{"id":252949,"date":"2025-07-11T15:31:48","date_gmt":"2025-07-11T15:31:48","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=252949"},"modified":"2025-07-11T15:31:50","modified_gmt":"2025-07-11T15:31:50","slug":"the-molar-mass-of-potassium-chlorate-is-molar-mass-for-potassium-39-1-g-mol-chlorine-35-5-g-mol-and-oxygen-16-g-mol","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/11\/the-molar-mass-of-potassium-chlorate-is-molar-mass-for-potassium-39-1-g-mol-chlorine-35-5-g-mol-and-oxygen-16-g-mol\/","title":{"rendered":"The molar mass of Potassium chlorate is molar mass for potassium = 39.1 g\/mol, chlorine = 35.5 g\/mol, and Oxygen = 16 g\/mol."},"content":{"rendered":"\n<p>The molar mass of Potassium chlorate is molar mass for potassium = 39.1 g\/mol, chlorine = 35.5 g\/mol, and Oxygen = 16 g\/mol.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-405.png\" alt=\"\" class=\"wp-image-252950\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is&nbsp;<strong>122.6&nbsp;g\/mol&nbsp;<\/strong>.<\/p>\n\n\n\n<p>To find the molar mass of a chemical compound, you must sum the molar masses of all the individual atoms in its formula. This calculation requires a few systematic steps.<\/p>\n\n\n\n<p>First, it is essential to determine the correct chemical formula for potassium chlorate. The name itself provides clues. &#8220;Potassium&#8221; refers to the element K, which is an alkali metal and forms an ion with a +1 charge (K\u207a). &#8220;Chlorate&#8221; is the name for the polyatomic ion with the formula ClO\u2083\u207b, which has a -1 charge. For a compound to be electrically neutral, the total positive charge must balance the total negative charge. In this instance, one potassium ion (K\u207a) will balance one chlorate ion (ClO\u2083\u207b). Therefore, the chemical formula for potassium chlorate is KClO\u2083.<\/p>\n\n\n\n<p>Second, we need to identify the number of atoms of each element present in one formula unit of KClO\u2083. By looking at the subscripts in the formula, we can see there is:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>One atom of Potassium (K)<\/li>\n\n\n\n<li>One atom of Chlorine (Cl)<\/li>\n\n\n\n<li>Three atoms of Oxygen (O)<\/li>\n<\/ul>\n\n\n\n<p>Third, we use the given molar masses for each element:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Potassium (K) = 39.1\u00a0g\/mol<\/li>\n\n\n\n<li>Chlorine (Cl) = 35.5\u00a0g\/mol<\/li>\n\n\n\n<li>Oxygen (O) = 16\u00a0g\/mol<\/li>\n<\/ul>\n\n\n\n<p>Finally, we calculate the total molar mass. We multiply the number of atoms of each element by its molar mass and then add all the results together.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass from potassium: 1 atom \u00d7 39.1\u00a0g\/mol\u00a0= 39.1\u00a0g\/mol<\/li>\n\n\n\n<li>Mass from chlorine: 1 atom \u00d7 35.5\u00a0g\/mol\u00a0= 35.5\u00a0g\/mol<\/li>\n\n\n\n<li>Mass from oxygen: 3 atoms \u00d7 16\u00a0g\/mol\u00a0= 48.0\u00a0g\/mol<\/li>\n<\/ul>\n\n\n\n<p>Now, we sum these values to get the molar mass of KClO\u2083:<br>Total Molar Mass = 39.1 + 35.5 + 48.0 = 122.6&nbsp;g\/mol&nbsp;.<\/p>\n\n\n\n<p>This result matches the second option in the multiple choice list, confirming it is the correct answer.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-304.jpeg\" alt=\"\" class=\"wp-image-252951\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The molar mass of Potassium chlorate is molar mass for potassium = 39.1 g\/mol, chlorine = 35.5 g\/mol, and Oxygen = 16 g\/mol. The Correct Answer and Explanation is: The correct answer is&nbsp;122.6&nbsp;g\/mol&nbsp;. To find the molar mass of a chemical compound, you must sum the molar masses of all the individual atoms in its [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-252949","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/252949","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=252949"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/252949\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=252949"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=252949"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=252949"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}