{"id":251978,"date":"2025-07-11T04:33:30","date_gmt":"2025-07-11T04:33:30","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=251978"},"modified":"2025-07-11T04:33:32","modified_gmt":"2025-07-11T04:33:32","slug":"graphing-points-in-a-piecewise-function","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/11\/graphing-points-in-a-piecewise-function\/","title":{"rendered":"Graphing Points in a Piecewise Function"},"content":{"rendered":"\n<p>Student Desmos Com Introduction: Kalie Bounan 6 to 8 Next Graphing Points in a Piecewise Function: 440 220<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-394.png\" alt=\"\" class=\"wp-image-251979\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here are the completed values for the table based on the given piecewise function.<br>x\u2081 y\u2081<br>-3 -3<br>-2 -2<br>-1 -1<br>0 0<br>1 -2<br>2 -4<br>3 -6<br>Explanation<br>The problem requires us to find the output values (y\u2081) for a set of input values (x\u2081) using a given piecewise function. A piecewise function is a function defined by multiple sub-functions, where each sub-function applies to a specific interval of the domain.<br>The function provided is:<br>f(x) = { x, if x &lt; 0<br>{ -2x, if x \u2265 0<br>To solve this, we must evaluate each x-value from the table individually. The key is to first determine which condition the x-value satisfies, either x &lt; 0 or x \u2265 0, and then apply the corresponding formula to find the y-value.<br>For the negative x-values (-3, -2, and -1), the condition x &lt; 0 is true. Therefore, we use the first formula, f(x) = x.<br>When x = -3, f(-3) = -3.<br>When x = -2, f(-2) = -2.<br>When x = -1, f(-1) = -1.<br>For the non-negative x-values (0, 1, 2, and 3), the condition x \u2265 0 is true. For these inputs, we must use the second formula, f(x) = -2x.<br>When x = 0, f(0) = -2 * 0 = 0.<br>When x = 1, f(1) = -2 * 1 = -2.<br>When x = 2, f(2) = -2 * 2 = -4.<br>When x = 3, f(3) = -2 * 3 = -6.<br>By following this process for each input, we can correctly complete the table. Each (x, y) pair represents a point that lies on the graph of this piecewise function.<br><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-202.jpeg\" alt=\"\" class=\"wp-image-251980\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Student Desmos Com Introduction: Kalie Bounan 6 to 8 Next Graphing Points in a Piecewise Function: 440 220 The Correct Answer and Explanation is: Here are the completed values for the table based on the given piecewise function.x\u2081 y\u2081-3 -3-2 -2-1 -10 01 -22 -43 -6ExplanationThe problem requires us to find the output values (y\u2081) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-251978","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/251978","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=251978"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/251978\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=251978"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=251978"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=251978"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}