{"id":251966,"date":"2025-07-11T04:26:49","date_gmt":"2025-07-11T04:26:49","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=251966"},"modified":"2025-07-11T04:26:51","modified_gmt":"2025-07-11T04:26:51","slug":"what-is-the-molecular-shape-of-hcn-3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/11\/what-is-the-molecular-shape-of-hcn-3\/","title":{"rendered":"What is the molecular shape of HCN"},"content":{"rendered":"\n<p>What is the molecular shape of HCN? bent linear angular trigonal pyramidal<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The molecular shape of <strong>HCN (Hydrogen Cyanide)<\/strong> is <strong>linear<\/strong>.<\/p>\n\n\n\n<p>Here\u2019s why:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Lewis Structure of HCN<\/strong>: The molecule consists of a central carbon (C) atom bonded to a hydrogen (H) atom and a nitrogen (N) atom. The carbon atom forms a triple bond with nitrogen, and a single bond with hydrogen.<\/li>\n\n\n\n<li><strong>Electron Groups<\/strong>: The carbon atom has two electron groups around it \u2014 one from the triple bond with nitrogen and the other from the single bond with hydrogen.<\/li>\n\n\n\n<li><strong>VSEPR Theory (Valence Shell Electron Pair Repulsion)<\/strong>: According to VSEPR theory, electron pairs (bonding or non-bonding) around a central atom arrange themselves in a way that minimizes repulsion. In the case of HCN, there are only two bonding pairs around carbon, which would place them as far apart as possible, resulting in a <strong>linear<\/strong> arrangement.<\/li>\n\n\n\n<li><strong>Bond Angles<\/strong>: In a linear geometry, the bond angle between the atoms is <strong>180\u00b0<\/strong>.<\/li>\n\n\n\n<li><strong>Molecular Shape<\/strong>: The presence of just two bonding pairs and no lone pairs on the central carbon atom dictates a linear shape, not angular, bent, or trigonal pyramidal.<\/li>\n<\/ol>\n\n\n\n<p>In summary, because the electron pairs around carbon are spread out in a linear arrangement, the molecular geometry of HCN is linear, with a bond angle of 180\u00b0. The triple bond between carbon and nitrogen is particularly strong and influences the overall shape, leading to this geometry.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-199.jpeg\" alt=\"\" class=\"wp-image-251967\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the molecular shape of HCN? bent linear angular trigonal pyramidal The Correct Answer and Explanation is: The molecular shape of HCN (Hydrogen Cyanide) is linear. Here\u2019s why: In summary, because the electron pairs around carbon are spread out in a linear arrangement, the molecular geometry of HCN is linear, with a bond angle [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-251966","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/251966","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=251966"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/251966\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=251966"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=251966"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=251966"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}