{"id":255508,"date":"2025-07-13T05:40:43","date_gmt":"2025-07-13T05:40:43","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=255508"},"modified":"2025-07-13T05:40:45","modified_gmt":"2025-07-13T05:40:45","slug":"write-balanced-net-ionic-equations-for-the-reactions-that-occur-in-each-of-the-following-cases","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/13\/write-balanced-net-ionic-equations-for-the-reactions-that-occur-in-each-of-the-following-cases\/","title":{"rendered":"Write balanced net ionic equations for the reactions that occur in each of the following cases"},"content":{"rendered":"\n
Write balanced net ionic equations for the reactions that occur in each of the following cases. Identify the spectator ion or ions in each reaction: (a) Cr2(SO4)3(aq) + 3(NH4)2CO3(aq) \u00e2\u2020\u2019 2Cr(CO3)3(s) + 6NH4SO4(aq) Spectator ions: NH4+ and SO4^2- (b) Ba(NO3)2(aq) + K2SO4(aq) \u00e2\u2020\u2019 BaSO4(s) + 2KNO3(aq) Spectator ions: K+ and NO3- (c) Fe(NO2)2(aq) + 2KOH(aq) \u00e2\u2020\u2019 Fe(OH)2(s) + 2KNO2(aq) Spectator ions: K+ and NO2-<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n
Let’s break down each reaction and find the balanced net ionic equations, along with identifying the spectator ions.<\/p>\n\n\n\n
Complete Ionic Equation:<\/strong> Cr2(SO4)3(aq)+3NH4CO3(aq)\u21922Cr(CO3)3(s)+6NH4SO4(aq)\\text{Cr}_2(\\text{SO}_4)_3(aq) + 3\\text{NH}_4\\text{CO}_3(aq) \\rightarrow 2\\text{Cr}(\\text{CO}_3)_3(s) + 6\\text{NH}_4\\text{SO}_4(aq)Cr2\u200b(SO4\u200b)3\u200b(aq)+3NH4\u200bCO3\u200b(aq)\u21922Cr(CO3\u200b)3\u200b(s)+6NH4\u200bSO4\u200b(aq) This equation involves all species in their ionic forms. Ammonium sulfate (NH4SO4\\text{NH}_4\\text{SO}_4NH4\u200bSO4\u200b) and chromium sulfate (Cr2(SO4)3\\text{Cr}_2(\\text{SO}_4)_3Cr2\u200b(SO4\u200b)3\u200b) dissociate into ions.<\/li>\n\n\n\n
Dissociation into Ions:<\/strong>\n
\n
Cr2(SO4)3\\text{Cr}_2(\\text{SO}_4)_3Cr2\u200b(SO4\u200b)3\u200b dissociates into 2 Cr3+\\text{Cr}^{3+}Cr3+ and 3 SO42\u2212\\text{SO}_4^{2-}SO42\u2212\u200b.<\/li>\n\n\n\n
NH4CO3\\text{NH}_4\\text{CO}_3NH4\u200bCO3\u200b dissociates into 2 NH4+\\text{NH}_4^{+}NH4+\u200b and CO32\u2212\\text{CO}_3^{2-}CO32\u2212\u200b.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
Net Ionic Equation:<\/strong> After removing spectator ions (those that appear unchanged on both sides of the equation), we have: 2Cr3+(aq)+3CO32\u2212(aq)\u21922Cr(CO3)3(s)2\\text{Cr}^{3+}(aq) + 3\\text{CO}_3^{2-}(aq) \\rightarrow 2\\text{Cr}(\\text{CO}_3)_3(s)2Cr3+(aq)+3CO32\u2212\u200b(aq)\u21922Cr(CO3\u200b)3\u200b(s)\n
\n
Spectator ions:<\/strong> NH4+\\text{NH}_4^{+}NH4+\u200b and SO42\u2212\\text{SO}_4^{2-}SO42\u2212\u200b, as these ions do not change during the reaction.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n\n\n\n\n
Complete Ionic Equation:<\/strong> Ba(NO3)2(aq)+K2SO4(aq)\u2192BaSO4(s)+2KNO3(aq)\\text{Ba(NO}_3\\text{)}_2(aq) + \\text{K}_2\\text{SO}_4(aq) \\rightarrow \\text{BaSO}_4(s) + 2\\text{KNO}_3(aq)Ba(NO3\u200b)2\u200b(aq)+K2\u200bSO4\u200b(aq)\u2192BaSO4\u200b(s)+2KNO3\u200b(aq) Both barium nitrate and potassium sulfate dissociate into their ions.<\/li>\n\n\n\n
Dissociation into Ions:<\/strong>\n
\n
Ba(NO3)2\\text{Ba(NO}_3\\text{)}_2Ba(NO3\u200b)2\u200b dissociates into Ba2+\\text{Ba}^{2+}Ba2+ and 2 NO3\u2212\\text{NO}_3^{-}NO3\u2212\u200b.<\/li>\n\n\n\n
K2SO4\\text{K}_2\\text{SO}_4K2\u200bSO4\u200b dissociates into 2 K+\\text{K}^{+}K+ and SO42\u2212\\text{SO}_4^{2-}SO42\u2212\u200b.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
Net Ionic Equation:<\/strong> After removing spectator ions: Ba2+(aq)+SO42\u2212(aq)\u2192BaSO4(s)\\text{Ba}^{2+}(aq) + \\text{SO}_4^{2-}(aq) \\rightarrow \\text{BaSO}_4(s)Ba2+(aq)+SO42\u2212\u200b(aq)\u2192BaSO4\u200b(s)\n
\n
Spectator ions:<\/strong> K+\\text{K}^{+}K+ and NO3\u2212\\text{NO}_3^{-}NO3\u2212\u200b, which do not participate in the formation of the precipitate.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n\n\n\n\n
Complete Ionic Equation:<\/strong> Fe(NO2)2(aq)+2KOH(aq)\u2192Fe(OH)2(s)+2KNO2(aq)\\text{Fe(NO}_2\\text{)}_2(aq) + 2\\text{KOH}(aq) \\rightarrow \\text{Fe(OH)}_2(s) + 2\\text{KNO}_2(aq)Fe(NO2\u200b)2\u200b(aq)+2KOH(aq)\u2192Fe(OH)2\u200b(s)+2KNO2\u200b(aq) Iron(II) nitrite and potassium hydroxide dissociate into ions.<\/li>\n\n\n\n
Dissociation into Ions:<\/strong>\n
\n
Fe(NO2)2\\text{Fe(NO}_2\\text{)}_2Fe(NO2\u200b)2\u200b dissociates into Fe2+\\text{Fe}^{2+}Fe2+ and 2 NO2\u2212\\text{NO}_2^{-}NO2\u2212\u200b.<\/li>\n\n\n\n
KOH\\text{KOH}KOH dissociates into K+\\text{K}^{+}K+ and OH\u2212\\text{OH}^{-}OH\u2212.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
Net Ionic Equation:<\/strong> After removing spectator ions: Fe2+(aq)+2OH\u2212(aq)\u2192Fe(OH)2(s)\\text{Fe}^{2+}(aq) + 2\\text{OH}^{-}(aq) \\rightarrow \\text{Fe(OH)}_2(s)Fe2+(aq)+2OH\u2212(aq)\u2192Fe(OH)2\u200b(s)\n
\n
Spectator ions:<\/strong> K+\\text{K}^{+}K+ and NO2\u2212\\text{NO}_2^{-}NO2\u2212\u200b, which remain unchanged during the reaction.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n\n\n\n\n
Summary of Spectator Ions:<\/h3>\n\n\n\n
\n
(a)<\/strong> NH4+\\text{NH}_4^{+}NH4+\u200b and SO42\u2212\\text{SO}_4^{2-}SO42\u2212\u200b<\/li>\n\n\n\n
(b)<\/strong> K+\\text{K}^{+}K+ and NO3\u2212\\text{NO}_3^{-}NO3\u2212\u200b<\/li>\n\n\n\n
(c)<\/strong> K+\\text{K}^{+}K+ and NO2\u2212\\text{NO}_2^{-}NO2\u2212\u200b<\/li>\n<\/ul>\n\n\n\n
Spectator ions are ions that exist in the same form on both sides of the chemical equation and do not participate in the reaction, remaining unchanged throughout the process.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"
Write balanced net ionic equations for the reactions that occur in each of the following cases. Identify the spectator ion or ions in each reaction: (a) Cr2(SO4)3(aq) + 3(NH4)2CO3(aq) \u00e2\u2020\u2019 2Cr(CO3)3(s) + 6NH4SO4(aq) Spectator ions: NH4+ and SO4^2- (b) Ba(NO3)2(aq) + K2SO4(aq) \u00e2\u2020\u2019 BaSO4(s) + 2KNO3(aq) Spectator ions: K+ and NO3- (c) Fe(NO2)2(aq) + 2KOH(aq) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-255508","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/255508","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=255508"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/255508\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=255508"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=255508"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=255508"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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<\/figure>\n","protected":false},"excerpt":{"rendered":"