{"id":254679,"date":"2025-07-12T16:11:53","date_gmt":"2025-07-12T16:11:53","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=254679"},"modified":"2025-07-12T16:11:55","modified_gmt":"2025-07-12T16:11:55","slug":"naoh-h2o-naoh-h2o-naoh-h2o","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/12\/naoh-h2o-naoh-h2o-naoh-h2o\/","title":{"rendered":"NaOH; H2O NaOH; H2O NaOH; H2O"},"content":{"rendered":"\n<p>NaOH; H2O NaOH; H2O NaOH; H2O<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-443.png\" alt=\"\" class=\"wp-image-254681\"\/><\/figure>\n\n\n\n<p>Here are the products of the three chemical reactions:<\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">![alt text](https:\/\/i.imgur.com\/B948q8I.png)<\/pre>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>The three reactions shown are examples of the base-catalyzed&nbsp;<strong>aldol condensation<\/strong>. In this type of reaction, a strong base like sodium hydroxide (NaOH) removes an acidic proton from the alpha-carbon (the carbon adjacent to the carbonyl group) of an aldehyde or ketone. This creates a resonance-stabilized carbanion known as an&nbsp;<strong>enolate<\/strong>. The enolate is a strong nucleophile and attacks the electrophilic carbonyl carbon of another aldehyde or ketone molecule, forming a new carbon-carbon bond.<\/p>\n\n\n\n<p>This initial step, called an aldol addition, forms a \u03b2-hydroxy carbonyl compound. Under the reaction conditions, this intermediate readily loses a molecule of water (dehydration) to form a highly stable \u03b1,\u03b2-unsaturated carbonyl compound. This final product is favored due to the conjugation between the newly formed carbon-carbon double bond and the carbonyl group.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>3-Hexanone:<\/strong>\u00a0This is a self-aldol condensation. 3-Hexanone can form two different enolates. The reaction favors the pathway where the enolate forms at the C-4 position and attacks another 3-hexanone molecule. Subsequent dehydration yields the more substituted and thermodynamically stable \u03b1,\u03b2-unsaturated ketone,\u00a0<strong>4-ethyl-5-propyl-oct-4-en-3-one<\/strong>.<\/li>\n\n\n\n<li><strong>3,3-Dimethylcyclopentanone + Pivaldehyde:<\/strong>\u00a0This is a crossed-aldol condensation. A successful crossed reaction occurs because one reactant, pivaldehyde, has no \u03b1-protons and cannot form an enolate. It can only act as the electrophile. The ketone, 3,3-dimethylcyclopentanone, is the sole source of the enolate. The enolate of the ketone attacks the aldehyde, and dehydration follows, leading to\u00a0<strong>2-(2,2-dimethylpropylidene)-3,3-dimethylcyclopentanone<\/strong>.<\/li>\n\n\n\n<li><strong>Propiophenone:<\/strong>\u00a0This is another self-aldol condensation. Propiophenone has only one set of \u03b1-protons, on the methylene group (-CH\u2082-). The base forms the enolate here, which then attacks a second molecule of propiophenone. The final dehydration step is highly favorable because it creates an extensively conjugated system that includes both phenyl rings and the carbonyl group, resulting in\u00a0<strong>2-methyl-1,3-diphenylpent-2-en-1-one<\/strong>.<\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-408.jpeg\" alt=\"\" class=\"wp-image-254694\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>NaOH; H2O NaOH; H2O NaOH; H2O Here are the products of the three chemical reactions: ![alt text](https:\/\/i.imgur.com\/B948q8I.png) Explanation The three reactions shown are examples of the base-catalyzed&nbsp;aldol condensation. In this type of reaction, a strong base like sodium hydroxide (NaOH) removes an acidic proton from the alpha-carbon (the carbon adjacent to the carbonyl group) of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-254679","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/254679","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=254679"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/254679\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=254679"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=254679"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=254679"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}