steps based on the rules for assigning oxidation numbers:<\/p>\n\n\n\n
Step 1: Identify the oxidation state of oxygen.<\/h3>\n\n\n\n
Oxygen typically has an oxidation number of -2 in most compounds, including aluminum oxide. Since there are three oxygen atoms in Al\u2082O\u2083, the total oxidation number for oxygen is:3\u00d7(\u22122)=\u221263 \\times (-2) = -63\u00d7(\u22122)=\u22126<\/p>\n\n\n\n
Step 2: Assign oxidation numbers to aluminum.<\/h3>\n\n\n\n
Let the oxidation number of aluminum be xxx. Since there are two aluminum atoms in the compound (Al\u2082O\u2083), the total oxidation number for aluminum will be:2\u00d7x=2×2 \\times x = 2×2\u00d7x=2x<\/p>\n\n\n\n
Step 3: Apply the rule that the sum of oxidation numbers in a neutral compound is zero.<\/h3>\n\n\n\n
Al\u2082O\u2083 is a neutral compound, meaning that the sum of the oxidation numbers of all elements in the compound must be zero. Therefore, we can write the equation:2x+(\u22126)=02x + (-6) = 02x+(\u22126)=0<\/p>\n\n\n\n
The oxidation number of aluminum (Al) in Al\u2082O\u2083 is +3.<\/p>\n\n\n\n
Explanation:<\/h3>\n\n\n\n
\n
Oxygen has a standard oxidation number of -2 in most compounds.<\/li>\n\n\n\n
In a neutral compound like Al\u2082O\u2083, the sum of the oxidation numbers of all elements must be zero.<\/li>\n\n\n\n
By applying this rule and knowing the oxidation state of oxygen, we can solve for the oxidation number of aluminum.<\/li>\n\n\n\n
The result shows that aluminum has an oxidation number of +3 in Al\u2082O\u2083.<\/li>\n<\/ul>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"
Find the oxidation number of Al in Al2O3. The Correct Answer and Explanation is: To determine the oxidation number of aluminum (Al) in aluminum oxide (Al\u2082O\u2083), we need to follow a few steps based on the rules for assigning oxidation numbers: Step 1: Identify the oxidation state of oxygen. Oxygen typically has an oxidation number […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-250459","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/250459","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=250459"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/250459\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=250459"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=250459"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=250459"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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