{"id":251382,"date":"2025-07-10T16:56:21","date_gmt":"2025-07-10T16:56:21","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=251382"},"modified":"2025-07-10T16:56:23","modified_gmt":"2025-07-10T16:56:23","slug":"be-sure-to-answer-all-parts-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/10\/be-sure-to-answer-all-parts-2\/","title":{"rendered":"Be sure to answer all parts"},"content":{"rendered":"\n<p>Be sure to answer all parts. Write a balanced equation for each reaction. a. HBr(aq) + KOH(aq) ? HBr (aq) +KOH (aq) KBR (aq) +H2O (l) Feedback Examine your products. In a neutralization reaction, water and an ionic salt are formed. Is your ionic compound charge balanced? Did you balance the equation and include the states of each substance? Ok, got it<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The reaction between hydrobromic acid (HBr) and potassium hydroxide (KOH) is a neutralization reaction. In a neutralization reaction, an acid reacts with a base to form water and an ionic salt. The reaction between HBr and KOH is no exception.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Write the reactants.<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>HBr<\/strong> is a strong acid, and in aqueous form, it dissociates completely into H+H^+H+ and Br\u2212Br^-Br\u2212 ions.<\/li>\n\n\n\n<li><strong>KOH<\/strong> is a strong base, and in aqueous form, it dissociates completely into K+K^+K+ and OH\u2212OH^-OH\u2212 ions.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Predict the products.<\/h3>\n\n\n\n<p>When these ions combine in the neutralization reaction:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>H+H^+H+ from HBr reacts with OH\u2212OH^-OH\u2212 from KOH to form <strong>water<\/strong> H2OH_2OH2\u200bO.<\/li>\n\n\n\n<li>The remaining ions K+K^+K+ and Br\u2212Br^-Br\u2212 combine to form the ionic salt <strong>potassium bromide<\/strong> (KBr), which is soluble in water.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Write the equation for the reaction.<\/h3>\n\n\n\n<p>The balanced equation is:HBr&nbsp;(aq)+KOH&nbsp;(aq)\u2192KBr&nbsp;(aq)+H2O&nbsp;(l)\\text{HBr (aq)} + \\text{KOH (aq)} \\rightarrow \\text{KBr (aq)} + \\text{H}_2\\text{O (l)}HBr&nbsp;(aq)+KOH&nbsp;(aq)\u2192KBr&nbsp;(aq)+H2\u200bO&nbsp;(l)<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Check charge balance.<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>On the left side of the equation, the ions are H+H^+H+, Br\u2212Br^-Br\u2212, K+K^+K+, and OH\u2212OH^-OH\u2212, which are all neutralized by the right side of the equation.<\/li>\n\n\n\n<li>On the right, potassium bromide (KBr) dissociates into K+K^+K+ and Br\u2212Br^-Br\u2212, and water (H\u2082O) is neutral, balancing the charges.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 5: States of matter.<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>HBr and KOH are both aqueous (aqaqaq), meaning they are dissolved in water.<\/li>\n\n\n\n<li>KBr is also aqueous (aqaqaq) because it is soluble in water.<\/li>\n\n\n\n<li>Water is a liquid (lll) at room temperature.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Final balanced equation:<\/h3>\n\n\n\n<p>HBr&nbsp;(aq)+KOH&nbsp;(aq)\u2192KBr&nbsp;(aq)+H2O&nbsp;(l)\\text{HBr (aq)} + \\text{KOH (aq)} \\rightarrow \\text{KBr (aq)} + \\text{H}_2\\text{O (l)}HBr&nbsp;(aq)+KOH&nbsp;(aq)\u2192KBr&nbsp;(aq)+H2\u200bO&nbsp;(l)<\/p>\n\n\n\n<p>This equation is now balanced in terms of both mass and charge, and the states of matter are correctly indicated.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner9-53.jpeg\" alt=\"\" class=\"wp-image-251390\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Be sure to answer all parts. Write a balanced equation for each reaction. a. HBr(aq) + KOH(aq) ? HBr (aq) +KOH (aq) KBR (aq) +H2O (l) Feedback Examine your products. In a neutralization reaction, water and an ionic salt are formed. Is your ionic compound charge balanced? Did you balance the equation and include the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-251382","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/251382","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=251382"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/251382\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=251382"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=251382"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=251382"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}