{"id":251406,"date":"2025-07-11T06:23:41","date_gmt":"2025-07-11T06:23:41","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=251406"},"modified":"2025-07-11T06:23:44","modified_gmt":"2025-07-11T06:23:44","slug":"write-a-balanced-chemical-equation-for-the-aqueous-reaction-between-potassium-hydroxide-and-hydrobromic-acid-3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/11\/write-a-balanced-chemical-equation-for-the-aqueous-reaction-between-potassium-hydroxide-and-hydrobromic-acid-3\/","title":{"rendered":"Write a balanced chemical equation for the aqueous reaction between potassium hydroxide and hydrobromic acid."},"content":{"rendered":"\n

Write a balanced chemical equation for the aqueous reaction between potassium hydroxide and hydrobromic acid. Include physical states. Question options: KOH (s) + HBr (g) \u00ae H2O (l) + KBr (aq) KOH (s) + HBr (g) \u00ae H2O (l) + KBr (s) KOH (s) + HBr (aq) \u00ae H2O (l) + KBr (s) KOH (aq) + HBr (aq) \u00ae H2O (l) + KBr (aq)<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The correct balanced chemical equation for the aqueous reaction between potassium hydroxide (KOH) and hydrobromic acid (HBr) is:KOH (aq)+HBr (aq)\u2192H2O (l)+KBr (aq)\\text{KOH (aq)} + \\text{HBr (aq)} \\rightarrow \\text{H}_2\\text{O (l)} + \\text{KBr (aq)}KOH (aq)+HBr (aq)\u2192H2\u200bO (l)+KBr (aq)<\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n
    \n
  1. Reactivity of KOH and HBr<\/strong>: Potassium hydroxide (KOH) is a strong base, and hydrobromic acid (HBr) is a strong acid. When these two substances are mixed in aqueous solution, they undergo a neutralization reaction. The general form of a neutralization reaction between an acid and a base is: acid\u00a0(aq)+base\u00a0(aq)\u2192water\u00a0(l)+salt\u00a0(aq)\\text{acid (aq)} + \\text{base (aq)} \\rightarrow \\text{water (l)} + \\text{salt (aq)}acid\u00a0(aq)+base\u00a0(aq)\u2192water\u00a0(l)+salt\u00a0(aq) In this case, the acid is HBr and the base is KOH.<\/li>\n\n\n\n
  2. Ionization in aqueous solution<\/strong>:\n
      \n
    • Potassium hydroxide dissociates into potassium ions (K\u207a) and hydroxide ions (OH\u207b) when dissolved in water: KOH\u00a0(aq)\u2192K+(aq)+OH\u2212(aq)\\text{KOH (aq)} \\rightarrow \\text{K}^+ (aq) + \\text{OH}^- (aq)KOH\u00a0(aq)\u2192K+(aq)+OH\u2212(aq)<\/li>\n\n\n\n
    • Hydrobromic acid dissociates into hydrogen ions (H\u207a) and bromide ions (Br\u207b) in water: HBr\u00a0(aq)\u2192H+(aq)+Br\u2212(aq)\\text{HBr (aq)} \\rightarrow \\text{H}^+ (aq) + \\text{Br}^- (aq)HBr\u00a0(aq)\u2192H+(aq)+Br\u2212(aq)<\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • Reaction<\/strong>:
      The hydrogen ion (H\u207a) from HBr combines with the hydroxide ion (OH\u207b) from KOH to form water (H\u2082O): H+(aq)+OH\u2212(aq)\u2192H2O\u00a0(l)\\text{H}^+ (aq) + \\text{OH}^- (aq) \\rightarrow \\text{H}_2\\text{O (l)}H+(aq)+OH\u2212(aq)\u2192H2\u200bO\u00a0(l) The potassium ion (K\u207a) pairs with the bromide ion (Br\u207b) to form potassium bromide (KBr), which remains in the aqueous state because it is soluble in water: K+(aq)+Br\u2212(aq)\u2192KBr\u00a0(aq)\\text{K}^+ (aq) + \\text{Br}^- (aq) \\rightarrow \\text{KBr (aq)}K+(aq)+Br\u2212(aq)\u2192KBr\u00a0(aq)<\/li>\n\n\n\n
    • Final balanced equation<\/strong>:
      Considering the dissociation of both the acid and the base, the final balanced equation is: KOH\u00a0(aq)+HBr\u00a0(aq)\u2192H2O\u00a0(l)+KBr\u00a0(aq)\\text{KOH (aq)} + \\text{HBr (aq)} \\rightarrow \\text{H}_2\\text{O (l)} + \\text{KBr (aq)}KOH\u00a0(aq)+HBr\u00a0(aq)\u2192H2\u200bO\u00a0(l)+KBr\u00a0(aq) This equation represents the neutralization process, where water and a soluble salt (KBr) are formed, both of which are in the correct physical states (liquid and aqueous, respectively).<\/li>\n<\/ol>\n\n\n\n

      In this equation:<\/p>\n\n\n\n

        \n
      • KOH<\/strong> and HBr<\/strong> are in aqueous form because they dissociate completely in water.<\/li>\n\n\n\n
      • H\u2082O<\/strong> is liquid because it is formed as a product of the neutralization reaction.<\/li>\n\n\n\n
      • KBr<\/strong> remains in aqueous form because it is highly soluble in water.<\/li>\n<\/ul>\n\n\n\n

        This shows that the reaction happens in solution and is typical of strong acid-strong base reactions.<\/p>\n\n\n\n

        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

        Write a balanced chemical equation for the aqueous reaction between potassium hydroxide and hydrobromic acid. Include physical states. Question options: KOH (s) + HBr (g) \u00ae H2O (l) + KBr (aq) KOH (s) + HBr (g) \u00ae H2O (l) + KBr (s) KOH (s) + HBr (aq) \u00ae H2O (l) + KBr (s) KOH (aq) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-251406","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/251406","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=251406"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/251406\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=251406"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=251406"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=251406"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}