{"id":253784,"date":"2025-07-12T07:19:55","date_gmt":"2025-07-12T07:19:55","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=253784"},"modified":"2025-07-12T07:19:57","modified_gmt":"2025-07-12T07:19:57","slug":"complete-the-molecular-orbital-diagram-of-f2-and-f2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/12\/complete-the-molecular-orbital-diagram-of-f2-and-f2\/","title":{"rendered":"Complete the molecular orbital diagram of F2 and F2"},"content":{"rendered":"\n<p>Complete the molecular orbital diagram of F2 and F2 What is the bond order of F2 ?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To complete the molecular orbital diagram for F\u2082 (Fluorine molecule), we need to consider the molecular orbitals formed by the atomic orbitals of two fluorine atoms. Fluorine has an atomic number of 9, so each atom has 9 electrons, and for F\u2082, we have a total of 18 electrons.<\/p>\n\n\n\n<p>The molecular orbital diagram for diatomic molecules like F\u2082 can be derived from the combination of atomic orbitals (\u03c3, \u03c3*, \u03c0, and \u03c0* orbitals). Here&#8217;s the procedure for completing the molecular orbital diagram for F\u2082:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Molecular Orbitals for F\u2082<\/h3>\n\n\n\n<p>The orbitals involved in bonding for F\u2082 are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>\u03c3(2s)<\/strong>: bonding orbital formed by the overlap of the 2s orbitals from each atom.<\/li>\n\n\n\n<li>*<em>\u03c3<\/em>(2s)**: anti-bonding orbital formed by the overlap of the 2s orbitals from each atom, but out of phase.<\/li>\n\n\n\n<li><strong>\u03c3(2p_z)<\/strong>: bonding orbital formed by the overlap of the 2p orbitals along the internuclear axis.<\/li>\n\n\n\n<li><strong>\u03c0(2p_x) and \u03c0(2p_y)<\/strong>: degenerate bonding orbitals formed by the sideways overlap of the 2p orbitals in the x and y directions.<\/li>\n\n\n\n<li><em>\u03c0(2p_x) and \u03c0<\/em>(2p_y)**: degenerate anti-bonding orbitals formed by the sideways overlap of the 2p orbitals in the x and y directions, but out of phase.<\/li>\n\n\n\n<li>*<em>\u03c3<\/em>(2p_z)**: anti-bonding orbital formed by the overlap of the 2p orbitals along the internuclear axis, but out of phase.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Electron Configuration for F\u2082<\/h3>\n\n\n\n<p>Now, distribute the 18 electrons across these molecular orbitals, starting from the lowest energy orbital:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>\u03c3(2s)<\/strong> (2 electrons)<\/li>\n\n\n\n<li><em>\u03c3(2s)<\/em>* (2 electrons)<\/li>\n\n\n\n<li><strong>\u03c0(2p_x)<\/strong> and <strong>\u03c0(2p_y)<\/strong> (4 electrons)<\/li>\n\n\n\n<li><strong>\u03c3(2p_z)<\/strong> (2 electrons)<\/li>\n\n\n\n<li><em>\u03c0(2p_x)<\/em>* and <em>\u03c0(2p_y)<\/em>* (4 electrons)<\/li>\n\n\n\n<li><em>\u03c3(2p_z)<\/em>* (2 electrons)<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Bond Order Calculation<\/h3>\n\n\n\n<p>Bond order is calculated as: Bond&nbsp;Order=12\u00d7(Number&nbsp;of&nbsp;bonding&nbsp;electrons\u2212Number&nbsp;of&nbsp;anti-bonding&nbsp;electrons)\\text{Bond Order} = \\frac{1}{2} \\times (\\text{Number of bonding electrons} &#8211; \\text{Number of anti-bonding electrons})Bond&nbsp;Order=21\u200b\u00d7(Number&nbsp;of&nbsp;bonding&nbsp;electrons\u2212Number&nbsp;of&nbsp;anti-bonding&nbsp;electrons)<\/p>\n\n\n\n<p>For F\u2082:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Bonding electrons<\/strong>: 2 (\u03c3(2s)) + 4 (\u03c0(2p_x) + \u03c0(2p_y)) + 2 (\u03c3(2p_z)) = 8<\/li>\n\n\n\n<li><strong>Anti-bonding electrons<\/strong>: 2 (\u03c3*(2s)) + 4 (\u03c0*(2p_x) + \u03c0*(2p_y)) + 2 (\u03c3*(2p_z)) = 8<\/li>\n<\/ul>\n\n\n\n<p>So, the bond order for F\u2082 is: Bond&nbsp;Order=12\u00d7(8\u22128)=0\\text{Bond Order} = \\frac{1}{2} \\times (8 &#8211; 8) = 0Bond&nbsp;Order=21\u200b\u00d7(8\u22128)=0<\/p>\n\n\n\n<p>Thus, <strong>F\u2082<\/strong> has a bond order of <strong>1<\/strong>, meaning it has a single bond between the two fluorine atoms.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion<\/h3>\n\n\n\n<p>The molecular orbital diagram for F\u2082 shows that the electrons are evenly distributed between bonding and anti-bonding orbitals, which results in a bond order of 1. This bond order implies a stable bond between the two fluorine atoms. The low bond order is a characteristic feature of molecules with relatively high electronegativity like fluorine.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner9-163.jpeg\" alt=\"\" class=\"wp-image-253785\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Complete the molecular orbital diagram of F2 and F2 What is the bond order of F2 ? The Correct Answer and Explanation is: To complete the molecular orbital diagram for F\u2082 (Fluorine molecule), we need to consider the molecular orbitals formed by the atomic orbitals of two fluorine atoms. Fluorine has an atomic number of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-253784","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253784","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=253784"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253784\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=253784"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=253784"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=253784"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}