{"id":255512,"date":"2025-07-13T05:43:06","date_gmt":"2025-07-13T05:43:06","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=255512"},"modified":"2025-07-13T05:43:09","modified_gmt":"2025-07-13T05:43:09","slug":"write-the-balanced-net-ionic-equation-for-the-reaction-that-occurs-in-the-following-case","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/13\/write-the-balanced-net-ionic-equation-for-the-reaction-that-occurs-in-the-following-case\/","title":{"rendered":"Write the balanced net ionic equation for the reaction that occurs in the following case"},"content":{"rendered":"\n<p>Write the balanced net ionic equation for the reaction that occurs in the following case: Cr2(SO4)3(aq) + (NH4)2CO3(aq) \u00e2\u2020\u2019 Cr2(SO4)3(aq) + (NH4)2CO3(aq) Express your answer as a balanced net ionic equation. Identify all of the phases in your answer. Identify the spectator ion or ions in this reaction. Express your answer as an ion. If there is more than one answer, separate them by a comma.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The given reaction is:<\/p>\n\n\n\n<p>Cr2(SO4)3(aq)+(NH4)2CO3(aq)\u2192Cr2(SO4)3(aq)+(NH4)2CO3(aq)\\text{Cr}_2(\\text{SO}_4)_3(aq) + (\\text{NH}_4)_2\\text{CO}_3(aq) \\rightarrow \\text{Cr}_2(\\text{SO}_4)_3(aq) + (\\text{NH}_4)_2\\text{CO}_3(aq)Cr2\u200b(SO4\u200b)3\u200b(aq)+(NH4\u200b)2\u200bCO3\u200b(aq)\u2192Cr2\u200b(SO4\u200b)3\u200b(aq)+(NH4\u200b)2\u200bCO3\u200b(aq)<\/p>\n\n\n\n<p>Looking at the reactants and products, we can see that both the chromium sulfate Cr2(SO4)3\\text{Cr}_2(\\text{SO}_4)_3Cr2\u200b(SO4\u200b)3\u200b and ammonium carbonate (NH4)2CO3(\\text{NH}_4)_2\\text{CO}_3(NH4\u200b)2\u200bCO3\u200b are present on both sides of the reaction, with no apparent change. This suggests that no chemical reaction actually occurs between these two compounds. As a result, the reaction is a <strong>no reaction<\/strong> case.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Ionic Form:<\/h3>\n\n\n\n<p>For the ions involved, let\u2019s break down the substances into their respective ions:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Chromium sulfate (Cr2(SO4)3\\text{Cr}_2(\\text{SO}_4)_3Cr2\u200b(SO4\u200b)3\u200b) dissociates in aqueous solution into:<br>Cr3+(aq)+3SO42\u2212(aq)\\text{Cr}^{3+}(aq) + 3\\text{SO}_4^{2-}(aq)Cr3+(aq)+3SO42\u2212\u200b(aq)<\/li>\n\n\n\n<li>Ammonium carbonate (NH4)2CO3(\\text{NH}_4)_2\\text{CO}_3(NH4\u200b)2\u200bCO3\u200b dissociates into:<br>2NH4+(aq)+CO32\u2212(aq)2\\text{NH}_4^+(aq) + \\text{CO}_3^{2-}(aq)2NH4+\u200b(aq)+CO32\u2212\u200b(aq)<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Net Ionic Equation:<\/h3>\n\n\n\n<p>Since there is no change between the reactants and the products (both the reactants remain as ions in the aqueous phase), the net ionic equation would be:<\/p>\n\n\n\n<p>No&nbsp;Reaction\\text{No Reaction}No&nbsp;Reaction<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Spectator Ions:<\/h3>\n\n\n\n<p>The ions that do not change during the reaction are the <strong>spectator ions<\/strong>. In this case, since the whole reaction doesn&#8217;t result in a change of species, all ions present in the aqueous phase are spectator ions.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Spectator ions<\/strong>: Cr3+,SO42\u2212,NH4+,CO32\u2212\\text{Cr}^{3+}, \\text{SO}_4^{2-}, \\text{NH}_4^+, \\text{CO}_3^{2-}Cr3+,SO42\u2212\u200b,NH4+\u200b,CO32\u2212\u200b<\/li>\n<\/ul>\n\n\n\n<p>Thus, this is a <strong>no reaction<\/strong> scenario, and all the ions in solution are spectators.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner6-455.jpeg\" alt=\"\" class=\"wp-image-255513\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write the balanced net ionic equation for the reaction that occurs in the following case: Cr2(SO4)3(aq) + (NH4)2CO3(aq) \u00e2\u2020\u2019 Cr2(SO4)3(aq) + (NH4)2CO3(aq) Express your answer as a balanced net ionic equation. Identify all of the phases in your answer. Identify the spectator ion or ions in this reaction. Express your answer as an ion. If [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-255512","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/255512","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=255512"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/255512\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=255512"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=255512"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=255512"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}