To calculate the molar mass of baking soda (NaHCO\u2083), we need to determine the mass of each element in the compound, and then sum them up.<\/p>\n\n\n\n
The chemical formula for baking soda is NaHCO\u2083, which contains the following elements:<\/p>\n\n\n\n
- \n
- Sodium (Na)<\/li>\n\n\n\n
- Hydrogen (H)<\/li>\n\n\n\n
- Carbon (C)<\/li>\n\n\n\n
- Oxygen (O)<\/li>\n<\/ul>\n\n\n\n
Step 1: Find the atomic masses of each element<\/h3>\n\n\n\n
- \n
- Sodium (Na)<\/strong>: The atomic mass of sodium is 22.99 g\/mol<\/strong>.<\/li>\n\n\n\n
- Hydrogen (H)<\/strong>: The atomic mass of hydrogen is 1.01 g\/mol<\/strong>.<\/li>\n\n\n\n
- Carbon (C)<\/strong>: The atomic mass of carbon is 12.01 g\/mol<\/strong>.<\/li>\n\n\n\n
- Oxygen (O)<\/strong>: The atomic mass of oxygen is 16.00 g\/mol<\/strong>.<\/li>\n<\/ol>\n\n\n\n
Step 2: Multiply the atomic mass of each element by the number of atoms of that element in the compound<\/h3>\n\n\n\n
- \n
- Sodium (Na)<\/strong>: 1 atom of Na, so the mass is: 1\u00d722.99=22.99\u00a0g\/mol1 \\times 22.99 = 22.99 \\text{ g\/mol}1\u00d722.99=22.99\u00a0g\/mol<\/li>\n\n\n\n
- Hydrogen (H)<\/strong>: 1 atom of H, so the mass is: 1\u00d71.01=1.01\u00a0g\/mol1 \\times 1.01 = 1.01 \\text{ g\/mol}1\u00d71.01=1.01\u00a0g\/mol<\/li>\n\n\n\n
- Carbon (C)<\/strong>: 1 atom of C, so the mass is: 1\u00d712.01=12.01\u00a0g\/mol1 \\times 12.01 = 12.01 \\text{ g\/mol}1\u00d712.01=12.01\u00a0g\/mol<\/li>\n\n\n\n
- Oxygen (O)<\/strong>: There are 3 atoms of oxygen in NaHCO\u2083, so the mass is: 3\u00d716.00=48.00\u00a0g\/mol3 \\times 16.00 = 48.00 \\text{ g\/mol}3\u00d716.00=48.00\u00a0g\/mol<\/li>\n<\/ul>\n\n\n\n
Step 3: Add the masses of each element together<\/h3>\n\n\n\n
Now, we add all the individual atomic masses together to get the total molar mass of NaHCO\u2083:22.99\u2009g\/mol+1.01\u2009g\/mol+12.01\u2009g\/mol+48.00\u2009g\/mol=84.01\u2009g\/mol22.99 \\, \\text{g\/mol} + 1.01 \\, \\text{g\/mol} + 12.01 \\, \\text{g\/mol} + 48.00 \\, \\text{g\/mol} = 84.01 \\, \\text{g\/mol}22.99g\/mol+1.01g\/mol+12.01g\/mol+48.00g\/mol=84.01g\/mol<\/p>\n\n\n\n
Conclusion:<\/h3>\n\n\n\n
The molar mass of baking soda (NaHCO\u2083) is 84.01 g\/mol<\/strong>.<\/p>\n\n\n\n
This molar mass is the sum of the individual atomic masses of sodium, hydrogen, carbon, and oxygen, each multiplied by the number of atoms in the formula for NaHCO\u2083.<\/p>\n\n\n\n
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<\/figure>\n","protected":false},"excerpt":{"rendered":"What is the molar mass (g\/mol) of baking soda NaHCO3? Find the mass of each atom and add them together. The Correct Answer and Explanation is: To calculate the molar mass of baking soda (NaHCO\u2083), we need to determine the mass of each element in the compound, and then sum them up. The chemical formula […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-251904","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/251904","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=251904"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/251904\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=251904"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=251904"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=251904"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
- Hydrogen (H)<\/strong>: 1 atom of H, so the mass is: 1\u00d71.01=1.01\u00a0g\/mol1 \\times 1.01 = 1.01 \\text{ g\/mol}1\u00d71.01=1.01\u00a0g\/mol<\/li>\n\n\n\n
- Hydrogen (H)<\/strong>: The atomic mass of hydrogen is 1.01 g\/mol<\/strong>.<\/li>\n\n\n\n
- Sodium (Na)<\/strong>: The atomic mass of sodium is 22.99 g\/mol<\/strong>.<\/li>\n\n\n\n