{"id":253859,"date":"2025-07-12T07:43:07","date_gmt":"2025-07-12T07:43:07","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=253859"},"modified":"2025-07-12T07:43:09","modified_gmt":"2025-07-12T07:43:09","slug":"francis-heard-that-a-car-stereo-system-was-on-sale-for-30-off","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/12\/francis-heard-that-a-car-stereo-system-was-on-sale-for-30-off\/","title":{"rendered":"Francis heard that a car stereo system was on sale for 30% off"},"content":{"rendered":"\n<p>Francis heard that a car stereo system was on sale for 30% off. If the sale price was $57.75, what was the original price of the stereo? (needs proportion, work and solution)<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To solve this problem, we can use a proportion to find the original price of the stereo.<\/p>\n\n\n\n<p>Let the original price of the stereo be represented by xx.<\/p>\n\n\n\n<p>The stereo is on sale for 30% off, meaning the sale price is 70% of the original price, because 100% &#8211; 30% = 70%. Therefore, the relationship between the original price and the sale price can be written as: 70100=57.75x\\frac{70}{100} = \\frac{57.75}{x}<\/p>\n\n\n\n<p>This proportion states that 70% of the original price equals the sale price of $57.75. To solve for xx, we can cross-multiply: 70\u00d7x=100\u00d757.7570 \\times x = 100 \\times 57.75<\/p>\n\n\n\n<p>Simplifying the right-hand side: 70x=577570x = 5775<\/p>\n\n\n\n<p>Now, divide both sides of the equation by 70 to isolate xx: x=577570x = \\frac{5775}{70} x=82.50x = 82.50<\/p>\n\n\n\n<p>Thus, the original price of the stereo was <strong>$82.50<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>The problem is based on applying a proportion to represent the relationship between the sale price and the original price. Since the stereo was on sale for 30% off, the sale price was 70% of the original price. Setting up a proportion allows us to solve for the original price algebraically. After cross-multiplying and simplifying, we find the original price to be $82.50. This approach of using proportions is a common way to solve percentage-based price discount problems.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Francis heard that a car stereo system was on sale for 30% off. If the sale price was $57.75, what was the original price of the stereo? (needs proportion, work and solution) The correct answer and explanation is: To solve this problem, we can use a proportion to find the original price of the stereo. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-253859","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253859","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=253859"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/253859\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=253859"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=253859"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=253859"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}