{"id":254516,"date":"2025-07-12T14:30:26","date_gmt":"2025-07-12T14:30:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=254516"},"modified":"2025-07-12T14:30:29","modified_gmt":"2025-07-12T14:30:29","slug":"what-is-the-percent-composition-for-each-element-in-magnesium-chloride","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/12\/what-is-the-percent-composition-for-each-element-in-magnesium-chloride\/","title":{"rendered":"what is the percent composition for each element in magnesium chloride"},"content":{"rendered":"\n<p>what is the percent composition for each element in magnesium chloride?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The percent composition of an element in a compound tells us what fraction of the total mass of the compound comes from that element. To calculate the percent composition of each element in magnesium chloride (MgCl\u2082), we need to first determine the molar mass of the compound and then calculate the mass contribution of each element.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Find the molar mass of MgCl\u2082<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Magnesium (Mg) has a molar mass of <strong>24.31 g\/mol<\/strong>.<\/li>\n\n\n\n<li>Chlorine (Cl) has a molar mass of <strong>35.45 g\/mol<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>Since there are two chlorine atoms in magnesium chloride, the molar mass of MgCl\u2082 is calculated as: Molar&nbsp;mass&nbsp;of&nbsp;MgCl\u2082=24.31\u2009g\/mol+2\u00d735.45\u2009g\/mol\\text{Molar mass of MgCl\u2082} = 24.31 \\, \\text{g\/mol} + 2 \\times 35.45 \\, \\text{g\/mol}Molar&nbsp;mass&nbsp;of&nbsp;MgCl\u2082=24.31g\/mol+2\u00d735.45g\/mol Molar&nbsp;mass&nbsp;of&nbsp;MgCl\u2082=24.31\u2009g\/mol+70.90\u2009g\/mol=95.21\u2009g\/mol\\text{Molar mass of MgCl\u2082} = 24.31 \\, \\text{g\/mol} + 70.90 \\, \\text{g\/mol} = 95.21 \\, \\text{g\/mol}Molar&nbsp;mass&nbsp;of&nbsp;MgCl\u2082=24.31g\/mol+70.90g\/mol=95.21g\/mol<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Calculate the mass contribution of each element<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The mass of magnesium (Mg) in MgCl\u2082 is 24.31 g.<\/li>\n\n\n\n<li>The mass of chlorine (Cl) in MgCl\u2082 is <strong>2 \u00d7 35.45 g = 70.90 g<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Calculate the percent composition of each element<\/h3>\n\n\n\n<p>The percent composition is calculated by dividing the mass of each element by the total molar mass of the compound and then multiplying by 100.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Percent composition of magnesium (Mg)<\/strong>:<\/li>\n<\/ul>\n\n\n\n<p>24.31\u2009g95.21\u2009g\/mol\u00d7100=25.55%\\frac{24.31 \\, \\text{g}}{95.21 \\, \\text{g\/mol}} \\times 100 = 25.55\\%95.21g\/mol24.31g\u200b\u00d7100=25.55%<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Percent composition of chlorine (Cl)<\/strong>:<\/li>\n<\/ul>\n\n\n\n<p>70.90\u2009g95.21\u2009g\/mol\u00d7100=74.45%\\frac{70.90 \\, \\text{g}}{95.21 \\, \\text{g\/mol}} \\times 100 = 74.45\\%95.21g\/mol70.90g\u200b\u00d7100=74.45%<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The percent composition of magnesium (Mg) in magnesium chloride is <strong>25.55%<\/strong>.<\/li>\n\n\n\n<li>The percent composition of chlorine (Cl) in magnesium chloride is <strong>74.45%<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>This method shows how the total mass of each element contributes to the compound&#8217;s overall mass.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-397.jpeg\" alt=\"\" class=\"wp-image-254517\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>what is the percent composition for each element in magnesium chloride? The Correct Answer and Explanation is: The percent composition of an element in a compound tells us what fraction of the total mass of the compound comes from that element. To calculate the percent composition of each element in magnesium chloride (MgCl\u2082), we need [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-254516","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/254516","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=254516"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/254516\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=254516"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=254516"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=254516"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}