To calculate the thermodynamic properties cpc_pcp\u200b, cvc_vcv\u200b, eee, and hhh (specific heat at constant pressure, specific heat at constant volume, internal energy, and enthalpy) for the given scenarios, we need to make use of specific formulas and relationships from thermodynamics, particularly for an ideal gas.<\/p>\n\n\n\n
1. High-Speed Missile at Stagnation Point:<\/strong><\/h3>\n\n\n\nGiven:<\/p>\n\n\n\n
\n- Temperature (T)<\/strong> = 934 \u00b0R<\/li>\n\n\n\n
- Pressure (P)<\/strong> = 7.8 atm<\/li>\n\n\n\n
- R<\/strong> (specific gas constant for air) \u2248 287 J\/(kg\u00b7K)<\/li>\n\n\n\n
- Gas constant R<\/strong> = 287 J\/(kg\u00b7K)<\/li>\n\n\n\n
- Ideal gas behavior is assumed<\/strong> for air.<\/li>\n<\/ul>\n\n\n\n
a. cpc_pcp\u200b and cvc_vcv\u200b:<\/h4>\n\n\n\n\n- For air, the specific heat ratio (\u03b3\\gamma\u03b3) is approximately 1.4.<\/li>\n\n\n\n
- The relationship between cpc_pcp\u200b and cvc_vcv\u200b is given by the formula: \u03b3=cpcv\\gamma = \\frac{c_p}{c_v}\u03b3=cv\u200bcp\u200b\u200b and also: cp\u2212cv=Rc_p – c_v = Rcp\u200b\u2212cv\u200b=R Using these, we can calculate cpc_pcp\u200b and cvc_vcv\u200b. First, find cvc_vcv\u200b and cpc_pcp\u200b by solving: cp=\u03b3\u22c5cvc_p = \\gamma \\cdot c_vcp\u200b=\u03b3\u22c5cv\u200b and cp\u2212cv=Rc_p – c_v = Rcp\u200b\u2212cv\u200b=R Substituting: cp=1.4\u22c5cvc_p = 1.4 \\cdot c_vcp\u200b=1.4\u22c5cv\u200b 1.4\u22c5cv\u2212cv=2871.4 \\cdot c_v – c_v = 2871.4\u22c5cv\u200b\u2212cv\u200b=287 0.4\u22c5cv=2870.4 \\cdot c_v = 2870.4\u22c5cv\u200b=287 cv=2870.4=717.5\u2009J\/kg\\cdotpKc_v = \\frac{287}{0.4} = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=0.4287\u200b=717.5J\/kg\\cdotpK Then, calculate cpc_pcp\u200b: cp=1.4\u22c5717.5=1004.5\u2009J\/kg\\cdotpKc_p = 1.4 \\cdot 717.5 = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1.4\u22c5717.5=1004.5J\/kg\\cdotpK<\/li>\n<\/ul>\n\n\n\n
b. Enthalpy (h)<\/strong> and Internal Energy (e)<\/strong>:<\/h4>\n\n\n\n\n- Enthalpy is given by: h=cp\u22c5Th = c_p \\cdot Th=cp\u200b\u22c5T Substituting cp=1004.5c_p = 1004.5cp\u200b=1004.5 J\/kg\u00b7K and T=934T = 934T=934 \u00b0R (convert to Kelvin by subtracting 459.67): T=934\u2212459.67=474.33\u2009KT = 934 – 459.67 = 474.33 \\, \\text{K}T=934\u2212459.67=474.33K h=1004.5\u22c5474.33=476,922.4\u2009J\/kgh = 1004.5 \\cdot 474.33 = 476,922.4 \\, \\text{J\/kg}h=1004.5\u22c5474.33=476,922.4J\/kg<\/li>\n\n\n\n
- Internal energy is given by: e=cv\u22c5Te = c_v \\cdot Te=cv\u200b\u22c5T e=717.5\u22c5474.33=340,649.7\u2009J\/kge = 717.5 \\cdot 474.33 = 340,649.7 \\, \\text{J\/kg}e=717.5\u22c5474.33=340,649.7J\/kg<\/li>\n<\/ul>\n\n\n\n
2. Standard Sea Level Conditions:<\/strong><\/h3>\n\n\n\nAt standard sea level conditions:<\/p>\n\n\n\n
\n- Pressure (P)<\/strong> = 1 atm<\/li>\n\n\n\n
- Temperature (T)<\/strong> = 288.15 K (standard temperature)<\/li>\n\n\n\n
- R<\/strong> = 287 J\/(kg\u00b7K)<\/li>\n<\/ul>\n\n\n\n
Using the same process, you can calculate cpc_pcp\u200b, cvc_vcv\u200b, hhh, and eee for these conditions as we did for the missile case.<\/p>\n\n\n\n
a. Specific Heats:<\/strong><\/h4>\n\n\n\n\n- Using \u03b3=1.4\\gamma = 1.4\u03b3=1.4 for air, we find: cv=287\/0.4=717.5\u2009J\/kg\\cdotpKc_v = 287 \/ 0.4 = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=287\/0.4=717.5J\/kg\\cdotpK cp=1.4\u22c5717.5=1004.5\u2009J\/kg\\cdotpKc_p = 1.4 \\cdot 717.5 = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1.4\u22c5717.5=1004.5J\/kg\\cdotpK<\/li>\n<\/ul>\n\n\n\n
b. Enthalpy and Internal Energy:<\/strong><\/h4>\n\n\n\n\n- Enthalpy: h=1004.5\u22c5288.15=289,858.6\u2009J\/kgh = 1004.5 \\cdot 288.15 = 289,858.6 \\, \\text{J\/kg}h=1004.5\u22c5288.15=289,858.6J\/kg<\/li>\n\n\n\n
- Internal energy: e=717.5\u22c5288.15=206,624.3\u2009J\/kge = 717.5 \\cdot 288.15 = 206,624.3 \\, \\text{J\/kg}e=717.5\u22c5288.15=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
Summary of Results:<\/h3>\n\n\n\nFor the High-Speed Missile:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=476,922.4\u2009J\/kgh = 476,922.4 \\, \\text{J\/kg}h=476,922.4J\/kg<\/li>\n\n\n\n
- e=340,649.7\u2009J\/kge = 340,649.7 \\, \\text{J\/kg}e=340,649.7J\/kg<\/li>\n<\/ul>\n\n\n\n
For Standard Sea-Level Conditions:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=289,858.6\u2009J\/kgh = 289,858.6 \\, \\text{J\/kg}h=289,858.6J\/kg<\/li>\n\n\n\n
- e=206,624.3\u2009J\/kge = 206,624.3 \\, \\text{J\/kg}e=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
![\"\"](\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-348.jpeg\")
<\/figure>\n","protected":false},"excerpt":{"rendered":"1 atm = 2116 lb\/ft2 = 1.01 \u00c3\u2014 10^5 N\/m^2. Calculate cp, cv, e, and h for a. The stagnation point of a high-speed missile at 934 \u00c2\u00b0R and 7.8 atm, respectively. b. Air at standard sea level conditions. The Correct Answer and Explanation is: To calculate the thermodynamic properties cpc_pcp\u200b, cvc_vcv\u200b, eee, and hhh […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-253852","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=253852"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=253852"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=253852"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=253852"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
a. cpc_pcp\u200b and cvc_vcv\u200b:<\/h4>\n\n\n\n\n- For air, the specific heat ratio (\u03b3\\gamma\u03b3) is approximately 1.4.<\/li>\n\n\n\n
- The relationship between cpc_pcp\u200b and cvc_vcv\u200b is given by the formula: \u03b3=cpcv\\gamma = \\frac{c_p}{c_v}\u03b3=cv\u200bcp\u200b\u200b and also: cp\u2212cv=Rc_p – c_v = Rcp\u200b\u2212cv\u200b=R Using these, we can calculate cpc_pcp\u200b and cvc_vcv\u200b. First, find cvc_vcv\u200b and cpc_pcp\u200b by solving: cp=\u03b3\u22c5cvc_p = \\gamma \\cdot c_vcp\u200b=\u03b3\u22c5cv\u200b and cp\u2212cv=Rc_p – c_v = Rcp\u200b\u2212cv\u200b=R Substituting: cp=1.4\u22c5cvc_p = 1.4 \\cdot c_vcp\u200b=1.4\u22c5cv\u200b 1.4\u22c5cv\u2212cv=2871.4 \\cdot c_v – c_v = 2871.4\u22c5cv\u200b\u2212cv\u200b=287 0.4\u22c5cv=2870.4 \\cdot c_v = 2870.4\u22c5cv\u200b=287 cv=2870.4=717.5\u2009J\/kg\\cdotpKc_v = \\frac{287}{0.4} = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=0.4287\u200b=717.5J\/kg\\cdotpK Then, calculate cpc_pcp\u200b: cp=1.4\u22c5717.5=1004.5\u2009J\/kg\\cdotpKc_p = 1.4 \\cdot 717.5 = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1.4\u22c5717.5=1004.5J\/kg\\cdotpK<\/li>\n<\/ul>\n\n\n\n
b. Enthalpy (h)<\/strong> and Internal Energy (e)<\/strong>:<\/h4>\n\n\n\n\n- Enthalpy is given by: h=cp\u22c5Th = c_p \\cdot Th=cp\u200b\u22c5T Substituting cp=1004.5c_p = 1004.5cp\u200b=1004.5 J\/kg\u00b7K and T=934T = 934T=934 \u00b0R (convert to Kelvin by subtracting 459.67): T=934\u2212459.67=474.33\u2009KT = 934 – 459.67 = 474.33 \\, \\text{K}T=934\u2212459.67=474.33K h=1004.5\u22c5474.33=476,922.4\u2009J\/kgh = 1004.5 \\cdot 474.33 = 476,922.4 \\, \\text{J\/kg}h=1004.5\u22c5474.33=476,922.4J\/kg<\/li>\n\n\n\n
- Internal energy is given by: e=cv\u22c5Te = c_v \\cdot Te=cv\u200b\u22c5T e=717.5\u22c5474.33=340,649.7\u2009J\/kge = 717.5 \\cdot 474.33 = 340,649.7 \\, \\text{J\/kg}e=717.5\u22c5474.33=340,649.7J\/kg<\/li>\n<\/ul>\n\n\n\n
2. Standard Sea Level Conditions:<\/strong><\/h3>\n\n\n\nAt standard sea level conditions:<\/p>\n\n\n\n
\n- Pressure (P)<\/strong> = 1 atm<\/li>\n\n\n\n
- Temperature (T)<\/strong> = 288.15 K (standard temperature)<\/li>\n\n\n\n
- R<\/strong> = 287 J\/(kg\u00b7K)<\/li>\n<\/ul>\n\n\n\n
Using the same process, you can calculate cpc_pcp\u200b, cvc_vcv\u200b, hhh, and eee for these conditions as we did for the missile case.<\/p>\n\n\n\n
a. Specific Heats:<\/strong><\/h4>\n\n\n\n\n- Using \u03b3=1.4\\gamma = 1.4\u03b3=1.4 for air, we find: cv=287\/0.4=717.5\u2009J\/kg\\cdotpKc_v = 287 \/ 0.4 = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=287\/0.4=717.5J\/kg\\cdotpK cp=1.4\u22c5717.5=1004.5\u2009J\/kg\\cdotpKc_p = 1.4 \\cdot 717.5 = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1.4\u22c5717.5=1004.5J\/kg\\cdotpK<\/li>\n<\/ul>\n\n\n\n
b. Enthalpy and Internal Energy:<\/strong><\/h4>\n\n\n\n\n- Enthalpy: h=1004.5\u22c5288.15=289,858.6\u2009J\/kgh = 1004.5 \\cdot 288.15 = 289,858.6 \\, \\text{J\/kg}h=1004.5\u22c5288.15=289,858.6J\/kg<\/li>\n\n\n\n
- Internal energy: e=717.5\u22c5288.15=206,624.3\u2009J\/kge = 717.5 \\cdot 288.15 = 206,624.3 \\, \\text{J\/kg}e=717.5\u22c5288.15=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
Summary of Results:<\/h3>\n\n\n\nFor the High-Speed Missile:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=476,922.4\u2009J\/kgh = 476,922.4 \\, \\text{J\/kg}h=476,922.4J\/kg<\/li>\n\n\n\n
- e=340,649.7\u2009J\/kge = 340,649.7 \\, \\text{J\/kg}e=340,649.7J\/kg<\/li>\n<\/ul>\n\n\n\n
For Standard Sea-Level Conditions:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=289,858.6\u2009J\/kgh = 289,858.6 \\, \\text{J\/kg}h=289,858.6J\/kg<\/li>\n\n\n\n
- e=206,624.3\u2009J\/kge = 206,624.3 \\, \\text{J\/kg}e=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
<\/figure>\n","protected":false},"excerpt":{"rendered":"1 atm = 2116 lb\/ft2 = 1.01 \u00c3\u2014 10^5 N\/m^2. Calculate cp, cv, e, and h for a. The stagnation point of a high-speed missile at 934 \u00c2\u00b0R and 7.8 atm, respectively. b. Air at standard sea level conditions. The Correct Answer and Explanation is: To calculate the thermodynamic properties cpc_pcp\u200b, cvc_vcv\u200b, eee, and hhh […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-253852","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=253852"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=253852"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=253852"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=253852"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
b. Enthalpy (h)<\/strong> and Internal Energy (e)<\/strong>:<\/h4>\n\n\n\n\n- Enthalpy is given by: h=cp\u22c5Th = c_p \\cdot Th=cp\u200b\u22c5T Substituting cp=1004.5c_p = 1004.5cp\u200b=1004.5 J\/kg\u00b7K and T=934T = 934T=934 \u00b0R (convert to Kelvin by subtracting 459.67): T=934\u2212459.67=474.33\u2009KT = 934 – 459.67 = 474.33 \\, \\text{K}T=934\u2212459.67=474.33K h=1004.5\u22c5474.33=476,922.4\u2009J\/kgh = 1004.5 \\cdot 474.33 = 476,922.4 \\, \\text{J\/kg}h=1004.5\u22c5474.33=476,922.4J\/kg<\/li>\n\n\n\n
- Internal energy is given by: e=cv\u22c5Te = c_v \\cdot Te=cv\u200b\u22c5T e=717.5\u22c5474.33=340,649.7\u2009J\/kge = 717.5 \\cdot 474.33 = 340,649.7 \\, \\text{J\/kg}e=717.5\u22c5474.33=340,649.7J\/kg<\/li>\n<\/ul>\n\n\n\n
2. Standard Sea Level Conditions:<\/strong><\/h3>\n\n\n\nAt standard sea level conditions:<\/p>\n\n\n\n
\n- Pressure (P)<\/strong> = 1 atm<\/li>\n\n\n\n
- Temperature (T)<\/strong> = 288.15 K (standard temperature)<\/li>\n\n\n\n
- R<\/strong> = 287 J\/(kg\u00b7K)<\/li>\n<\/ul>\n\n\n\n
Using the same process, you can calculate cpc_pcp\u200b, cvc_vcv\u200b, hhh, and eee for these conditions as we did for the missile case.<\/p>\n\n\n\n
a. Specific Heats:<\/strong><\/h4>\n\n\n\n\n- Using \u03b3=1.4\\gamma = 1.4\u03b3=1.4 for air, we find: cv=287\/0.4=717.5\u2009J\/kg\\cdotpKc_v = 287 \/ 0.4 = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=287\/0.4=717.5J\/kg\\cdotpK cp=1.4\u22c5717.5=1004.5\u2009J\/kg\\cdotpKc_p = 1.4 \\cdot 717.5 = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1.4\u22c5717.5=1004.5J\/kg\\cdotpK<\/li>\n<\/ul>\n\n\n\n
b. Enthalpy and Internal Energy:<\/strong><\/h4>\n\n\n\n\n- Enthalpy: h=1004.5\u22c5288.15=289,858.6\u2009J\/kgh = 1004.5 \\cdot 288.15 = 289,858.6 \\, \\text{J\/kg}h=1004.5\u22c5288.15=289,858.6J\/kg<\/li>\n\n\n\n
- Internal energy: e=717.5\u22c5288.15=206,624.3\u2009J\/kge = 717.5 \\cdot 288.15 = 206,624.3 \\, \\text{J\/kg}e=717.5\u22c5288.15=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
Summary of Results:<\/h3>\n\n\n\nFor the High-Speed Missile:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=476,922.4\u2009J\/kgh = 476,922.4 \\, \\text{J\/kg}h=476,922.4J\/kg<\/li>\n\n\n\n
- e=340,649.7\u2009J\/kge = 340,649.7 \\, \\text{J\/kg}e=340,649.7J\/kg<\/li>\n<\/ul>\n\n\n\n
For Standard Sea-Level Conditions:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=289,858.6\u2009J\/kgh = 289,858.6 \\, \\text{J\/kg}h=289,858.6J\/kg<\/li>\n\n\n\n
- e=206,624.3\u2009J\/kge = 206,624.3 \\, \\text{J\/kg}e=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
<\/figure>\n","protected":false},"excerpt":{"rendered":"1 atm = 2116 lb\/ft2 = 1.01 \u00c3\u2014 10^5 N\/m^2. Calculate cp, cv, e, and h for a. The stagnation point of a high-speed missile at 934 \u00c2\u00b0R and 7.8 atm, respectively. b. Air at standard sea level conditions. The Correct Answer and Explanation is: To calculate the thermodynamic properties cpc_pcp\u200b, cvc_vcv\u200b, eee, and hhh […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-253852","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=253852"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=253852"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=253852"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=253852"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
2. Standard Sea Level Conditions:<\/strong><\/h3>\n\n\n\nAt standard sea level conditions:<\/p>\n\n\n\n
\n- Pressure (P)<\/strong> = 1 atm<\/li>\n\n\n\n
- Temperature (T)<\/strong> = 288.15 K (standard temperature)<\/li>\n\n\n\n
- R<\/strong> = 287 J\/(kg\u00b7K)<\/li>\n<\/ul>\n\n\n\n
Using the same process, you can calculate cpc_pcp\u200b, cvc_vcv\u200b, hhh, and eee for these conditions as we did for the missile case.<\/p>\n\n\n\n
a. Specific Heats:<\/strong><\/h4>\n\n\n\n\n- Using \u03b3=1.4\\gamma = 1.4\u03b3=1.4 for air, we find: cv=287\/0.4=717.5\u2009J\/kg\\cdotpKc_v = 287 \/ 0.4 = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=287\/0.4=717.5J\/kg\\cdotpK cp=1.4\u22c5717.5=1004.5\u2009J\/kg\\cdotpKc_p = 1.4 \\cdot 717.5 = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1.4\u22c5717.5=1004.5J\/kg\\cdotpK<\/li>\n<\/ul>\n\n\n\n
b. Enthalpy and Internal Energy:<\/strong><\/h4>\n\n\n\n\n- Enthalpy: h=1004.5\u22c5288.15=289,858.6\u2009J\/kgh = 1004.5 \\cdot 288.15 = 289,858.6 \\, \\text{J\/kg}h=1004.5\u22c5288.15=289,858.6J\/kg<\/li>\n\n\n\n
- Internal energy: e=717.5\u22c5288.15=206,624.3\u2009J\/kge = 717.5 \\cdot 288.15 = 206,624.3 \\, \\text{J\/kg}e=717.5\u22c5288.15=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
Summary of Results:<\/h3>\n\n\n\nFor the High-Speed Missile:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=476,922.4\u2009J\/kgh = 476,922.4 \\, \\text{J\/kg}h=476,922.4J\/kg<\/li>\n\n\n\n
- e=340,649.7\u2009J\/kge = 340,649.7 \\, \\text{J\/kg}e=340,649.7J\/kg<\/li>\n<\/ul>\n\n\n\n
For Standard Sea-Level Conditions:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=289,858.6\u2009J\/kgh = 289,858.6 \\, \\text{J\/kg}h=289,858.6J\/kg<\/li>\n\n\n\n
- e=206,624.3\u2009J\/kge = 206,624.3 \\, \\text{J\/kg}e=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
<\/figure>\n","protected":false},"excerpt":{"rendered":"1 atm = 2116 lb\/ft2 = 1.01 \u00c3\u2014 10^5 N\/m^2. Calculate cp, cv, e, and h for a. The stagnation point of a high-speed missile at 934 \u00c2\u00b0R and 7.8 atm, respectively. b. Air at standard sea level conditions. The Correct Answer and Explanation is: To calculate the thermodynamic properties cpc_pcp\u200b, cvc_vcv\u200b, eee, and hhh […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-253852","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=253852"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=253852"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=253852"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=253852"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Using the same process, you can calculate cpc_pcp\u200b, cvc_vcv\u200b, hhh, and eee for these conditions as we did for the missile case.<\/p>\n\n\n\n
a. Specific Heats:<\/strong><\/h4>\n\n\n\n\n- Using \u03b3=1.4\\gamma = 1.4\u03b3=1.4 for air, we find: cv=287\/0.4=717.5\u2009J\/kg\\cdotpKc_v = 287 \/ 0.4 = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=287\/0.4=717.5J\/kg\\cdotpK cp=1.4\u22c5717.5=1004.5\u2009J\/kg\\cdotpKc_p = 1.4 \\cdot 717.5 = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1.4\u22c5717.5=1004.5J\/kg\\cdotpK<\/li>\n<\/ul>\n\n\n\n
b. Enthalpy and Internal Energy:<\/strong><\/h4>\n\n\n\n\n- Enthalpy: h=1004.5\u22c5288.15=289,858.6\u2009J\/kgh = 1004.5 \\cdot 288.15 = 289,858.6 \\, \\text{J\/kg}h=1004.5\u22c5288.15=289,858.6J\/kg<\/li>\n\n\n\n
- Internal energy: e=717.5\u22c5288.15=206,624.3\u2009J\/kge = 717.5 \\cdot 288.15 = 206,624.3 \\, \\text{J\/kg}e=717.5\u22c5288.15=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
Summary of Results:<\/h3>\n\n\n\nFor the High-Speed Missile:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=476,922.4\u2009J\/kgh = 476,922.4 \\, \\text{J\/kg}h=476,922.4J\/kg<\/li>\n\n\n\n
- e=340,649.7\u2009J\/kge = 340,649.7 \\, \\text{J\/kg}e=340,649.7J\/kg<\/li>\n<\/ul>\n\n\n\n
For Standard Sea-Level Conditions:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=289,858.6\u2009J\/kgh = 289,858.6 \\, \\text{J\/kg}h=289,858.6J\/kg<\/li>\n\n\n\n
- e=206,624.3\u2009J\/kge = 206,624.3 \\, \\text{J\/kg}e=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
<\/figure>\n","protected":false},"excerpt":{"rendered":"1 atm = 2116 lb\/ft2 = 1.01 \u00c3\u2014 10^5 N\/m^2. Calculate cp, cv, e, and h for a. The stagnation point of a high-speed missile at 934 \u00c2\u00b0R and 7.8 atm, respectively. b. Air at standard sea level conditions. The Correct Answer and Explanation is: To calculate the thermodynamic properties cpc_pcp\u200b, cvc_vcv\u200b, eee, and hhh […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-253852","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=253852"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=253852"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=253852"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=253852"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
b. Enthalpy and Internal Energy:<\/strong><\/h4>\n\n\n\n\n- Enthalpy: h=1004.5\u22c5288.15=289,858.6\u2009J\/kgh = 1004.5 \\cdot 288.15 = 289,858.6 \\, \\text{J\/kg}h=1004.5\u22c5288.15=289,858.6J\/kg<\/li>\n\n\n\n
- Internal energy: e=717.5\u22c5288.15=206,624.3\u2009J\/kge = 717.5 \\cdot 288.15 = 206,624.3 \\, \\text{J\/kg}e=717.5\u22c5288.15=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
Summary of Results:<\/h3>\n\n\n\nFor the High-Speed Missile:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=476,922.4\u2009J\/kgh = 476,922.4 \\, \\text{J\/kg}h=476,922.4J\/kg<\/li>\n\n\n\n
- e=340,649.7\u2009J\/kge = 340,649.7 \\, \\text{J\/kg}e=340,649.7J\/kg<\/li>\n<\/ul>\n\n\n\n
For Standard Sea-Level Conditions:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=289,858.6\u2009J\/kgh = 289,858.6 \\, \\text{J\/kg}h=289,858.6J\/kg<\/li>\n\n\n\n
- e=206,624.3\u2009J\/kge = 206,624.3 \\, \\text{J\/kg}e=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
<\/figure>\n","protected":false},"excerpt":{"rendered":"1 atm = 2116 lb\/ft2 = 1.01 \u00c3\u2014 10^5 N\/m^2. Calculate cp, cv, e, and h for a. The stagnation point of a high-speed missile at 934 \u00c2\u00b0R and 7.8 atm, respectively. b. Air at standard sea level conditions. The Correct Answer and Explanation is: To calculate the thermodynamic properties cpc_pcp\u200b, cvc_vcv\u200b, eee, and hhh […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-253852","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=253852"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=253852"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=253852"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=253852"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Summary of Results:<\/h3>\n\n\n\nFor the High-Speed Missile:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=476,922.4\u2009J\/kgh = 476,922.4 \\, \\text{J\/kg}h=476,922.4J\/kg<\/li>\n\n\n\n
- e=340,649.7\u2009J\/kge = 340,649.7 \\, \\text{J\/kg}e=340,649.7J\/kg<\/li>\n<\/ul>\n\n\n\n
For Standard Sea-Level Conditions:<\/h4>\n\n\n\n\n- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=289,858.6\u2009J\/kgh = 289,858.6 \\, \\text{J\/kg}h=289,858.6J\/kg<\/li>\n\n\n\n
- e=206,624.3\u2009J\/kge = 206,624.3 \\, \\text{J\/kg}e=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n
<\/figure>\n","protected":false},"excerpt":{"rendered":"1 atm = 2116 lb\/ft2 = 1.01 \u00c3\u2014 10^5 N\/m^2. Calculate cp, cv, e, and h for a. The stagnation point of a high-speed missile at 934 \u00c2\u00b0R and 7.8 atm, respectively. b. Air at standard sea level conditions. The Correct Answer and Explanation is: To calculate the thermodynamic properties cpc_pcp\u200b, cvc_vcv\u200b, eee, and hhh […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-253852","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=253852"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=253852"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=253852"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=253852"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
- \n
- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=476,922.4\u2009J\/kgh = 476,922.4 \\, \\text{J\/kg}h=476,922.4J\/kg<\/li>\n\n\n\n
- e=340,649.7\u2009J\/kge = 340,649.7 \\, \\text{J\/kg}e=340,649.7J\/kg<\/li>\n<\/ul>\n\n\n\n
For Standard Sea-Level Conditions:<\/h4>\n\n\n\n
- \n
- cp=1004.5\u2009J\/kg\\cdotpKc_p = 1004.5 \\, \\text{J\/kg\u00b7K}cp\u200b=1004.5J\/kg\\cdotpK<\/li>\n\n\n\n
- cv=717.5\u2009J\/kg\\cdotpKc_v = 717.5 \\, \\text{J\/kg\u00b7K}cv\u200b=717.5J\/kg\\cdotpK<\/li>\n\n\n\n
- h=289,858.6\u2009J\/kgh = 289,858.6 \\, \\text{J\/kg}h=289,858.6J\/kg<\/li>\n\n\n\n
- e=206,624.3\u2009J\/kge = 206,624.3 \\, \\text{J\/kg}e=206,624.3J\/kg<\/li>\n<\/ul>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"
1 atm = 2116 lb\/ft2 = 1.01 \u00c3\u2014 10^5 N\/m^2. Calculate cp, cv, e, and h for a. The stagnation point of a high-speed missile at 934 \u00c2\u00b0R and 7.8 atm, respectively. b. Air at standard sea level conditions. The Correct Answer and Explanation is: To calculate the thermodynamic properties cpc_pcp\u200b, cvc_vcv\u200b, eee, and hhh […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-253852","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=253852"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253852\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=253852"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=253852"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=253852"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}