{"id":250628,"date":"2025-07-10T11:20:14","date_gmt":"2025-07-10T11:20:14","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=250628"},"modified":"2025-07-10T11:20:17","modified_gmt":"2025-07-10T11:20:17","slug":"identify-the-element-as-paramagnetic-or-diamagnetic","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/10\/identify-the-element-as-paramagnetic-or-diamagnetic\/","title":{"rendered":"Identify the element as paramagnetic or diamagnetic."},"content":{"rendered":"\n<p>Identify the element as paramagnetic or diamagnetic. (a) Ti, titanium Full electron configuration = (do not use noble gas notation) Orbital box notation: 3d 4s 3p 3s 2p 2s 1s Ti is (b) Sn, tin Noble gas electron configuration = Orbital box notation: 5p 5s Sn is<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(a) <strong>Titanium (Ti)<\/strong><\/h3>\n\n\n\n<p><strong>Full Electron Configuration:<\/strong><br>Ti has an atomic number of 22, so its electron configuration is:<br>1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 3d\u00b2 4s\u00b2<\/p>\n\n\n\n<p><strong>Orbital Box Notation:<\/strong><br>The orbital box notation shows the arrangement of electrons in the orbitals:<\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">CopyEdit<code>1s \u2191\u2193   2s \u2191\u2193   2p \u2191\u2193 \u2191\u2193 \u2191\u2193   3s \u2191\u2193   3p \u2191\u2193 \u2191\u2193 \u2191\u2193  \n3d \u2191\u2193 \u2191   4s \u2191\u2193\n<\/code><\/pre>\n\n\n\n<p>In the 3d orbital, Ti has 2 electrons, and in the 4s orbital, it has 2 electrons.<\/p>\n\n\n\n<p><strong>Paramagnetic or Diamagnetic?<\/strong><br>Titanium is <strong>paramagnetic<\/strong> because it has unpaired electrons in the 3d orbital. A substance is considered <strong>paramagnetic<\/strong> if it has one or more unpaired electrons, which can align with an external magnetic field, causing the substance to be attracted to the field.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">(b) <strong>Tin (Sn)<\/strong><\/h3>\n\n\n\n<p><strong>Noble Gas Electron Configuration:<\/strong><br>Sn has an atomic number of 50, and its electron configuration can be written as:<br>[Kr] 5s\u00b2 4d\u00b9\u2070 5p\u00b2<\/p>\n\n\n\n<p>This shows that Sn\u2019s valence electrons are in the 5s and 5p orbitals.<\/p>\n\n\n\n<p><strong>Orbital Box Notation:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">CopyEdit<code>5s \u2191\u2193   4d \u2191\u2193 \u2191\u2193 \u2191\u2193 \u2191\u2193 \u2191\u2193   5p \u2191\u2193 \u2191\n<\/code><\/pre>\n\n\n\n<p>Here, Sn has 2 electrons in the 5s orbital and 2 electrons in the 5p orbital. There are no unpaired electrons in the 5s orbital, but there is one unpaired electron in the 5p orbital.<\/p>\n\n\n\n<p><strong>Paramagnetic or Diamagnetic?<\/strong><br>Tin is <strong>paramagnetic<\/strong> because it has one unpaired electron in the 5p orbital. As with titanium, the presence of unpaired electrons causes Sn to be attracted to a magnetic field.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Summary:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Titanium (Ti)<\/strong> is <strong>paramagnetic<\/strong> due to the presence of unpaired electrons in the 3d orbital.<\/li>\n\n\n\n<li><strong>Tin (Sn)<\/strong> is <strong>paramagnetic<\/strong> because of the unpaired electron in the 5p orbital.<\/li>\n<\/ul>\n\n\n\n<p>Both elements exhibit paramagnetism because they contain unpaired electrons that align with external magnetic fields.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-138.jpeg\" alt=\"\" class=\"wp-image-250629\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Identify the element as paramagnetic or diamagnetic. (a) Ti, titanium Full electron configuration = (do not use noble gas notation) Orbital box notation: 3d 4s 3p 3s 2p 2s 1s Ti is (b) Sn, tin Noble gas electron configuration = Orbital box notation: 5p 5s Sn is The Correct Answer and Explanation is: (a) Titanium [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-250628","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/250628","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=250628"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/250628\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=250628"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=250628"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=250628"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}