{"id":253130,"date":"2025-07-11T22:42:59","date_gmt":"2025-07-11T22:42:59","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=253130"},"modified":"2025-07-11T22:43:01","modified_gmt":"2025-07-11T22:43:01","slug":"balance-the-following-equations","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/11\/balance-the-following-equations\/","title":{"rendered":"Balance the following equations"},"content":{"rendered":"\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-415.png\" alt=\"\" class=\"wp-image-253131\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here are the balanced chemical equations:<\/p>\n\n\n\n<p><strong>a. Na\u2082CO\u2083 + 2HCl \u2192 2NaCl + CO\u2082 + H\u2082O<\/strong><br><strong>b. 3Cl\u2082 + 3KOH \u2192 2KCl + KClO\u2083 + 3HCl<\/strong><br><strong>c. 4Fe(OH)\u2082 + O\u2082 + 2H\u2082O \u2192 4Fe(OH)\u2083<\/strong><br><strong>d. 6FeSO\u2084 + K\u2082Cr\u2082O\u2087 + 7H\u2082SO\u2084 \u2192 3Fe\u2082(SO\u2084)\u2083 + Cr\u2082(SO\u2084)\u2083 + K\u2082SO\u2084 + 7H\u2082O<\/strong><br><strong>e. FeS + 2HCl \u2192 FeCl\u2082 + H\u2082S<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation of Balancing<\/h3>\n\n\n\n<p>Balancing chemical equations is a fundamental process in chemistry that ensures the law of conservation of mass is upheld. This principle dictates that matter cannot be created or destroyed during a chemical reaction. Consequently, the number of atoms for each element must be identical on both the reactant and product sides of an equation. We achieve this balance by adjusting the stoichiometric coefficients, the whole numbers placed before each chemical formula.<\/p>\n\n\n\n<p>For straightforward reactions, balancing by inspection is often sufficient. Consider equation (e),&nbsp;FeS + HCl \u2192 FeCl\u2082 + H\u2082S. We can see that the iron and sulfur atoms are already balanced. However, the products contain two chlorine atoms and two hydrogen atoms, while the reactants initially show only one of each. By placing a coefficient of 2 in front of the HCl, the equation becomes&nbsp;FeS + 2HCl \u2192 FeCl\u2082 + H\u2082S, satisfying the atom count for all elements. The same inspection method can be applied to equation (a).<\/p>\n\n\n\n<p>More complex reactions, such as (c),&nbsp;Fe(OH)\u2082 + O\u2082 + H\u2082O \u2192 Fe(OH)\u2083, benefit from a systematic algebraic approach. By assigning variable coefficients to each substance, we can set up a system of linear equations based on the atom count for each element. Solving these equations provides the simplest whole number ratio for the coefficients, which is&nbsp;4:1:2:4&nbsp;in this case.<\/p>\n\n\n\n<p>For complex oxidation reduction (redox) reactions like (d), the half reaction method is the most reliable. This involves separating the overall reaction into an oxidation half reaction (loss of electrons) and a reduction half reaction (gain of electrons). Each half reaction is independently balanced for atoms and charge. The key step is to equalize the number of electrons transferred by multiplying the half reactions by appropriate integers. Finally, the balanced half reactions are combined, and any spectator ions are reintroduced to yield the final, fully balanced molecular equation.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner9-80.jpeg\" alt=\"\" class=\"wp-image-253132\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The Correct Answer and Explanation is: Here are the balanced chemical equations: a. Na\u2082CO\u2083 + 2HCl \u2192 2NaCl + CO\u2082 + H\u2082Ob. 3Cl\u2082 + 3KOH \u2192 2KCl + KClO\u2083 + 3HClc. 4Fe(OH)\u2082 + O\u2082 + 2H\u2082O \u2192 4Fe(OH)\u2083d. 6FeSO\u2084 + K\u2082Cr\u2082O\u2087 + 7H\u2082SO\u2084 \u2192 3Fe\u2082(SO\u2084)\u2083 + Cr\u2082(SO\u2084)\u2083 + K\u2082SO\u2084 + 7H\u2082Oe. FeS + 2HCl \u2192 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-253130","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253130","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=253130"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253130\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=253130"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=253130"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=253130"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}